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Hii Guyss, I studied physics from Ashish sir through youtube and solved adv illustrarion book and followed blocked strategy.. So , i'm Deepesh from IITD here. If you have got more than 97 %ile in jee main, then turant advanced ki preparation me lag jao. Meri mains rank 25k thi, and advanced me 4 digit rank. Doing mechanical engineering from IITD. ALL THE BEST FOR JEE ADVANCED ❤❤❤
@physicsgalaxyworld Sir, but in the official answer key of jee advanced 2017 paper 2 no answer was found correct for Q17 Physics which you were solving at 8:42 and the nearest possible option was found to be option 2 and not 1
please correct your video and short about frame dependancy of force force is always independant of reference frames clearly written in kleppner kolenkow also and its the fundamental
@@jeevang750 Physics aur maths me yhi difference H Cause of force is attraction F=gm1m2/r^2 and f=kq1q2/r^2 in sb me mass charge and distance between particles independant of frame hota h that is why force is always frame independant
@@Senthilodadri or u can say that force dependency on frame is based on the concept that ur talking about. Whatever frame u see, the distance between two charges don't change, sooo.
Q 14 Genuine Doubt Why is the point of contact between finger and the ring taken as axis of rotation? It is given in the question that the finger rotates about the center of the smaller circle and the larger ring stays in contact with the finger. So isn't the center of the smaller ring the axis of rotation? (As it is in rest, while finger is not in rest since it is continuously rotating about the center of the smaller ring) Please smn explain
yes you are right iaor is defined as the axis whose all point remain at instantaneous rest in this case the centre of circle is at instantaneous rest therefore the answer would be (K)=1/2(MR^2 + M(R-r)^2)w^2 therefore there was no option satisfying this answer therefore the question was particularly dropped in the first part of paragraph.
@@RohitRaj-n7g tum jaise logo ko sharam ani chahiye/. ek insaan ne itna knowledge hone ke bad bhi students ke liye itna sab kra and tum ese kah rhe ho.
@@shrey---------- mains 1 me yr chem bilcul nhi ati thi . negative me number the .. although other subject thik hai. like mains 1 me maths me 98.25 percentile the. now mains 2 ka result 25 april ko hai. isme jyada expectation hai as me chem krke gaya tha ioc and thodi physical
jee advance qweschion were never wrong they can be done by practical knowledge even if they are theoriticallyy incorrect example that chimney qweschion of jee advance
@@IITDMECHANICAL15 yes bro u are right, that ques was conceptually correct and options were not matching but sir said that one of the options is correct despite JEE ADV gave tht as BONUS
A thin uniform disc of mass 'M' and radius 'R' is rigidly fixed to a vertical wall at point 'O' with a massless hinge. The disc is free to rotate in the vertical plane about the hinge. A small particle of mass 'm' (much smaller than 'M') sticks to the rim of the disc at point 'P' which is diametrically opposite to the hinge (point O). The disc is released from rest in a horizontal position (point P is at the lowest point). Find the angular velocity ω of the disc just before the particle loses contact with the disc (point P reaches the highest point). Ye ai ne create kiya hai problem, valid hai kya ? Agar solution mila toh pls koi reply karo
Yeh wala ek illustration se uthaya gaya hai... So basically at the maximum amplitude, i.e when disc is in horizontal position. Therefore writing the SHM eqn, α = π/2 sin(wt + Φ) As, α = π/2 , at t =0. I.e Φ = π/2 Now when the point of contact loses, ie N =0.. I.e 2mRw² = mgcosα Cosα = 1 -2sin²(α/2)... Then we can find the omega from abv FBD eqn. And to find theta at which this happens, we can diffn the SHM eqn, and then, W = -(π/2)w sin(wt) Insert value of W, i.e √g cosα/2R As we know sin can be negative only in the 3rd or 4th quadrant, i.e using principal value of trigonometry formulae, u can solve the abv sin exp, and find 't', after which put this ' t', in the amplitude eqn to find ur theta... Hope it helps Edit: to find angular freqn, using the TBD eqn 3mgR β = (11MR²/2)α α is angular accn
I am in 12th now. PC/IOC ke liye Alk sir ke lectures (paid tg se) achhe rhenge ya phir akk sir/vj sir ke lectures (apni kaksha vale)??? please suggest seniors. Baaki subjects sort ho gye bas PC/IOC Bach rhe h.
I do not understand this definition. $dQ/dt$ represents the rate of CHANGE of charge flow at an instant even though current is defined as only the charge flow per unit time. Please reply
mana ki maine lucknow city choose kiya hai exam centre ke liye ham kaise jane ki lucknow ki koun sa thau(place) me centre hai koi ko thaha hai kya plz reply how to find
@@IITDMECHANICAL15 should have used "came here with the speed that is obtained when magnetic and electric forces are balanced or equal" My mind went on the Lorentz equation
Can anyone pls explain why Normal is in horizontal direction and friction is upwards? Should it be opposite? Like normal in vertical and friction in horizontal?
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Watch to understand about JEE(Adv) Paper Design and Revision Series - ruclips.net/user/liveJcDZm9qWnD4
Follow Block Strategy for JEE Advanced 2024 for your best score in advanced - ruclips.net/video/N4ViED6p0FU/видео.html
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JEE Advanced Preparation strategy videos -
Magnetic field - ruclips.net/video/7TBMnahL6LQ/видео.html
Dual Nature of Light - ruclips.net/video/Mj6CYMpb2iw/видео.html
Current Electricity - ruclips.net/video/Qg8v9R2HTPs/видео.html
Thermal Fluid - ruclips.net/video/1Ovm2NUulb8/видео.html
Hii Guyss, I studied physics from Ashish sir through youtube and solved adv illustrarion book and followed blocked strategy..
So , i'm Deepesh from IITD here.
If you have got more than 97 %ile in jee main, then turant advanced ki preparation me lag jao.
Meri mains rank 25k thi, and advanced me 4 digit rank. Doing mechanical engineering from IITD.
ALL THE BEST FOR JEE ADVANCED ❤❤❤
Bhaiya please apna phone number de dijiye same aapke jaisi condition h aur adv. Ko 1 month bcha h boht jruri guidance chahiye please bhaiya 🙏
9k rank pe IITD mech kese?
@@PURVA_PATEL637peel ke padho bus
@@studywithme-qm3qy bhai usne 4 digit rank boli h 9k rank nhi
@@studywithme-qm3qy brooo! 2156
@physicsgalaxyworld Sir, but in the official answer key of jee advanced 2017 paper 2 no answer was found correct for Q17 Physics which you were solving at 8:42 and the nearest possible option was found to be option 2 and not 1
I think sir made assumption that r
@@FlowState-nr8fr yes but even if was given we would choose the most precise answer which is option 2
Much needed Sir. Thank you so much
Ram ram sare competitors ko.✋
Ram Ram🫂
Bismillah -e- rehman o raheem
Ram Ram bhai ^^ 🙏
Aashirwad
Ram ram bhai❤
THANK YOU SO MUCH SIR FOR YOUR HELP AND SUPPORT PLEASE GIVE YOUR BLESSINGS SIR❤️❤️🙏🙏
please correct your video and short about frame dependancy of force force is always independant of reference frames clearly written in kleppner kolenkow also and its the fundamental
Bhai aap Oly maths chhorke yeh sbh me kbh aaye
Isn't it that all vector unit are dependent on frame of reference
@@jeevang750 Physics aur maths me yhi difference H Cause of force is attraction F=gm1m2/r^2 and f=kq1q2/r^2 in sb me mass charge and distance between particles independant of frame hota h that is why force is always frame independant
@@Senthilodadri or u can say that force dependency on frame is based on the concept that ur talking about. Whatever frame u see, the distance between two charges don't change, sooo.
Force is always frame independent, isme itna jyada kya hai... Only when frame is accerlated pseudo force lagta hai
Thank you sir. Mai advance ka question solve karte huye sath sath hi important details likhta hu
Bhai solve hote hai saare ? Kuch tips hai kya Bhai physics ke liye ?
Easy
Q 14 Genuine Doubt
Why is the point of contact between finger and the ring taken as axis of rotation?
It is given in the question that the finger rotates about the center of the smaller circle and the larger ring stays in contact with the finger.
So isn't the center of the smaller ring the axis of rotation? (As it is in rest, while finger is not in rest since it is continuously rotating about the center of the smaller ring)
Please smn explain
At any instant the rotation occurs about the point of contact which is considered as the IAOR. IAOR lies on the circumference of the smaller ring.
yes you are right
iaor is defined as the axis whose all point remain at instantaneous rest
in this case the centre of circle is at instantaneous rest
therefore the answer would be (K)=1/2(MR^2 + M(R-r)^2)w^2
therefore there was no option satisfying this answer
therefore the question was particularly dropped in the first part of paragraph.
@@thejade3693yes, but we are talking in non inertial frame, here finger is at rest with respect to the the ring, that's why it is used
Thanks sir!
Thank you so much sir...
sir ashirvaad dijiye is bar advance phod du
Sir का आशीर्वाद उसके साथ ही रहता है जिसके बैंक मे पैसा होता है 🥺😭😭
@@RohitRaj-n7g Kitna paisa
@@RohitRaj-n7g tum jaise logo ko sharam ani chahiye/. ek insaan ne itna knowledge hone ke bad bhi students ke liye itna sab kra and tum ese kah rhe ho.
@@prathammathuraare bhai tumhara mains,nijal gaya Kya Just asking
@@shrey---------- mains 1 me yr chem bilcul nhi ati thi . negative me number the .. although other subject thik hai. like mains 1 me maths me 98.25 percentile the. now mains 2 ka result 25 april ko hai. isme jyada expectation hai as me chem krke gaya tha ioc and thodi physical
sir you are giving awsome advices
Sr thank you want advance booster for chem and math
🎉
THANK YOU SIR
Sir.. For the first question you got answer as option (A).. Please Can you explain why was this question made BONUS in Jee advanced 2017???
It was bonus?
@@jeeboi347 Yes.. check Jee advanced official paper
Sir sab kuch telegram par kyu dalte ho? Niche hi yt pe google drive ki link dedo na plz... sab log telegram thodi use karte hai...
for money 💰
Sir i will secured under 4000 in jee advanced
*secure
Bhai mene 18k sochi thi or 9k aa gyi, teri 2k aane ke chances hain..all the best. Prepare hard🤟
@@Deepesh.Lodhi_IIT-D lodhi bhai iit d me konsi branch milli
@@yashjain694 mechanical
Sir i’m facing issues in the video in the pyq talks course. The voice is not audible at all. Kindly see to this please. I’ve mailed you before.
Sir ita request to complete onion physics of remaining chapters for 25 aspirants
Sir but that Kinetic Energy ques was WRONG and it was given as BONUS. So how it can be option1.
Plz anyone explain.
jee advance qweschion were never wrong they can be done by practical knowledge even if they are theoriticallyy incorrect example that chimney qweschion of jee advance
@@IITDMECHANICAL15 yes bro u are right, that ques was conceptually correct and options were not matching but sir said that one of the options is correct despite JEE ADV gave tht as BONUS
@@yashjeeadv24 yes we should be ready for such que which can ruin our time.
Can smn explain my doubt
Sir paragraph me Jo ask Kiya hai usse hi 25% problem solved ho Gaya
PLEASE CAN SOMEONE TELL when to use instantaneous axis of rotation
How much you guys getting in mocks ?
Also tell which mock ?
@@unknownDK9957wow its nice
Revision lecture se kre ya apne banaye hue notes se kre mocks ke pehle
combined both paper ? and in score test?@@unknownDK9957
133 advanced 2023
@@unknownDK9957 Ha bhai zara apne rank batana
A thin uniform disc of mass 'M' and radius 'R' is rigidly fixed to a vertical wall at point 'O' with a massless hinge. The disc is free to rotate in the vertical plane about the hinge. A small particle of mass 'm' (much smaller than 'M') sticks to the rim of the disc at point 'P' which is diametrically opposite to the hinge (point O). The disc is released from rest in a horizontal position (point P is at the lowest point).
Find the angular velocity ω of the disc just before the particle loses contact with the disc (point P reaches the highest point).
Ye ai ne create kiya hai problem, valid hai kya ? Agar solution mila toh pls koi reply karo
Yeh wala ek illustration se uthaya gaya hai... So basically at the maximum amplitude, i.e when disc is in horizontal position.
Therefore writing the SHM eqn,
α = π/2 sin(wt + Φ)
As, α = π/2 , at t =0.
I.e Φ = π/2
Now when the point of contact loses, ie N =0.. I.e 2mRw² = mgcosα
Cosα = 1 -2sin²(α/2)...
Then we can find the omega from abv FBD eqn.
And to find theta at which this happens, we can diffn the SHM eqn, and then,
W = -(π/2)w sin(wt)
Insert value of W, i.e √g cosα/2R
As we know sin can be negative only in the 3rd or 4th quadrant, i.e using principal value of trigonometry formulae, u can solve the abv sin exp, and find 't', after which put this ' t', in the amplitude eqn to find ur theta...
Hope it helps
Edit: to find angular freqn, using the TBD eqn
3mgR β = (11MR²/2)α
α is angular accn
I am in 12th now. PC/IOC ke liye Alk sir ke lectures (paid tg se) achhe rhenge ya phir akk sir/vj sir ke lectures (apni kaksha vale)???
please suggest seniors.
Baaki subjects sort ho gye bas PC/IOC Bach rhe h.
Akk sir bro
Akk sir ka mujhe idea nahi hai but alk sir se main khud padha hun and I can say you can go for it
@@aryankumargwal1950 ok bro, thanks
I do not understand this definition. $dQ/dt$ represents the rate of CHANGE of charge flow at an instant even though current is defined as only the charge flow per unit time.
Please reply
Guys has anyone enrolled in PYQ talks ? How is it? Can you tell if it is worth it?
Nothing is permanent except "My Dear Students"
Sir 2025 aspirants ke liye bhi video layie plz sir
good afternoon sir
sir is your last year 120 concepts video is useful for neet 2024 also??
pls reply sir
Sir 2025 aspirants ke liye bhi video layie plz❤❤
Sir mocks m marks kam aa rahe hai 🥺🥺
Krishn ji ap apna km kr chuke hai ab ap mjhe itne skti de ki mai krm nibaah Pau 🙂
wish you all the best !
Sir but this questions first part was bonus due to the incorrect options given by IIT....
Sir please make video for class 11 (jee 2027)
Sir, please also explain problem solving skill of jee advanced
mathematics
Sir apki website and app Kam nahi kar Rahi please help
Sir aap apni physicsgalaxy book ke soln bhi elaborated form me daliye
Sir pls make videos on 2025 jee aspirants 😢😢😢
This question is famous as sudarshan chakra question
Sir should we do the pyqs or illustrations first ?
Illustrations
Illustrations + pyq+dpyq
Namoh budhay ji 😎💯
Sir, Pyq talks is not available on Web version of PG ,then what can I do?
yeahh i was also thinking about this. shayad mobile se hi dekhna padega.
@@prathammathura Toh jiske pas phone nahi hai woh kya kare?
Sir jee mains ka decent score mtlb kitni %ile according to you
99+
Sir said in earlier videos above 150+ marks
mana ki maine lucknow city choose kiya hai exam centre ke liye ham kaise jane ki lucknow ki koun sa thau(place) me centre hai koi ko thaha hai kya plz reply how to find
Sir i will work very hard for my selection. Thank you
came here by balancing the electrical and magnetic force on myself { only adv students can understand }
Adv student, but wth does that even mean lmaoo
The question isn't even related to electricity or magnetism lol
@@jeeboi347 bhai magntic aur electric force jab ksi particle pe balance hojate hai tab wo speed of light gain krta hai
@@IITDMECHANICAL15 should have used "came here with the speed that is obtained when magnetic and electric forces are balanced or equal"
My mind went on the Lorentz equation
Sir please neet 2024 important topics ka video upload kariye ❤❤🙏🙏
Respected ashish arora sir neet is just around the corner please give some beneficial tips for it also ❤
Sir neet ke liye bhi video plzz
JAI SHREE RAM 🙏🙏🙏🙏
sir i got 99 percentile in jee mains can i still get a rank under 2k in advance?
No it's too late. U can't 😂
Drop lele bhai 😢
Bro just wants validation
No jee advanced is not joke there is a reason why people start preparing from 8th
ABE teri capablity pe depend krta h ye 91 percentile wala bhi 3k rank le aate h aur 99 wale bi 25k leaate h validation kyu mang rhe ho khud ko dekho
Hi score?
Sir pyq talks start hogyi h?
It’s on physics galaxy app. Paid course hai
ONCE UPON A TIME THIS CHANNEL WAS ALSO DEALING WITH NEET RELATED PROBLEMS 😢
Yeh iit ke liye hai suru se
Bich me thori der ke liye Dali thi baas neet ke liye videos
sir neet walo ko toh bhul hi gye aap🥲
Can anyone pls explain why Normal is in horizontal direction and friction is upwards? Should it be opposite? Like normal in vertical and friction in horizontal?
Maturity is when you realise that your and topper's knowledge is very different so you can't have same mindset as of topper 🙂
😅
Maturity is that u r not mature. Till now......👽
maturity is when you realise these type of thoughts makes u are always gonna be underrated
Shi kha bhai. Wo bohot pehle se padh rhe hote hain. Jab wo taiyaari kr rhe hote hain tab hume in exams ka malum bhi nhi hota.
@@Aditya-Bhardwajjab ham preparation start karte tab wo irodov, pathfinder,black book kar rhe hote
Radhe Radhe sabhi logo jo mujhe takkar degye 26 may wale din ❤
When will 4th edition of Physics Galaxy Books for JEE Main & Advanced release ?
Last 🫠😢
W pfp,brotha👍
Love u
15 minutes of unadulterated nonsense! Hats off 😅
IITian PRANAV NARHARI BAVIKAR IITK Aerospace engineering
Jai shree ram ❤
Ram ram ji
8s1 less than 100 like and 100-150 comment 😅
1st
Bs kro Esaral hr jgh mt ghusne ki koshish