Complete Design Process of a Fixed Bed Catalytic Reactor
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- Опубликовано: 21 дек 2024
- 🚀 Learn how to design a real fixed-bed catalytic reactor for the production of MTBE. Discover the steps required to solve such complex problems and get a step-by-step guide on the key equations and assumptions for designing a fixed bed reactor. 💯
🎉 We apply the use of mass & energy balances, thermodynamics, reactor design, and mechanical design techniques to create a CAD design of our proposed reactor. We will determine factors such as the design equations, column height, diameter and adiabatic temperature rise etc.
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7:41 Since Us is constant, dUs can be set to zero early on, which saves much algebra.
Yes, you are correct, some of the algebraic manipulations could have been done earlier; however, often, I find simplifying steps too quickly can be confusing for students who are just learning, but you are definitely right it could be done earlier! Thank you for watching it's much appreciated!
@@TheChemEngStudent I recently retired from 21 years of higher education physics teaching and research. Although the research is theoretical and is continuing just as before...
My PhD is in EEE, but I now find myself learning Chemical Engineering as part of the diverse skillset required for my new career managing employees who design heat exchangers and reactors.
You videos have been far more helpful than the textbooks!
@@stevenverrall4527 Thank you for your very kind words, it is greatly appreciated! I am truly honoured that a distinguished highly experienced academic is finding value in my work. Full respect for learning Chemical Engineering, one of my specialisms is in Heat Transfer and heat exchanger design and optimisation. If you have any particular topic requests please just let me know and I can create a video.
I definitely agree with Aleena this has been so useful for my project, I wouldn't have passed without this!
Glad it was helpful!
Is the density in the mass balance equation the density of the catalyst bed?
Yes the Rho(b) is the density of the bed.
A really good video tutorial, looking forward to doing the reactor course!
Thank you for your kind words, and looking forward to working with you on this incredible course!
Another great video and well worth spending time to go through this as its super easy to follow!!!!
Thank you for your kind words!
What is that coefficient in the spreedsheet
Which one are you referring to?
This is a life saving video, Thank you so much.
Thank you for your kind words, I am glad this helped!
I totally agree!!
I couldnt agree more
I agree!
So do I use the rate constant of reaction or the equilibrium constant of reaction when subbing in K for -r'A? Im doing CO + 2H2 → CH3OH. Thank you in advance!
I am using a basis of 95% conversion at first
for -r'A this will be the reaction rate constant. If you know it explicitly you simply just substitute it in, if not, you can use the Arrhenius Equation. With reversible reactions you will need to consider the rate of the forward and reverse reactions for the overall rate constant. With you basis if you haven't already I would also reccommed to use 100 kmol for feed that way it simplifies the conversions from %. I hope this helps!
how would this change for a reactor dealing with multiple reactions?
The mechanical design will remain almost the same. The main difference will fall within the kinetics and thermodynamics portion of the design. For example, the reaction Cp will need to account for all the compounds relative to their mole fractions. Similarly, the reaction rate will be dependent upon the limiting reaction step, therefor individual kinetics and thermodynamic details for each reaction will be required. It is also worth noting that if any interactions take place between the multiple reactions, this needs to either be stated as negligible in the assumptions or accounted for in the design. I hope this helps.
@@TheChemEngStudent okay thank you very much
When you calculate the latent heat, how can you find out the F?? please help me
This is the molar flow rate of the feed stream which can be seen in the table four slides prior to that. I hope this helps!
3:40 where did u get this provided data?
This was my own data as part of my project. Most of the data can be found from databases; or are made as assumptions for the initial design. Thanks for watching, I hope this helps!
Awesome tutorial, great schematic too!
Thank you for your kind words! Glad you like it!
Great video But i had a question that for fixed bed reactor we take weight of catalyst as a function of conversion right?
Yes, there are several ways of determining the catalyst weight. It can be dependent upon conversion but not an explicit function of it. Alternatively, you can create a modified material balance whereby the integral is dX/dW where X is conversion and W is the catalyst weight. I hope this was helpful.
@@TheChemEngStudent Got it
Thank you very much
@@TheChemEngStudent Although do you have video how you implemented the equation to produce chart
if so plz send the link
I will be making a video on this topic soon, so I will include a link for you when it is up.
Where do you get these data for calculating the fixed bed reactor?
The data is based on a university project, however there are several variations to the design process as it just depends upon the information that is available to you.
How did you get the velocity value 16.96? cheers
This was found by dividing the volumetric flow rate of the feed stream (tube only) by the cross-sectional area of the tube.
@16:26, I'd suggest to pay attention to your writing, dt should be dt(sub). Otherwise it is confusing.
Thank you for watching and for your feedback, much appreciated!
I think you made a mistake at 3:45 The heat of reaction unit should be kJ/mol
The Heat of Reaction units needs to remain consistent within the numerator and denominator i.e. kJ/kmol, as there would be an inconsistent difference of a factor of 1000. We could express either as J/mol or kJ/kmol. I hope this helps, and thanks for watching!
A really detailed video, this has been so helpful to me Dr
Thank you for your kind words, glad it was helpful!
From where did you taken this case study ?
The case study was developed by myself, as a university project.
@@TheChemEngStudent ohk one more question. how did you calculated mass balance table beacuse link u provided in description is not working?
so helpful video but can you show me the design reaction? thank you so much
😍😍
Thank you for your feedback, I will endeavor to get a tutorial uploaded on this subject.
is this reactor suitable for the production of acetic acid via methanol carbonylation using the Ni/Ac as the catalyst, anyway its a good video
Yes a FBCR would be a suitable option for this particular system, so long as the acetic acid and methanol were in the same state as the design becomes incredibly complex when you have all three states present as the catalyst is usually in a solid form. Thank you for watching!
great content as usual sir
Much appreciated
Such a well explained video sir
Thank you for your kind words!
Sorry to ask to many ques but whats the catalyst used
The most common catalyst used for the production of MTBE is Amberlyst 15
Excellent video very informative and helpful!
Thank you for your kind words!
Sorry for asking so many questions but I hope that I could get answers hihi
First, You say that volumetric flow per tube= Area per tube * the length ( but when I take the calculation, I can not get the same result with you)
Second, in the calculation of latent heat, can you help me show the formula to calculate the flowrate (F)
Thank you so much for your very helpful video
It might be easier to discuss the details via email, please get in touch via info@chemengstudent.com and we can take a further look into the design.
Top quality stuff my friend
Thank you kindly
Concentration changes along the direction of flow.Why direction of flow and 'dz' are perpendicular to each other???
Both variables are modeled parallel as the direction of flow has to be on the same axis. The schematic I drew was just for illustration purposes which was horizontal, however the actual system in the problem statement was vertical. Thank you for watching, I hope this helps!
Great tutorial, very informative
Glad it was helpful!
Void fraction 0.42 & porosity is 0.35.
What is the difference between this two??
In this example the void fraction is the free space within the bed, (sometimes referred to as the bed porosity), however in this example the porosity is the solid particle porosity, as indicated by the subscript "s", I hope this helps, and thank you for watching!
Ok. Overall a very informative video!
@@bapusothombare7368 Thank you sir, very much appreciated!
Super Super video!!!!
Thank you very much!