Newbie Question, on the X axis why does the graph sheet show negative numbers to the left for each unit? I see -5 for 5 units to the left and -10 the last unit to the left. When you move the vertex to the left you add? And the opposite for the right. You have positive numbers on the graph sheet to the right +5 and +10, yet when you move the vertex to the right you subtract. It’s a bit confusing to me. Thank you for the video!
I think I understand your question... It's all because the general equation for a parabola has x minus the shift to the right. So when we shift to the right it makes the equation look like it is subtracting from x. For example, shifting right 3 units would give us y=(x-3)^2. When we shift to the left, we still subtract but we subtract a negative... which is the same as adding a positive, so it looks like we are adding to x. For example, shifting left 3 units would give us y=(x- -3)^2 which is the same as y=(x+3)^2. Technically, you could keep the double negative in the equation and it wouldn't be mathematically wrong!
Compare the shape of the parabola to the shape of a basic parabola by looking at the pattern of the points. Starting at the vertex of the basic parabola, the next point over is 1 above. The next point over is 3 above. The next point over is 5 above…. etc. If your parabola doesn’t follow that pattern, then there is vertical stretch! Just figure out how far up the next point is and divide it by how far the next point would be up on a basic parabola!
What about the intercept? I have drawn a parabola myself and every value matches the equation thanks to your video but the intercept is different edit: my guess is if i match the intercept then this might no longer be a parabola
It's hard for me to answer this without seeing your work, but I'll try! I'm guessing that you are talking about the y-intercept. Remember that vertex form doesn't easily tell you the value of the y-intercept. To find the y-intercept from the equation, plug zero in for x and compute to get the value of y. If that value does not match the y-intercept on the graph, it is likely due to one of two things... either the graph is not plotted correctly or a computation mistake was made when plugging in zero. I would double check those!
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This explanation makes me understand than my teacher taught me in the classroom
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This is so much simpler than the quadratic formula 😅
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Thanks so much for helping me although I'm not good in mathematics but this video really helped me understand how to form a parabolic equation ❤🙏
most of the time its called a quadratic equation jsyk its the same
Newbie Question, on the X axis why does the graph sheet show negative numbers to the left for each unit? I see -5 for 5 units to the left and -10 the last unit to the left. When you move the vertex to the left you add?
And the opposite for the right. You have positive numbers on the graph sheet to the right +5 and +10, yet when you move the vertex to the right you subtract. It’s a bit confusing to me.
Thank you for the video!
I think I understand your question...
It's all because the general equation for a parabola has x minus the shift to the right. So when we shift to the right it makes the equation look like it is subtracting from x. For example, shifting right 3 units would give us y=(x-3)^2. When we shift to the left, we still subtract but we subtract a negative... which is the same as adding a positive, so it looks like we are adding to x. For example, shifting left 3 units would give us y=(x- -3)^2 which is the same as y=(x+3)^2. Technically, you could keep the double negative in the equation and it wouldn't be mathematically wrong!
how did you find how much the parabola has been stretched or compressed
Compare the shape of the parabola to the shape of a basic parabola by looking at the pattern of the points. Starting at the vertex of the basic parabola, the next point over is 1 above. The next point over is 3 above. The next point over is 5 above…. etc. If your parabola doesn’t follow that pattern, then there is vertical stretch! Just figure out how far up the next point is and divide it by how far the next point would be up on a basic parabola!
@@numberninja this makes sense, thanks
What about the intercept?
I have drawn a parabola myself and every value matches the equation thanks to your video but the intercept is different
edit: my guess is if i match the intercept then this might no longer be a parabola
It's hard for me to answer this without seeing your work, but I'll try! I'm guessing that you are talking about the y-intercept. Remember that vertex form doesn't easily tell you the value of the y-intercept. To find the y-intercept from the equation, plug zero in for x and compute to get the value of y. If that value does not match the y-intercept on the graph, it is likely due to one of two things... either the graph is not plotted correctly or a computation mistake was made when plugging in zero. I would double check those!
@@numberninja yes thank you it helped a lot
Shouldn't the last equation be like y=2(x-3)*-4?
Actually, having x-3 in parentheses will shift the parabola to the right. In order to shift it to the left, we would need x+3 in parentheses!
Thanks🥹. You explained it better than my tutor. She made all the things complicated. Thanks a lot again 😭😭