positive y moments are in the direction your fingers curl when you point your thumb in the +y direction. so the 600*12 rotates in the opposite direction as your fingers, therefore it is negative.
You are the best, so funny and just such a great teacher. 3D combined loading was lost on me until I discovered this! All the other videos are amazing too!
@Panth Naik as long as you also calculate the internal moments and torque at the cut, you will get the same result. It is not really superposition that is being applied, rather the six equilibrium equations.
Don't know if you still read the comments but thank you so much!! Solid mechanics was a total nightmare for me until i watched your playlist of videos and i feel just a bit more confident about doing my exam next friday! Thank you and keep up the great work! :D
At 6:40, why is the 600*12 being subtracted, while at 5:45, a positive moment is induced when 600*8 is added to Mx? Thanks in advance - it's a very helpful video.
You sound like you're stoned in this video. But I don't care because you helped me a lot not to mention your sense of humor that my professor doesn't have.
Thank you for the great video sir, how do we know when to use the correct shear vs stress equations. For example, for Ny, how do we know that normal stress is N/A and not Mx/y. Same goes for the shear equations. Also, when do we apply both equation for both stress n strain. Really struggling with this concept
@@lwthorn1977 yeah probably otherwise the solution has gone wrong .. anyways , most times shear stress can be omitted due to their small contribution to the result and the percentage of this fault comes to a 2 or 3 percent ... actually most times i use tresca or vonmises criterion and it doesnt bother me somuch
You are the best teacher I have ever listened :)) I passsed my strength of materials 1 course thanks to u !! And Hope I will pass strength of materials 2 course, too :)) I just wanted to say thank you so much,. And u should go on to make some jokes during the video.. Coz It makes me laugh :))
Quick question , at the beginning of the problems why did you not superposition the applied forces to the cross section at b. Hence giving vx=-500,vz=600, and ny=800, then going from there. Thats what my textbook does, they just take the applied force and put it onto the cross section of where we are looking at. Does your method and my method give the same result in the end?
Will the sign of the compressive or tensile force not be different at the cross section giving you a different normal force number for that cross section?
Your lectures are excellent chief. I thought 1st moment of area, Q, for V_x should be all area below pt. B or above pt. B as mentioned on the earlier 2D example, so shouldn't be the whole circle instead of half?
How do you know when it was shear stress and when it was normal stress? I know normal has to on with it being perpendicular to the force and shear has to be parallel. So why is Mx in normal stress and not shear? and same with the rest. THank you
911Teresa911 bending moments have a tension and compression force couple which are normal to the surface and cause a normal stress, they also cause elongation and contraction which are associated with normal stress. Twisting moment or torque cause angle changes which are associated to shear stress.
+deepak np remember that shear is across a surface, normal is into a surface. So if you look at the force of y in this example, it goes into the surface therefor it is normal stress. If you look at force of x, it goes sideways, therefor it will cause shearing.
Hi there, can you evaluate more on the Moment equilibrium equations as I cant quite get my head around that. Why is Moment about x only caused by the 600 lb? and for moments about y and z respectively
+structurefree Thanks for the clarification.Your videos are super useful,I am currently revising this subject using your channel,its a big help,keep being AWESOME.....chika chika..haha
For part 3, when you find the normal force due to Mx, how did you know it was a normal force and that it compresses point b. I just cant quite visualize this piece. Thank you
Visualize it as a beam bending. The moment about the x-axis is due to the 600lb force. Its causing compression at the top (where point b is) and tension at the bottom. In simple words visualize this as a smiley face. Top in compression and bottom in tension. Hope this helps.
@@bzq3386 Thank you! This helped me realize to look at it in its entirety, not just the cross-section. Because if you think about the rotation the 600 lb force will cause, it will go through the plane of the cross-section. Thank you again
Wait I think I understand now. My signs are basically opposite then yours , but they should give me the same answer. While my compressive normal force is positive, yours is negative, and while my moments are positive or negative , yours are the opposite sign. But they should give me the same answer, is that correct?
I cover some of the strain/stress concepts, torsion, and beam deflections in my mechanics of materials playlist. Unfortunately, I have yet to add the other topics...I'll add them to my to do list.
I'm more interested in drawing an infinitesimal element cube with arrows for axial, bending, transverse shear, and torsional shear. A problem that is more conceptual, drawing at different cross sections at different points (ex. top of cross section, side of cross section, etc.)
Which one off your videos do you recommend i apply for the lift arm of a Skid steer loader connected to the chasis at one end and connected by pivot to a bucket with load at the other end
thank you for the amazing video, should not the shear stress on point B( on the surface) be zeo because shear is caused by forces between layers! thank you!
Hi, Actually what to do when the cross section is of Hexagon and not circular. I have an assignment of allen wrench in which we need to follow combined stress method to check the convergence between hypermesh and Mechanics of material results. I can send the pic of problem if i get an email id if you provide. or anyone who can help with the topic
Shouldn't all of your signs be flipped if you are considering the stresses at B resulting from the applied forces? i.e. You are finding the internal forces and moments that balance out these forces, but you're considering the left side of the cut when your proper sign convention would result from considering the right side of the cut. Gnomesayin?
+Fricks and Fracks No, when you write out your equilibrium equations you will find this. In this example, when finding Vx, you would write out the equilibrium equation as follow: Fy = 0 = Vx - 500 => Vx = 500. This Vx is headed the opposite direction, and therefor balancing like you say. There is no need to switch the signs once you've found your forces.
is that possible to add(combine) two mechanical force(torque) Ex:- if i have two 1.5v batterys >> - if i connect in series the voltage increase OR - if i connect in parallel current rating is increase same as in mechanically either rpm increase or torque increase i dont know is that good question or silly one........hahahah but please replay me if you have any suggestion
Ive spent a lot of time on trying to understand internal loadings, and I want to know why you ignore equilibrium sometimes. Why do you have a negative normal force? I feel like that isn't possible. I also feel like a negative moment reaction is impossible. Can someone clarify?
It is not impossible. It is negative because it has to counteract the other forces in the positive direction to reach equilibrium. I dont understand how to take moments in 3D any suggestions?
+Shawn Ng No, the torsion happens along the normal axis. Basically, if you draw out your cuts like he did the torsion should make a clockwise/counterclockwise arrow. In this example, that only happens along the y-axis and not the z- or x-axis.
I did not understand why you take only one moment due to forces for x and y-axis. And 2 moments for the z-axis. since we have 3 forces in 3 directions that imply each axis should also have 2 moments due to forces
Sir you are brilliant, I feel sorry for myself because I didn’t discover your channel earlier, 7 years and still more than useful 😍
So nice of you
I feel like Yoda - "Life long you must learn. Structurefree your teacher is."
structurefree :)
positive y moments are in the direction your fingers curl when you point your thumb in the +y direction. so the 600*12 rotates in the opposite direction as your fingers, therefore it is negative.
You are just too good man. Keep it up! Been struggling with it for 2 days now, watched the first 8 minutes and Im good to go
Thank you so much I have a statics and mechanics final tomorrow morning and you really cleared the air on combined loading! Very clear video
You are the best, so funny and just such a great teacher. 3D combined loading was lost on me until I discovered this! All the other videos are amazing too!
Istanbul Technical University Naval Arch. Students want to say thank you for your lessons; we learned mechanics thanks to you.
My bro God bless you. Passed mechanics of materials because of this channel💪💪💪
"It's normal. Just like me!" Hahaha. That part got me laughing. thanks for the extreme help!
@Panth Naik as long as you also calculate the internal moments and torque at the cut, you will get the same result. It is not really superposition that is being applied, rather the six equilibrium equations.
Don't know if you still read the comments but thank you so much!! Solid mechanics was a total nightmare for me until i watched your playlist of videos and i feel just a bit more confident about doing my exam next friday! Thank you and keep up the great work! :D
12:25 Can you please explain why you took this area, wasn't Q above or below
Gkrozr Vx.Qz/Iz so he uses the left or right area but if it was Vz.Qx/Ix he will use the upper or Lower area
Omar Zain Thank you.Appreciated :)
You are amazing...teacher love u...i wanna be ur student forever...so intresting ur lectures are
At 6:40, why is the 600*12 being subtracted, while at 5:45, a positive moment is induced when 600*8 is added to Mx? Thanks in advance - it's a very helpful video.
For anybody reading this. He messed up sign convention here. Use Right Hand Rule
I mean, as long as he sticks with that convention, it's alright.
12:48 what is Q the left shaded half of the circle and not the half circle above Vx?
literal lifesaver. thank you so much
You sound like you're stoned in this video. But I don't care because you helped me a lot not to mention your sense of humor that my professor doesn't have.
12:59 why is that half of the circle??
12:25 explain why you took this area, you said before Q is above or below
i hate it when this happens
Can you explain the reason why you chose those interanl loads in the begining?
Thanks man. Your tutorial saved my life
+Mohamad Hasrul Reza Mohd HIsham ajar aq la pulak..hahaha
senang je lah. aku dah ajaq wan
Thank you for the great video sir, how do we know when to use the correct shear vs stress equations. For example, for Ny, how do we know that normal stress is N/A and not Mx/y. Same goes for the shear equations. Also, when do we apply both equation for both stress n strain. Really struggling with this concept
how did you compute the moment forces about point z? im not understanding how you know to multiple for that particular axis.
As far as i am concerned , there are no shear stresses at the periphery , the shear stress profile is parabolic.
@@lwthorn1977 yeah probably otherwise the solution has gone wrong .. anyways , most times shear stress can be omitted due to their small contribution to the result and the percentage of this fault comes to a 2 or 3 percent ... actually most times i use tresca or vonmises criterion and it doesnt bother me somuch
Thank you so much for this video,one week before my exam, lifesaver :D
writing my mechanics of materials exam tomorrow,feeling confident thanks to you bro!
it is really helpful.BTW, what software are u using?
i'm glad it helps.
Amazing!!, i finally realize it thanks to you 👍
You are the best teacher I have ever listened :)) I passsed my strength of materials 1 course thanks to u !! And Hope I will pass strength of materials 2 course, too :)) I just wanted to say thank you so much,. And u should go on to make some jokes during the video.. Coz It makes me laugh :))
Thank you for the kind words. I'm actually more flattered that you think I'm funny. Congratulations on all your success!
Gemiden AA la geçmen lazım bu dersi
Quick question , at the beginning of the problems why did you not superposition the applied forces to the cross section at b. Hence giving vx=-500,vz=600, and ny=800, then going from there. Thats what my textbook does, they just take the applied force and put it onto the cross section of where we are looking at. Does your method and my method give the same result in the end?
Will the sign of the compressive or tensile force not be different at the cross section giving you a different normal force number for that cross section?
Dude, you explain so clearly.
Is there no continuation of the video?
Awesome part 1!
Your lectures are excellent chief. I thought 1st moment of area, Q, for V_x should be all area below pt. B or above pt. B as mentioned on the earlier 2D example, so shouldn't be the whole circle instead of half?
It is relative to the direction of the internal shear force you are looking at. Thank you for the kind words! Good luck with school!
How do you know when it was shear stress and when it was normal stress? I know normal has to on with it being perpendicular to the force and shear has to be parallel. So why is Mx in normal stress and not shear? and same with the rest. THank you
911Teresa911 bending moments have a tension and compression force couple which are normal to the surface and cause a normal stress, they also cause elongation and contraction which are associated with normal stress. Twisting moment or torque cause angle changes which are associated to shear stress.
why is it shear stress and not normal stress? can you explain how to distinguish(pick) what type of stress it is
+deepak np remember that shear is across a surface, normal is into a surface. So if you look at the force of y in this example, it goes into the surface therefor it is normal stress. If you look at force of x, it goes sideways, therefor it will cause shearing.
floormatt3 omg ty so much!
You just saved a very frustrated student!
What is the book used? Idk what is the whole question.
Hi there, can you evaluate more on the Moment equilibrium equations as I cant quite get my head around that. Why is Moment about x only caused by the 600 lb? and for moments about y and z respectively
There should be a torque at the cross-section about y axis due to the 600 lb force or am I wrong?
+Rajnish Singh Yes, there is. It is labeled as My in this problem.
+structurefree Thanks for the clarification.Your videos are super useful,I am currently revising this subject using your channel,its a big help,keep being AWESOME.....chika chika..haha
For part 3, when you find the normal force due to Mx, how did you know it was a normal force and that it compresses point b. I just cant quite visualize this piece. Thank you
Visualize it as a beam bending. The moment about the x-axis is due to the 600lb force. Its causing compression at the top (where point b is) and tension at the bottom. In simple words visualize this as a smiley face. Top in compression and bottom in tension. Hope this helps.
@@bzq3386 Thank you! This helped me realize to look at it in its entirety, not just the cross-section. Because if you think about the rotation the 600 lb force will cause, it will go through the plane of the cross-section. Thank you again
@@nicolef4552 Welcome!
Wait I think I understand now. My signs are basically opposite then yours , but they should give me the same answer. While my compressive normal force is positive, yours is negative, and while my moments are positive or negative , yours are the opposite sign. But they should give me the same answer, is that correct?
If you've got normal force in Y direction, wouldn't it be torsion instead of moment about that axis?
Do you have a site or channel with mechanics of aerostructures video lectures. very similar to this
what topics are you looking for? fiber reinforced polymer composite mechanics?
structurefree here are a list of the topics am looking for www.colorado.edu/engineering/CAS/courses.d/Structures.d/
I cover some of the strain/stress concepts, torsion, and beam deflections in my mechanics of materials playlist. Unfortunately, I have yet to add the other topics...I'll add them to my to do list.
Thanks. I ll appreciate that so much
I'm more interested in drawing an infinitesimal element cube with arrows for axial, bending, transverse shear, and torsional shear. A problem that is more conceptual, drawing at different cross sections at different points (ex. top of cross section, side of cross section, etc.)
Good idea!
you say compression, normal or shear but you failed to explain why those points/faces are experiencing such forces.
If you view his other prequel videos, all of that is explained.
Which one off your videos do you recommend i apply for the lift arm of a Skid steer loader connected to the chasis at one end and connected by pivot to a bucket with load at the other end
I love your videos. If I need to look up something and I see it is one of ypur cideos
When you are solving for My, why are you subtracting 600(12)?
how do you calculate the moment equations. can you explain how to do it. i can do it in two -d but i cant wrap my head around how you do it in 3d
wouldnt Vx be 0 at B due to its distribution? max at neutral axis and 0 at edges?
Awesome review prior to my midterm.
Is the formula you use for the shear stress not for other shapes?
Good job keep it up
Thank you so much! but why did you consider only half of the circle to find Q?
i also cant understand that part can you make me understand it
@@aliabbas2138 q is calculated for only one side of the point for which you are calculating the shear which is the shear formula requirment
its torque about y axis not moment right?
You are a life saver, Thank you every much!
thank you for the amazing video, should not the shear stress on point B( on the surface) be zeo because shear is caused by forces between layers! thank you!
Why Vx induce shear stress at B not at A?
Hello, Can anyone please help me in understanding ,How to take moment about any axis?
why Q only take half of the area of circle?
how to identify moment -600(12) or +600(12)?
Hi, Actually what to do when the cross section is of Hexagon and not circular. I have an assignment of allen wrench in which we need to follow combined stress method to check the convergence between hypermesh and Mechanics of material results.
I can send the pic of problem if i get an email id if you provide. or anyone who can help with the topic
Shouldn't all of your signs be flipped if you are considering the stresses at B resulting from the applied forces? i.e. You are finding the internal forces and moments that balance out these forces, but you're considering the left side of the cut when your proper sign convention would result from considering the right side of the cut. Gnomesayin?
+Fricks and Fracks No, when you write out your equilibrium equations you will find this. In this example, when finding Vx, you would write out the equilibrium equation as follow: Fy = 0 = Vx - 500 => Vx = 500. This Vx is headed the opposite direction, and therefor balancing like you say. There is no need to switch the signs once you've found your forces.
is that possible to add(combine) two mechanical force(torque)
Ex:- if i have two 1.5v batterys >>
- if i connect in series the voltage increase
OR
- if i connect in parallel current rating is increase
same as in mechanically
either rpm increase
or torque increase
i dont know is that good question or silly one........hahahah
but please replay me if you have any suggestion
Great teacher ! very helpful videos..
Thank you! You are too kind.
Normal, just like me! haha, make me laugh so loud. Btw, great explanation!
+Adlee Jaafar ha ha ha! just reading it makes me laugh. why is mechanics so much fun!
Omg Adlee. ermm Hi!
structurefree
Why 600lb induces a moment in x directrion?
Ive spent a lot of time on trying to understand internal loadings, and I want to know why you ignore equilibrium sometimes. Why do you have a negative normal force? I feel like that isn't possible. I also feel like a negative moment reaction is impossible. Can someone clarify?
It is not impossible. It is negative because it has to counteract the other forces in the positive direction to reach equilibrium. I dont understand how to take moments in 3D any suggestions?
Isn't the 600 lb producing a Torque?
Why do we only care about the x axis and y axis, as opposed to all 3 (including the z)?
Is there a confusion between moment and torsion?
The way i see it, for the x-axis: 600*8 is the torsion while 600&12 is the moment, please clarify.
+Shawn Ng No, the torsion happens along the normal axis. Basically, if you draw out your cuts like he did the torsion should make a clockwise/counterclockwise arrow. In this example, that only happens along the y-axis and not the z- or x-axis.
Your videos, I physically smile... Comment fail.
Love you man
I did not understand why you take only one moment due to forces for x and y-axis. And 2 moments for the z-axis. since we have 3 forces in 3 directions that imply each axis should also have 2 moments due to forces
OMG...goddamn memories lane. Just graduated...n idk how i survived through all this.
I wish you were my teacher.
how to know whether to put minus or plus sign for moment eq????? pls someone help meeeeeeeeeeee
fantastic material my homies
Part2?
who you know it's shear or normal ?
Thank you very much
Man you are saving my ass.
600 * 12 should be torque not moment??
I like this guy
when finding the moment around the z axis, the 500(8) part should be negative
No, it's positive. Apply the right hand rule along the z-axis.
But it is supposed to be negative once I used the right hand rule along the z-axis
Oops didnt notice the direction of force carefully. Sorry
Last minute life saving
why the witd =2in
Many thanks in advance!!!!!!
This guy is hilarious.
Love u bro u saved me
yes.
Thank you.
Thanks, very helpful
thank you
very helpful
thanks man you saved my ass
i'm still confused to how the positive negative is determined in each moment Mx My Mz
Hahahaha ,, I like how you laugh and thanks for this helpful lecture
Thank you so much!