Projection of a Vector onto another Vector
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- Опубликовано: 12 сен 2024
- I work through projecting a vector onto another vector in two setting: 1) When the vectors are described with magnitude and direction. 2) When the vectors are described by their horizontal and vertical components. NOTE: If you check to see if the composite vectors (at the end of this video) are perpendicular, the dot product will not equal zero. I rounded off my work too much when working through the scaler multiple portion of the projection formula.
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You literally brought my grade up from a 82 to a 95. Thank you!!!
+Kimo Thomas you're welcome!
CONGRATS...I'd say we did that together...BAM!!!
I am glad you are finding my videos so helpful:) I do plan on making more videos. I having too much fun making them to stop!
I've watched your video about 20 times now. It's really very potent, and good.
BAM!!!...hope you had a comfortable seat and plenty of popcorn:)
V1 and V2 are the component vectors of V so V1+V2=V. I am showing that by drawing V1 and V2 head to tail.
If I drew a diagram to represent V2 as V-V1 then yes it would be in quadrant 2:). Thank you very much for watching!
i needed to backtrack a bit, you made my understanding very clear. A big thanks.
You're very welcome and thanks for choosing this channel to study with and sub to!
Please keep spreading the word to help us keep growing...BAM!!!
Professor RobBob,,thank you for a monster explanation of Vector Projection in Trigonometry. Once again, Vector Projections has many applications in the real world. Precalculus/Calculus III has a more detail explanation of Vector Projections. Trigonometry is an excellent building blocks for Science and Engineering.
Thanks...just shows you were really paying attention:)) Thanks for watching.
If anyone is interested. What Mr Tarrou is doing here is rotating the x-y axis by 35 degrees. You can see this at the end when he solves for V1 and V2. The point here is that the magnitude of the original vector was unchanged. The significance of that becomes manifest in Physics, (in Relativity specifically) where observers with different frames of reference eventually get the same answer. More info here: ruclips.net/video/Hy7ou5R_vjE/видео.htmlm55s
Pang...I've noticed you have been adding additional comments to many students replys on my videos...thanks for the additional help.
Just curious, are you a Professor?
Math teacher with good hand writing? Whaaaat!? Is the sun rising from West?!
+Evang3lium must be...because it's true...BAM!!!
Thanks for watching and subbing..please tell all your friends to watch and do the same:D
Exactly bro! During my 15 years in school I have never seen a math teacher to have such a good hamdwriting
and THANKS for liking and subscribing!
you always have exactly what I am looking for. I'm really glad i found you!
BAM!!! Me too…and for supporting and subscribing!
I hope this means you're still telling all your friends where to find me too?!
Hi sir!! A real big fan! Thanks for doing what you love, but in public form! I'll be making a few educational videos myself when I have the time! I love learning and im sure I'll love teaching! I look up to you, you do a great job sir!
Are you going to be going over any of these concepts but in three dimensions? I found this video while searching for help on finding the angle between two vectors in three-space.
Thanks!
No plans for a 3 dimensional video:(
I hope you find teaching as rewarding as I do when that time comes!
I do appreciate you choosing my channel to learn from and hope that you will continue to watch, learn and SUBSCRIBE to support free educational channels like mine:)
Great help in my calc class. I tell everybody how good and helpful you are. Many thanks,
+wrednymaz you're welcome and we really appreciate all your support!!!
your videos have been saving me this entire quarter!!! thank you so much!
+eriko9 thanks for taking the time to sub and study with Tarrou's Chalk Talk!
Please keep watching and sharing this channel with everyone...BAM!!!
Thanks for the video, the explanation was awesome. Keep up the good work!
Thanks for liking and subbing...please tell everyone to watch and do the same:D
The last problem you come up with a solution of approximately for component vector … remember vectors can be placed anywhere in a 2-D plane or 3-D space if they have the same direction and magnitude just a helpful hint
At the end of the video you come up with a vector of -39, 80 approximately remember vectors can be shifted anywhere and in 2D or 3D when the vectors have the same magnitude and direction
your a great teacher. thankyou. I hope you keep posting video's, especially in the higher mathmatical world. again thankyou, and here i com calc 1.
It appears to me that V2 should be in Quad 2. Adding negative V1 to V is the same as subtracting positive V1 from V. So, adding negative V1 to V would put the head of V to the tail of negative V1, which would put V2 in Quad 2. Drawing V2 from the tail of V to the head of negative V1. This would match the coordinates of V2, which has a negative X and a positive Y, putting V2 in Quad 2.
ProfRobBob... At approx 14:37 you said you would use Cosine function to find the direction/angle and magnitude of the horiz/vert components for Vsub1, but you could more efficiently use the arctan function with x/y components to find the direction and subtract that direction from Vector V and then use cosine when your trying to get ProjwV like you did in part b?. But i think you meant? You COULD use the arccosine function to find Vector V's angle after having got the magnitude of vector V using only the components, After that then you could use the cosine function to find Vector Vsub1's magnitude like in part B? Then again there are probably a dozen or so other ways due to the way trig works.
Yes, I was referring/summarizing how I initially worked through the problem in the beginning of the lesson:) Thank you for listening to my lesson so carefully and pointing this out.
That was awesome !! As usual Mr. T :)))))))!!
Thank you for your video! Very well explained sir!
Why in the first case (magnitude with direction) result is scalar value. And in second case (vertical and horizontal components) result is a vector? What is true Projection of vectors is a scalar or vector?
The angle of part b is not 45°, it is 35° because 25° + 35° = 60°. 25° + 45° = 70°. The answer Mr, Tarrou will give at the end is not correct.
+gibsonj338 Never mind.
I thought the thing but is it a mistake or I didn't understood it?
+great one oh never mind I understood that now
PLEASE HELP! I have a problem like this except I am not given any angle measures. my question is: An airplane is heading southwest at 600 knots and encounters a wind blowing from the west at 90 knots. Find the planes resultant velocity, and direction?
+Kennedy K. South-West mean your standard position angle is 225 degrees and wind blowing from the west to east has a standard angle of 0. You are also adding vectors, not projecting a vector onto another vector. The lesson you want is here ruclips.net/video/3f8ng0vUkDE/видео.html
I keep getting distracted by that beautiful handwriting
GREAT!!!...I have a few cursive videos if you need a break from math too...BAM!!!
sir can you tell me why V2 = v-v1?
i am understanding finally woooh!!
thanks alot
BAM!!!
I dig the fit
I'm fairly certain that 60 degrees - 25 degrees is 35 degrees...not 45 degrees.
lol I commented before I finished the video hahahah
Thanks for finishing and paying such close attention too...BAM!!!
Me 2. I veered over into the comments to see if anyone spotted it . Thank god xd
note: there is an annotation correction if your using flash:)
Thanks, amazing :)
I just realized I forgot to put vectors on my memory aid *facepalm*
m8 ur a good teacher but sometimes ur addition and subtraction or horrendous loollolol
Proof that teachers make mistakes too...as long as I continue to catch them:)