I started by breaking off a factor of (n+1)(n+2) from the denominator then using the identity: 1 / (n+1)(n+2) = 1/(n+1) - 1/(n+2) But that made things WAAAAY more complicated than they needed to be, haha! The solution was probably in there somewhere, but I felt like I was drifting farther and farther away from it...
So, first attempt at this problem, I tried to modify series expansion of e^x to match the problem. I ended up with incorrect answer. Anyone would like to do that and share the solution?
Very cool!!
Thank you!
Brings me back to my college days! Thanks bud
+Joshua Learn I hope were good old days. :-)
When I see factorials in the sum, I think about e or something like as the answer but the answer is 1😅, it's really a cute answer 😀
I think you actually can use expansion of e^x to evaluate this sum. Though one needs to be very careful.
@@nchoosekmath yes I thought of that method
I started by breaking off a factor of (n+1)(n+2) from the denominator then using the identity:
1 / (n+1)(n+2) = 1/(n+1) - 1/(n+2)
But that made things WAAAAY more complicated than they needed to be, haha! The solution was probably in there somewhere, but I felt like I was drifting farther and farther away from it...
+alkankondo89 Does that actually work? I does complicate things a bit, but if it works, then it works! Hard solution is still a solution!
So, first attempt at this problem, I tried to modify series expansion of e^x to match the problem. I ended up with incorrect answer. Anyone would like to do that and share the solution?
@@peterforeman1707 Awesome! I somehow got e^2 and e term in my answer. This is neat.