6:15 In this Case Let initial velocity (u) is 20km/hr=5.55m/s Angle is 30° Gravity(g) is 9.8m/s^2 Range that is horizontal distance covered is, R=u^2xsin2(30°)/g =5.55x5.55x0.866/9.8 =2.72 Matlab thele par se gaadi sirf 2.72 meter aage jake giregi. Height attained by scooty is, H=u^2xsin^2(30°)/2g =5.55x5.55x0.25/19.6 =0.4 meter Matlab scooty Gaadi ko jake thokni chahiye. Time Required is, T=2usin(30°)/g =2x5.55x0.5/9.8 =0.6 seconds Matlab ki scooty ko 0.6 seconds me niche girna chahiye par yaha to scooty is flying for 9 seconds💀💀 (1 like to banata hai) Edit: Nishchay Bhai please ♥️
6:41 Given: - Mass of the object (m) = 350 kg - Initial speed (u) = 20 km/h - Angle of projection (θ) = 30° First, we need to convert the initial speed from km/h to m/s: 1 km/h = 1000 m / 3600 s = 5/18 m/s So, initial speed (u) = 20 km/h * 5/18 = 100/18 m/s ≈ 5.56 m/s Now, we can calculate the horizontal and vertical components of the object's velocity: Horizontal component (ux) = u * cos(θ) Vertical component (uy) = u * sin(θ) ux = 5.56 m/s * cos(30°) ≈ 4.81 m/s uy = 5.56 m/s * sin(30°) ≈ 2.78 m/s Next, we can calculate the time of flight (t) using the vertical motion: The time to reach the highest point (time to peak) is given by: t_peak = uy / g, where g = 9.81 m/s² (acceleration due to gravity) t_peak = 2.78 m/s / 9.81 m/s² ≈ 0.283 s Since the motion is symmetrical, the total time of flight is twice the time to reach the peak: t = 2 * 0.283 s = 0.566 s Finally, we can find the horizontal distance (range) the object will travel: Range = ux * t Range = 4.81 m/s * 0.566 s ≈ 2.72 meters Therefore, the object will land approximately 2.72 meters away from the point where it was launched. Answer: The object will land approximately 2.72 meters away from the launch point.
6:37 Velocity = 20 km/hr = 20×1000/3600 = 50/9 m/s = 5.55 m/s Angle of elevation with the ground= 30° Range= (5.55)²sin(2×30°)/(9.8) ≈ 2.72201 metres (Its the maximum range, g is taken constant, and the mass is neglected. If mass is also taken into account then the range would be less than this)
6:41 speed(V)=20km/hr=5.55555556 m/s θ=30* Maximum distance can be covered by her(R) = (u^2 sin2θ)/g = (30.86419753 X root 3 )/ 2g = 2.727467258 Absolutely crazy 😅
6:37 at this point you asked us a ques Ans. u=20km/h=5.5m/s g=10m/s*2 Range of a projectile= u^2*sin2theta/g =5.5^2 x sin60/10 =3.025 x √3/2 =2.6165 Pls like, it took some effort to calculate ❤❤❤❤ Length of 1 car= 4.8m Length of 5 car=24m Theta=30 The range of projectile=u^2 x sin60/g 240=u^2 x √3/2 u^2 = 240 x 2/√3 u=4√30/√√3 Therefore required velocity=4√30/√√3 CHEEN TAPAK DUM DUM
6:38 34.64 m which is not about even above 3 to 4 vehicles . These serial are actually illogical But when u roast them satisfaction milta hai aur hasi bhi band nhi hoti😂😂😂
Nischay seriously m apko dekh k bhut khush hoti hu life m kbhi apse Milne ka moka mila na m us din bhut khush hongi ap bhut acche ho me kitna hi presan hu pr apko dekh k sach m khush ho jati hu
6:33 Initial velocity 20km/h =20x5/18 = 5.5m/s Slope 30° from horizontal axis , varticall velocity hogi usinthetha= 2.75m/s and horizontal velocity hogi ucosthetha =4.8 m/s Ab hamare pass x and y component aa chuke h to easy rahega time of flight niklna. Let's find time of flight= 2u/g = 0.55 s Yaha pr maine Y component ki velocity li h maine cauz (TOF) vertical velocity pr depend krta h na ki horizontal pr. Range nikalte h aab, R=UxT= 4.8x0.55 =2.64m pr jakr land krega scooter Isme horizontal velocity li h cuz range horizontal velocity pr depend krta h.
Oo Bhai gazab sabke answer dekhe Maine sale sab log sidha formula dal ke answer bata rhe the lekin tumne to step wise pura solve kia h and explanation bhi accha kia h jaise vertical velocity hi kyu li time of flight mai 👍
6:15 In this Case
Let initial velocity (u) is 20km/hr=5.55m/s
Angle is 30°
Gravity(g) is 9.8m/s^2
Range that is horizontal distance covered is,
R=u^2xsin2(30°)/g
=5.55x5.55x0.866/9.8
=2.72
Matlab thele par se gaadi sirf 2.72 meter aage jake giregi.
Height attained by scooty is,
H=u^2xsin^2(30°)/2g
=5.55x5.55x0.25/19.6
=0.4 meter
Matlab scooty Gaadi ko jake thokni chahiye.
Time Required is,
T=2usin(30°)/g
=2x5.55x0.5/9.8
=0.6 seconds
Matlab ki scooty ko 0.6 seconds me niche girna chahiye par yaha to scooty is flying for 9 seconds💀💀
(1 like to banata hai)
Edit: Nishchay Bhai please ♥️
Ooo BC mujhe tution dede vro
Jee aspirant spotted👍👍
@@Swara_47 I am preparing NEET😅😅
@@Harshvardhan_Patil1008 Ohh! Sorry but atleast I was right that you are preparing for a competitive exam ! 😃
💀🫥🙏ram ram bhaiya 🫥🙏
6:41
Given:
- Mass of the object (m) = 350 kg
- Initial speed (u) = 20 km/h
- Angle of projection (θ) = 30°
First, we need to convert the initial speed from km/h to m/s:
1 km/h = 1000 m / 3600 s = 5/18 m/s
So, initial speed (u) = 20 km/h * 5/18 = 100/18 m/s ≈ 5.56 m/s
Now, we can calculate the horizontal and vertical components of the object's velocity:
Horizontal component (ux) = u * cos(θ)
Vertical component (uy) = u * sin(θ)
ux = 5.56 m/s * cos(30°) ≈ 4.81 m/s
uy = 5.56 m/s * sin(30°) ≈ 2.78 m/s
Next, we can calculate the time of flight (t) using the vertical motion:
The time to reach the highest point (time to peak) is given by:
t_peak = uy / g, where g = 9.81 m/s² (acceleration due to gravity)
t_peak = 2.78 m/s / 9.81 m/s² ≈ 0.283 s
Since the motion is symmetrical, the total time of flight is twice the time to reach the peak:
t = 2 * 0.283 s = 0.566 s
Finally, we can find the horizontal distance (range) the object will travel:
Range = ux * t
Range = 4.81 m/s * 0.566 s ≈ 2.72 meters
Therefore, the object will land approximately 2.72 meters away from the point where it was launched.
Answer: The object will land approximately 2.72 meters away from the launch point.
💀💀💀
Broo forget everything about the outer world 💀💀💀
Kaun se grah se ho bhai?🤔
U r great!! 😂
@@cskyoo6495 YOOOO 2 MINS AGO
3:42
what a kidney touching acting 😂😂😂
Kuch to touch hua 😂😂
@@_tanya11_😂😂😂
12:19 ,literally 😂i am watching this video while eating bhel puri 😄
6:37 Velocity = 20 km/hr = 20×1000/3600 = 50/9 m/s = 5.55 m/s
Angle of elevation with the ground= 30°
Range= (5.55)²sin(2×30°)/(9.8)
≈ 2.72201 metres
(Its the maximum range, g is taken constant, and the mass is neglected. If mass is also taken into account then the range would be less than this)
Sch btana engineering kr rhi ho na😅
Simaraa😅😅
Lemda = 9.8 always remember it by oure science teacher 😊 hehehh by the way wow but in 50/9m/s exact mean I didn't understand!
Hey bro , can u say how much speed and elevation with the ground we need to cover the distance showed in that serial, plss
Sidha answer batana tha
Pura chapter hi pada diya 😂😂
14:07 Roti ❌ Rotla ❌ Dhakosala ✅
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Kash aaj mere 8subscribers hogayen
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I'm your biggest fan br0
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10:05 i could practically smell the edits
Yeah, I know how shit smells.
Just like trash
3:48 gaming insaan set up❤
12:57 Cry wala laugh ya laugh wala cry 😭🤣
14:21
Didn't realise how these 14 min passed, literally amazing video enjoyed it so much.💖💗
10:16 was chikna triggu's supremacy!!❤️❤️
12:26 meri bhi insta feed pura is cheez se ki bharti hainn😂😂
To ye dekh ke feed kyu bhar rhe ho😂😂
1:58 Seriel wale be like humare yaha aise hi hota h😂🤣
0:01 reminds me of old Ashish Chanchlani videos 😂❤
Kamla OP😂😂
Sameeee😢 nostalgia ❤
Same❤
0:07 hehe
Exactly 💯😂
4:01 shaddi bhi ho gya bacha bhi ho gya 😂😂😂😂
Theta 30⁰
Velocity 20 km/hours = 5.5 m/s
Range = u² sin2∅/g
Range = 1.5125 √3
=2.619 meter
Kya bhai
Ae baigan 👀🤣🤣
Bhai isko math bolte h na😮
@@LUCKY_GAMERRR😂😂😂
Bhai Bhai
9:06 sasural simar ka❌
Makkhi✔️
Makhija returns
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BRO IN SHOCK 😶😶IN 1SEAND 4:09
Vanshaj 😂😂
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Nonu ne reply de diya kash muje bhi de deta 😢
Iss reel ka link dedo koyi mujhe dkhna hai plzzz
Ye wastage of food hai
6:41 speed(V)=20km/hr=5.55555556 m/s
θ=30*
Maximum distance can be covered by her(R)
= (u^2 sin2θ)/g
= (30.86419753 X root 3 )/ 2g
= 2.727467258
Absolutely crazy 😅
Bhai decimal ki start ki 2 digits hi consider karte hai😅😅
YE TO DEV MANHUSH NIKLA RE!😅😵😵..........
itna brain study me lagata to ye video abhi nahi dekh raha hota😂😂...
EDIT:Btw,don't take my joke seriously.✔✔
🤓🙏
Lagta Hai Pura Physics Yahi Nikal Gaya
😂😂😂😂
@@ElectroGamer722yeh wahi log hai jo videos me bhi padhai dhund lete hai😎
2:16 kawrrrrrrrrrrr 🦴
6:37 at this point you asked us a ques
Ans. u=20km/h=5.5m/s
g=10m/s*2
Range of a projectile= u^2*sin2theta/g
=5.5^2 x sin60/10
=3.025 x √3/2
=2.6165
Pls like, it took some effort to calculate ❤❤❤❤
Length of 1 car= 4.8m
Length of 5 car=24m
Theta=30
The range of projectile=u^2 x sin60/g
240=u^2 x √3/2
u^2 = 240 x 2/√3
u=4√30/√√3
Therefore required velocity=4√30/√√3
CHEEN TAPAK DUM DUM
😂😂
🎉🎉 we haven't started trigonometry in class yet so I won't understand the solution BTW nischay should give heart to ur comment
Thankyou guys for the appreciation
Bro kuch samajh nhi aya 😂😂 I am. Commerce student
WHAT bro you r genius btw I m only in sixth but that trigonometry should be like basic
6:00 gravity ki bizti Kar di bhai😅😊😂
9:39 When Nischay said daru piyagi 💀💀
Iykyk 💀💀
Mai yahi comment dudne aya tha😂😂
oo daru badnaam kardi
Macher ka pate bhar Aaraha hai
😂
13:10 Aapne waqt badal diya jasbat badal diya zindagi badal di 😂😂😂😂😂😂 unexpected serials seens ye scam ko India se bhar mat jana do😂😂😂😂😂😂😂😂😂😂😂😂😂
9:10 TV serial super cheap 🙄🤒
10:15 wow omha❤❤❤❤
4:09 kya scene tha 😂❤ you are the best
2:45 ap janata ko murk samjhna band kare ...hagu😂😂❤
Tum kon ho 😮
11:46 That make sense that you are A whole Green forest because you know that who is red forest😁😁😁😁😁❤❤
3:56 😂😂😂 41:21 statue 😂😂 12:25 hachiwali seen bohat cute thi yaaaar🤓💞💞appki hachi bohat cute he 12:45 😂😂❤
Life hack 069 💀 9:49
Why 69😂
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I am your 100th liker😂
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10:20 hero toh ho hi aap 😊😊
I
Yeh me kehne hi wali thi fir yeh comment dikh gayi😅
Yes but no my brother
4:05 😂😂😂😂😂😂😂
13:45 -- mujhe toh unse jada apne pe hasi a rahi hai
Pehle ye serial mai seriously dekhti thi😂
Pehle wale serial k naam kya tha?
Sath nibhana sathiya@@RG-lo8wr
@@RG-lo8wr I wanna know the same
5:03 main aise hi statue hokar phone pakad ke video dekh rahi thi but fir aapki video dekh rahi hu toh hasi toh aa hi jaata hai 😂😂😂
1:35 Sellmon Boi Driving 🤘😂😂
3:16 avinash mishra jo abhi bigg boss 18 me hai 😂
3:56 was epic finally nishchay ki shadi to hui chahe noni banake hui😂😂
Tum kon ho 😮
12:52 old laugh is back 😂
4:32 Statue 😡🤣
Bhai those marzil and vanjaj ke scenes gave me nostalgic memories back ❤.....
Becuz I'm re-watching this video after completing gaming insaan ❤
3:51 this scene 😂
❤❤❤❤❤❤😂😂😂😂😊😊😊😅😅😅😅😅😅😅❤❤❤❤❤❤❤❤ hai na 😹 hai 😂
POSE THORA CASUAL HE🌚🤧👊🏻 5:40
Tum kon ho
69 likes ☠️💀
@@painfulsadbrokensong3452Chup gawar
@@painfulsadbrokensong3452 insan human😂
sahdeep2005😂50
5:31 kya pose me statue huye he😂😂
12:28 koi naa bro video banane ke liye content to mil hi jata hain naa is se 😀😀
1:31 Most hilarious 😂😂😂😂😂😂😂😂😆😆
13:28 papita ka pate ko lagakar face transplant😂 That make me so laugh 😂😂😂
6:38 34.64 m which is not about even above 3 to 4 vehicles . These serial are actually illogical
But when u roast them satisfaction milta hai aur hasi bhi band nhi hoti😂😂😂
9:40 triggu said daru piyegi ❤😂
5:26
the power of statue 😂
7:21 what the heck is that 😶kuch bhi matlab kuch bhi
2:27 Kya karu me MBBS krna chhod du kyaa😢😢😢😢..Aise hi theek ho jayenge sab🫠🫠🫠🫠🫠
Chod Munna Bhai mbbs wala ban ja😊
Etna achha video kiyu bnate ho bhai jishe dhekh ke meri hashi hi nhi rukti hai...😂😅🤣🥰
2:30 doctor's be like hum job chorde ?? 🤣
12:11 nischay yeah dekhne ke baad bhelpuri khana mat chod dena 😂😂
13:35 Mera bhi mann ho raha hai 😑😢😂😂
11:29 11:29 11:29 11:29 11:30 11:31 11:31 11:32 11:32 11:32 11:32 11:33
12:45 his laugh 🤣🤣🤣🤣🤣🤣🤣🤣
😂😂😂😂
11:22 Coco melon 😂
10:15 style walk❌cute and crazy walk✔️
10:06 triggu bhai u don't have to do all this u already look like a hero ❤
2:50 Nischay's narration is epic 😂🔥
12:55 haas rahe ho ya ro rahe ho 😅
12:24 this is how my friends eat during out lunch break
Same 😂😂😂
Nischay seriously m apko dekh k bhut khush hoti hu life m kbhi apse Milne ka moka mila na m us din bhut khush hongi ap bhut acche ho me kitna hi presan hu pr apko dekh k sach m khush ho jati hu
6:33
Initial velocity 20km/h =20x5/18 = 5.5m/s
Slope 30° from horizontal axis , varticall velocity hogi usinthetha= 2.75m/s and horizontal velocity hogi ucosthetha =4.8 m/s
Ab hamare pass x and y component aa chuke h to easy rahega time of flight niklna.
Let's find time of flight= 2u/g = 0.55 s
Yaha pr maine Y component ki velocity li h maine cauz (TOF) vertical velocity pr depend krta h na ki horizontal pr.
Range nikalte h aab,
R=UxT= 4.8x0.55 =2.64m pr jakr land krega scooter
Isme horizontal velocity li h cuz range horizontal velocity pr depend krta h.
Oo Bhai gazab sabke answer dekhe Maine sale sab log sidha formula dal ke answer bata rhe the lekin tumne to step wise pura solve kia h and explanation bhi accha kia h jaise vertical velocity hi kyu li time of flight mai 👍
🏅🏆 Le bhai rakh le
you've absolutely smashed it mate.
🤯
Mind blowing sir g 🤓 konsi class mai ho aap 😭
11:00 Caption gaya tel mein 😶🥲
12:50 the mood swings bruhhhh 😂😂😂
05:00 .... Aree vaai statue bana hua tha koi mobile churake vaag gaya 😢
7:02
😂😂 ro rahe he sab
9:33 vo aapaki kaju katli he😂😂
Tum kon ho 😮
1:45 🌚daru was personal 🐸
Uske kaan me ear phone he 3:27😂
9:12😂😂😂😂😂😂
12:39 aur kha bhelpuri bnd krdo bhai ab ye khana 😂😂
Jhalmuri khao
4:20 Statue 😂😂
Love ur videos😂❤❤ . This 14 min of video made my day❤
That's great
10:06 nonu bhaiya to pehle se hi hero material hai ❤
Pagle
Yeah you are right❤ nishchay bhaiya are very handsome and cute boy❤😊
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07:28 😂😂😂 ooh ohh ohho ohhoo 😂😂
12:05 ese logo ko dekh kar hi india ko unhygienic kahate ha
6:05
Ladke❎
Papa ke pari✅
5:16 Statue scene ft. Nonu 😂🔥
English or Spanish 😂
It's giving English or Spanish vibe 👽💀🤷😂
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Think you 104 Subscribers ❤
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12:18 bhaiya is literally crying for his favorite food "bhel puri"😂😂
Hi
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0:34 best 😂😂
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Papa nhi maama
Maa Kasam jisne like nhibkiya
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9:19 logic 😂😂 rip
1:16
itna achaa toh meri physics ki teacher bhi nahi padhati😂😂
3:21 Nation wants to know 😂😂
😅 If you saw it😁 you saw it😅 (headset in girls ears )
1:05 just nischay finding logics 😂😂
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6:40
velocity=20km/h=5.55m/s
maximum range on angle 30=((5.55)²*sin(2*30))/g
=(30.80)*1.73/2*9.8
≈ 2.718 metres(mass neglected)
air drag lele account mein
6:25 .. when an engineer become roster 😂😂😂😂
6:55 Omg😂😂😂❤
Funniest part and Funniest video ever😂😂😂❤❤
Bhaiyaa aaapki sb videos ko dekhkr bina hsse rha hi nhi jata😅😅😂😊
10:14 🥺❤️ Nischay...🫶🏻