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very clear and excellent lecturing so far I have seen, Sir Prof. Dhang explanations have been so explicit in undersatanding the concept of RCC Design
Thanks a lot sir.Your all lectures are awesome. It helped me a lot.May God bless you many more.
At 6:19 minimum eccentricity = 20mm (max(20, 17)). emin > 15 mm (0.05*300). I think eccentricity check is not applied properly here.
One of best lecture .....to Resolve my Quaries.... Thank you sirrrr
NICE INFORMATIVE LEACTURE VIDEO...
Why did you subtract area of steel from Area of concrete while computing Area of steel (9:16) from Pu (ultimate axial load) .... when in previous examples and theory, you said we ignore subtracting that quantity!
I think he did the mistake in the previous examples. We need to subtract it
What if span is not equal
Thank you so much sir
how can l get Mx and My ıf l have Pu?
beam moment plus eccentricity (additional moment)
👍
thank you.
turn down the volume....simple solution.
Gg
very clear and excellent lecturing so far I have seen, Sir Prof. Dhang explanations have been so explicit in undersatanding the concept of RCC Design
Thanks a lot sir.Your all lectures are awesome. It helped me a lot.May God bless you many more.
At 6:19 minimum eccentricity = 20mm (max(20, 17)). emin > 15 mm (0.05*300). I think eccentricity check is not applied properly here.
One of best lecture .....to Resolve my Quaries.... Thank you sirrrr
NICE INFORMATIVE LEACTURE VIDEO...
Why did you subtract area of steel from Area of concrete while computing Area of steel (9:16) from Pu (ultimate axial load) .... when in previous examples and theory, you said we ignore subtracting that quantity!
I think he did the mistake in the previous examples. We need to subtract it
What if span is not equal
Thank you so much sir
how can l get Mx and My ıf l have Pu?
beam moment plus eccentricity (additional moment)
👍
thank you.
turn down the volume....simple solution.
Gg