THANK YOU FOR THIS! There are too many ways to misinterpret rules related to apartment calculations! Not sure why you stopped making videos, but I bet of you to make more! We still need schools, hospitals, motors (including multiple on a cct) and transformers!
thank you so much Adrew Payce The apartment load calculation video was really helpful and you made it clear to understand. I would like if possible videos about school calculation and more Stay safe
18:15 why are we using 120/240? If this is Canada this calculation will be 120/208, as the Standata only allows the use of 240v for the single unit feeder, not for any other panels.
This tutorial does not give the TTR of the equipment. The 75 degree column of Table 2 must be used if the equipment has a TTR of 75 degrees C, even if 90 degree conductor is used.
You make a good point, and I've had some difficulty finding any circuit breakers rated to 90 degC, most are marked to 75degC. However the equipment is far downstream of the apartment breaker, in the branch circuit. The line he is presently sizing simply connects the main panel to the apartment subpanel. So, by my (untrained) reading of the code book, I think he can get away with sizing the feeder line by only considering the terminal connections at each end, leaving branch circuit sizing for another day. Please correct me if I'm wrong.
I have a question about a school .. having a 1500m sq of class room area, and 1000m sq of non class room area. No space heating and it says power loads within the school equal 25 kva...supply is 120/208v 3 phase.. whats the minimum service conductor ampacity?.. i don't no what I'm doing wrong?.. please whenever u get a chance I'd appreciate if u could help.. ur apartment calc video is great man . Lots of help for my other questions ... keep it up!
Very informative, thanks a lot. I would like to comment on Objective #2 house panel feeder, the calculated ampacity is 171.7A - Can we use rule 8-106(1) to use conductor size 1/0 instead of 2/0?
Can anyone explain the Suite C example? starting at 14:10? I don't understand why 6000w is added to the load even though the suite does not have an electric range and does not have any loads greater than 1500w. This is covered by 8-202(1)(a)(vii) which reads: vii) any loads provided for, in addition to those outlined in Items i) to vi), at a) 25% of the rating of each load with a rating in excess of 1500 W, if an electric range has been provided for; OR b) 25% of the rating of each load with a rating in excess of 1500 W plus 6000 W, if an electric range has not been provided for; Seems to me the "add 6000w" only applies where there is a load above 1500w, but in this example there aren't any.
Arguably, the code is missing a comma in clause B before "plus 6000". Taken literally, you would need to add 6000W to *each* load over 1500W before multiplying by 25%, which would be pretty crazy.
@@christianwicks3036 The question is, are we calculating: (25% * LoadsOver1500W) + 6000W or 25% * (LoadsOver1500W + 6000W) They intend for it to be the first one, which means they *should* have written: "each load with a rating in excess of 1500 W, plus 6000 W" The comma is important. Without the comma, it implies we should be calculating 25% * (LoadsOver1500W + 6000W), which is wrong.
Thank you for the comment. It is a goal of mine to make videos for all of the occupancy calculation from section 8 of the CEC. I hope to be done by September.
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Thank you so much, we switched to online learning during the covid virus and this allows me to point the students towards this video. Very well done:)
Very very nice sir . Wish you can continue your work to explain more codes and helping us better understanding of Canadian electrical codes.
THANK YOU FOR THIS! There are too many ways to misinterpret rules related to apartment calculations! Not sure why you stopped making videos, but I bet of you to make more!
We still need schools, hospitals, motors (including multiple on a cct) and transformers!
thank you so much Adrew Payce
The apartment load calculation video was really helpful and you made it clear to understand.
I would like if possible videos about school calculation and more
Stay safe
Great video.
18:15 why are we using 120/240? If this is Canada this calculation will be 120/208, as the Standata only allows the use of 240v for the single unit feeder, not for any other panels.
Should continuous load factor to be take into account?
Great tutorial but why did you use the 90 degree colum? Did i miss something?
yeah, whats up with that? :/
@@Aidanjgraham @Joe Dirt I believe this was the rules back in 2017. Termination temp assumptions changed not too long ago
Hello .. is there any templates available for this course, please ... thanks,,,
This tutorial does not give the TTR of the equipment. The 75 degree column of Table 2 must be used if the equipment has a TTR of 75 degrees C, even if 90 degree conductor is used.
You make a good point, and I've had some difficulty finding any circuit breakers rated to 90 degC, most are marked to 75degC. However the equipment is far downstream of the apartment breaker, in the branch circuit. The line he is presently sizing simply connects the main panel to the apartment subpanel. So, by my (untrained) reading of the code book, I think he can get away with sizing the feeder line by only considering the terminal connections at each end, leaving branch circuit sizing for another day. Please correct me if I'm wrong.
@@spelunkerd I believe that you are wrong as where it connects in the main panel is of course to the circuit breaker which is 75 degree rated.
Yes I was questioning this too, 4-006 says if tt is not mentioned then use 60degree column for up to 100amp; 75deg col for over 100amp
Yes, I was wondering why the 90 degree column was used here when the breaker temperature rating isn’t listed.
I have a question about a school .. having a 1500m sq of class room area, and 1000m sq of non class room area. No space heating and it says power loads within the school equal 25 kva...supply is 120/208v 3 phase.. whats the minimum service conductor ampacity?.. i don't no what I'm doing wrong?.. please whenever u get a chance I'd appreciate if u could help.. ur apartment calc video is great man . Lots of help for my other questions ... keep it up!
Very informative, thanks a lot. I would like to comment on Objective #2 house panel feeder, the calculated ampacity is 171.7A - Can we use rule 8-106(1) to use conductor size 1/0 instead of 2/0?
IS ANY NEW VIDEOS SINCE 2017 DO YOU SAMPLE QUESTION FOR RECENT 2023
If it’s 208 do you need root 3?
Can anyone explain the Suite C example? starting at 14:10? I don't understand why 6000w is added to the load even though the suite does not have an electric range and does not have any loads greater than 1500w. This is covered by 8-202(1)(a)(vii) which reads:
vii) any loads provided for, in addition to those outlined in Items i) to vi), at
a) 25% of the rating of each load with a rating in excess of 1500 W, if an electric range has been provided for;
OR
b) 25% of the rating of each load with a rating in excess of 1500 W plus 6000 W, if an electric range has not been provided for;
Seems to me the "add 6000w" only applies where there is a load above 1500w, but in this example there aren't any.
Arguably, the code is missing a comma in clause B before "plus 6000". Taken literally, you would need to add 6000W to *each* load over 1500W before multiplying by 25%, which would be pretty crazy.
@@RickYorgason The way I interpret item b above is:
If you are calculating the redundant parts of this objective, you ARE adding 25% of 0W + 6KW = 6KW
@@christianwicks3036 The question is, are we calculating:
(25% * LoadsOver1500W) + 6000W
or
25% * (LoadsOver1500W + 6000W)
They intend for it to be the first one, which means they *should* have written:
"each load with a rating in excess of 1500 W, plus 6000 W"
The comma is important. Without the comma, it implies we should be calculating 25% * (LoadsOver1500W + 6000W), which is wrong.
thank you bro that good explanations can you make more examples for hospital
Thank you for the comment. It is a goal of mine to make videos for all of the occupancy calculation from section 8 of the CEC. I hope to be done by September.
you didn't mention the house panel must be rated at 100% as you didn't take it to 125% as 8-104(3), for the main service finale count and the feeder.
Very good information thanks
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