Well, before we started with the whole moment lesson, we declared every force moving to the right and up as + forces, and forces directed downwards and to the left as - forces. That is why we had to negate F1y and F2y
In ex 1, I gave a scenario, that with moment problems, for x axis, whenever fx moves to the right, it is positive, and to the left, it is negative. So you don't focus on the resultant force but the resolved forces, x and y
Sir why not always split the diagram into its FBD😢..😊 though u aa super...so check on that to aid more understanding to de weak to be scientist. Thank you
To realize this: draw a line parallel to F1x from f1y to F1(900n).then you have the angle 30 facing the line you just constructed. Once the angle is opposite to the side F1x, we use sine
May I know sir why in example number 3, F1x is 900 sin (30°)? Instead of 900 cos (30°) since it's horizontally in x axis
It's rather vertical, you need to tilt the drawing to see.
Dear your explanation way is fantastic
Thanks so so much
please the last question why was the F1y positive when the force is negative 300
Well, before we started with the whole moment lesson, we declared every force moving to the right and up as + forces, and forces directed downwards and to the left as - forces. That is why we had to negate F1y and F2y
I love your videos
Thanks so so much Mona. Please where do you watch me from?
For no 3, u said if the direction is moving into the x axis it x negative but when u were solving for F1 you didn't negate the x value. Why is dat
In ex 1, I gave a scenario, that with moment problems, for x axis, whenever fx moves to the right, it is positive, and to the left, it is negative. So you don't focus on the resultant force but the resolved forces, x and y
Thanks
Sir why not always split the diagram into its FBD😢..😊 though u aa super...so check on that to aid more understanding to de weak to be scientist. Thank you
Okay. Thanks for you input will consider that subsequently
Why did u use sine for F1x
To realize this: draw a line parallel to F1x from f1y to F1(900n).then you have the angle 30 facing the line you just constructed. Once the angle is opposite to the side F1x, we use sine
Thanks
You are welcome
sir do don't we include the reaction forces, or you just ignore them in every situation
your lessons are one of the best
Thanks so much
Yes please, at this point we are not going to consider the reactions, in another topic, we shall consider them and include in our calculation
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Fablios
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