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Thank you, Mr. Scorcerer (lol). Greetings from Guatemala!
Him: "I hope this is useful for someone in the world"Me *in Australia*: "THANK YOUUU"
awesome!!!!!!
Thank you so much for that, oh wise One! That really did help out & I appreciate how succinct & down-to-earth your explanation was, my Friend! Cheers!
Very helpful, and clearly explained. Thank you so much!
you are welcome!
What a legend. You sir deserve a religion dedicated to your teachings. Mathematics is more of a cult.
What
Thank you so much for this clear explanation!
you are welcome!!
Are the x vector and y vectors always the same? If not, how did you get them?
Could the y vector be any scalar of the x vector?
Amazing Video sir, Great work !!
Thank you!!
Hmm, so given that S is instead the function x^2=y, this wouldn't be closed under addition due to the two resulting vector additions not being multiple of each other?
please help me to show this , "Let A be an m × n matrix and u, v ∈ Rn. Prove that(a) A(u + v) = Au + Av. (b) A(cu) = c(Au), for any scalar c."
Thank you, Mr. Scorcerer (lol). Greetings from Guatemala!
Him: "I hope this is useful for someone in the world"
Me *in Australia*: "THANK YOUUU"
awesome!!!!!!
Thank you so much for that, oh wise One! That really did help out & I appreciate how succinct & down-to-earth your explanation was, my Friend! Cheers!
Very helpful, and clearly explained. Thank you so much!
you are welcome!
What a legend. You sir deserve a religion dedicated to your teachings. Mathematics is more of a cult.
What
Thank you so much for this clear explanation!
you are welcome!!
Are the x vector and y vectors always the same? If not, how did you get them?
Could the y vector be any scalar of the x vector?
Amazing Video sir, Great work !!
Thank you!!
Hmm, so given that S is instead the function x^2=y, this wouldn't be closed under addition due to the two resulting vector additions not being multiple of each other?
please help me to show this , "Let A be an m × n matrix and u, v ∈ Rn. Prove that
(a) A(u + v) = Au + Av. (b) A(cu) = c(Au), for any scalar c."