You literally just pulled a bunch of new things out of the air without explaining their background. Where did h(t) come from and why is it a transfer function? What is a transfer function? You applied this property of LaPlace , L{f(t-a)}=L{f(t)}×e^-as, and didn't explain how you got that or prove it's true. You didn't explain why H(s) = Y(s) / X(s). You also just randomly said the inverse LaPlace of e^(as) is d(t-a)...no explanation of how you know that or where it came from. Most of your videos are really good. This one was horrible.
@@omarilyas6103 Haha yeah I know, but I still like posting puns because it's led to some really cool conversations! Plus I think it drives up engagement on videos, and I try to support the channels that way. Another strategy I've adopted is replying to comments that mention an upcoming test, and asking how it went. I've gotten a few conversations out of that as well.
sir can i say that we are discussing about the impulse response for LTI systems only to discuss about the properties of LTI system in a simpler way.but how does it make it simpler
U(t) is step signal that limit you used in example but you said Impulse response used to get system response. May be it's because of Laplace integration we have to take during convert "t" to "S" domain. point me if i'm incorrect.
I am literally so happy that you exist, there is light at the end of the EE tunnel when I watch your videos.
You literally just pulled a bunch of new things out of the air without explaining their background. Where did h(t) come from and why is it a transfer function? What is a transfer function? You applied this property of LaPlace , L{f(t-a)}=L{f(t)}×e^-as, and didn't explain how you got that or prove it's true. You didn't explain why H(s) = Y(s) / X(s). You also just randomly said the inverse LaPlace of e^(as) is d(t-a)...no explanation of how you know that or where it came from. Most of your videos are really good. This one was horrible.
Laplace? More like “this is the place”…for learning. Thank you for uploading these very informative lectures!
that was terrible bro, but respect for posting it stiwl
@@omarilyas6103 Haha yeah I know, but I still like posting puns because it's led to some really cool conversations! Plus I think it drives up engagement on videos, and I try to support the channels that way. Another strategy I've adopted is replying to comments that mention an upcoming test, and asking how it went. I've gotten a few conversations out of that as well.
you are still alive dud?
@@zeusor Yep
@@PunmasterSTP so how's life tho?
Great work!❤️
Sir, in minute 6:56, you changed the +infinity into 0. This made the integration limits from -infinity to 0!!!
yes, can someone explain/correct this?
@@wulantsabita9843 if you know the definition of unit step then you can understand that
@@charankumar4267 I know it but didn't understand why we changed the limit from +infinity to zero. Can you explain it please?
unit step function is defined for x>=0
I have a doubt why we are multiplying f(t) with u(t) ?
but through this video it is cleared
thanks a lot
i have a doubt here you have taken limit from - infinity to infinity but in maths we studied limit from 0 to infinity for laplace please explain
I am confused too. Laplace of constant number is a/s. I think there is a mistake
sir can i say that we are discussing about the impulse response for LTI systems only to discuss about the properties of LTI system in a simpler way.but how does it make it simpler
Sir please upload lectures on convolution.
Sir can you please provide notes of these videoes?
how did you get X(s)e^-s?
L{f(t-a)}=L{f(t)}×e^-as
@@sayan486 Can you tell me, L{f(t-a)}=L{f(t)}×e^-as it is one of laplace tranform properties or what else?
sorry for my language if it's wrong.
@@inwarsnighter Yes it is a property of Laplace transform
sir when will u teach fourier series and transform?
why is the transform of x(t-1) -> x(s)e^-s ???
put t-1=m and solve , youll get it
sir please upload video on convolution in time domain.
how to calculate laplace of x(t-1)
L{f(t-a)}=L{f(t)}×e^-as
@@sayan486 shouldn't there be -e^-as after where you ended you equation?
a=1
Shifting theorem L{f(x-X)}= F(s).e^-sX
Thank you very much sir.....
cant we define impulse response for LTV variant system
Great !
Can anyone tell me, L{f(t-a)}=L{f(t)}×e^-as it is one of laplace tranform properties or what else?
sorry for my language if it's wrong.
U(t) is step signal that limit you used in example but you said Impulse response used to get system response. May be it's because of Laplace integration we have to take during convert "t" to "S" domain. point me if i'm incorrect.
U told that split systems are time variant
Neso Academy ruclips.net/video/emRV4juY17s/видео.html at 5:40
Neso Academy for split systems do we apply convolution integral
It is not split system. It's TIV system.
y(t)=a(t)x(t-1)+b(t)x(t+1)
a(t)=1 t0
this is split. here we define coefficient a(t) and b(t).
@@alphasatari thanks bro
My first born son shall be named "Sajeed".
okay
sir, integral of 0(zero) is some constant. i think you should modify that.
Thank you !
This is the only reaction from NESO. Don't they like feedback?
If you can't handle criticism, stay away from science!
Can I get written notes of these lectures?