Construct a hyperbola with the distance between the focus and the directrix as 55mm and eccentricity is 1.5. Also draw the tangent and normal at any point on the curve. Sir this question v ethu ?
Thank you Mr.Bharath kumar.. it's a very easy subject.. stay tuned for practical EG videos for the upcoming units. Kindly check the playlist for all units.
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Construct a hyperbola with the distance between the focus and the directrix as 55mm and eccentricity is 1.5. Also draw the tangent and normal at any point on the curve.
Sir this question v ethu ?
1.5
Means
1.5*10/10= 15/10=3/2.
Kindly watch the playlist it's explained.
Same one for e=0.75
.75*100/100= 75/100= 3/4
Ok sir
Really good teach sir
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Super sir very good explanation
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Thank you sir
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Sir please explan the blue box 2/3 means ellipse only how it become hyperpola
As we know the definition of eccentricity already. (Moving point to Focus , moving point to directrix)
Here it's given from directrix ...
Super sir nice teaching but I feel eg is tough from panimalar engineering college
Thank you Mr.Bharath kumar.. it's a very easy subject.. stay tuned for practical EG videos for the upcoming units. Kindly check the playlist for all units.
Thank you sir
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Yes sir I already shared for my friends
Super sir I am learning it.... Thanks sir👍
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Sir in 1:12 please tell me the blue box explanation. How to find the eccentricity why the value is taken as 2/3 to 3/2
Check the Definition of eccentricity.
If the question is definitely in reverse manner that is 1/e. 1/(2/3) then it becomes 3/2
sir how to point 1,2,3 points what mm
It depends upon number of lines you want, focus distance.
Preferably 1cm gap between them.. l
Sir you are from which College Sir ?
Sjce
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