Math Olympiad | A Nice Algebra Problem | A Nice Math Problem

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  • Опубликовано: 12 сен 2024
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    Find the value of x and y?
    How to solve x^2 - y^2 = 2023
    In this video, we'll show you How to Solve Math Olympiad Question A Nice Math Equation x^2 - y^2 = 2023 in a clear , fast and easy way. Whether you are a student learning basics or a professtional looking to improve your skills, this video is for you. By the end of this video, you'll have a solid understanding of how to solve math olympiad exponential equations and be able to apply these skills to a variety of problems.
    #matholympiad #mathtricks #maths

Комментарии • 12

  • @SrisailamNavuluri
    @SrisailamNavuluri 19 дней назад +1

    2023=7×289=7^1×17^2
    Ther are 6 factors.we get 3 pairs of solutions.

    • @SALogics
      @SALogics  19 дней назад

      Yes, you are right! ❤

  • @YAWTon
    @YAWTon 19 дней назад +2

    Did you forget to say that you are looking for integer solutions? Your solution is incomplete, and it is a solution by guessing. How did you guess that x and y are multiples of 17? I would give you 5 out of 20 for your solution and presentation.

    • @SALogics
      @SALogics  17 дней назад

      This solution is for smallest positive integer solutiions ❤

    • @glasssmirror2314
      @glasssmirror2314 13 дней назад +1

      I wanted to ask same question.

    • @glasssmirror2314
      @glasssmirror2314 13 дней назад +1

      Pls explain more about Smallest P Int....Sol.....

  • @paulkolodner2445
    @paulkolodner2445 19 дней назад

    2023 = 1012^2 - 1011^2 = 148^2 - 141^2 = 68^2 - 51^2 - ie, one solution for each of the odd prime factors of 2023.

    • @SALogics
      @SALogics  17 дней назад

      Yes, you are right! ❤

  • @erwinkurniadi1850
    @erwinkurniadi1850 20 дней назад

    What about x=148 and y = 141, is that the wrong answer?

    • @Kevin-vn7mg
      @Kevin-vn7mg 20 дней назад +2

      It is. The complete set is (x,y) => (1012, 1011), (148, 141), (68,51)
      (x+y)(x-y) = 2023*1
      (x+y)(x-y) = 289*7
      (x+y)(x-y) = 119*17

    • @sundaramsadagopan7795
      @sundaramsadagopan7795 20 дней назад

      x^2--y^2 = 2023, (x+y) (x-y)=(289)(7), x+y=289, x-y=7..........x=148, y=141.(21904--19881= 2023)

    • @SALogics
      @SALogics  19 дней назад

      That's correct! ❤