DBT JRF PYQs Solution | Genetics | Part 2 | Tips & Tricks | By Virendra Singh |

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  • Опубликовано: 28 янв 2025

Комментарии • 14

  • @kratikavarshney4616
    @kratikavarshney4616 9 месяцев назад

    29:46

  • @ambreenreshi
    @ambreenreshi Год назад

    thank you Sir

  • @prashantshukla4195
    @prashantshukla4195 Год назад

    very helpful session sir🙏🙏🙏🙏

  • @anjaligorai6943
    @anjaligorai6943 Год назад

    Thank you Sir.

  • @tanmoydas7095
    @tanmoydas7095 Год назад +3

    Sir regarding colour blind daughter from colour blind man I think ans should be 3( from mother first miotic division).
    Since it's a daughter colourblind gene carring x chromosome should come from father and that is supposed not to be suppressed by x chromosome she got from her mother ( assuming mother is normal ). In this case mother should have n-1 gamate i.e lacking X chromosome. So that daughter shall be having only one x chromosome that is carring colour blindness. Regarding miotic division doesn't matter 1st or 2nd, both provide n-1 gamate. So option 3.

  • @chhaya2659
    @chhaya2659 Год назад

    🙏

  • @AM-ik7nm
    @AM-ik7nm Год назад +1

    Pedigree wala q to x linked recessive hoga.

    • @vedemy
      @vedemy  Год назад

      Check probability too

  • @Themoon-cu9fr
    @Themoon-cu9fr Год назад

    RQPS

  • @pbiswas2106
    @pbiswas2106 Год назад

    Sir, with due respect sir, i would like to draw your attention on the qst of marker and gene, in that qst the they want to know about the frequency of the population having that two markers only while the desired gene will be absent.....not asking for double crossed over population. There is no such case possible where only two markers will be there without the gene X,,,,therefore, its ans will be zero,option-1.

    • @vedemy
      @vedemy  Год назад

      Okay let me check it

  • @Themoon-cu9fr
    @Themoon-cu9fr Год назад

    1

  • @Themoon-cu9fr
    @Themoon-cu9fr Год назад

    4

  • @Themoon-cu9fr
    @Themoon-cu9fr Год назад

    2