Classical Mechanics Lecture 4A | Degrees of Freedom with Examples | MSc Physics Lectures
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- Опубликовано: 18 сен 2024
- Classical Mechanics Lecture 4A | Degrees of Freedom with Examples - MSc Physics Lectures
A tiny portion of the following animation videos is used in this lecture.
(a) Wheel rolling animation: • Understanding Rolling ...
(b) Piston movement: • Adjustable cushioning ...
(b) Screw animation: • Three-Link Screw-Type ...
It is interesting to learn than a planar car wheel has 1 degree of freedom. In reality a car wheel rotates about itss axis and also about an axis which is perpendicular to floor and passing thru center of wheel. The second rotation is less than half circle. So in this case can we say degrees of freedom is 1.4??
Degrees of freedom (DoF) is an integer, meaning that fractional values are not meaningful. In our wheel example, one DoF is the "distance travelled" and no more information required to be specified.
Well explained sir.
Thank you so much
thank you professor!
You are welcome!
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Scissor explanation is quite good sir.
Thank you
at 2:18, it should be (3-k)n for degree of freedom
In three-dimensional space, we have a total of 3n degrees of freedom. Further if there are k number of constraints, then, the final degrees of freedom is (3n - k). First evaluate 3n. Then reduce it by k.
Very nice explanation 😀😀😀.illustrations superb.
Thank u sir❤
Thankyou Sir
❤❤ really wonderful class sir❤
thanku sir
Sir please upload small oscillation
Sir, In the example with the wheel
If the wheel is not incontact with the road .Now I can say it has 6 degrees of freedom.
Thank you so much sir
Tnxs sir
Thank you sir!
Sir...ur lectures r not on sequence...few lectures r missing in between...
Yes!
If I drop an object and it falls vertically downwards, what is the no. of DOF?
one
Yes, one degree of freedom.
@@ProfSivakumarRajagopalan But Prof, we know that the motion is vertically downwards once we solved the equations of motion and apply initial conditions, na? For different initial conditions, the path could be parabolic or any other conic section?
Joel Jeevan 1st msc physics
the kinematic links act as constraints, so they should reduce the DOF. Towards the end of the lecture, Sir says more links = more DOF,, can someone please clarify this for me ?
You got the concept correctly. Great. More links make us do additional thinking. That is more number of DOF minus a lot of constraints.
Can you give us the link of the problems about the course please professor ?
Sir what is linear stability theor?
Thank you for these great lectures Sir,,
as we know, generally for a Rigid body,
DOF = 6 - no. of constraints,
how do we understand this calculation for the wheel and bolt example, ?
for eg, in the wheel's case, I could understand that the wheel had 1 DOF as rotation and translation were synonymous here, but what were the constraints that reduced it's DOF from 6 to 1 ? for one, I know about the contact between the wheel and surface. But I am still confused. COuld you please explain.
Translational movement is an consequence. No force is applied for translational displacement
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