Hofmann Elimination, Amine to Alkene (aka Exhaustive Methylation)

1. Add excess CH3I (methyl iodide) to make -NH2 into -N(CH3)3+
2. Addition of Ag2O will precipitate AgI and leave OH- leftover
3. OH- will help perform E2 elimination with N(CH3)3 as leaving group.
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[@pragatid9534]

Passing 12th grade chem cause of you! Thanks

[@chemistNATE]

Chyeahhhhh

[@chakravarthy34]

Ag2O is a basic oxide & in aqueous solutions undergo hydrolysis to give a basic solution , which is used as a base.
Further Silver Iodide precipitates , since its soluability product is low.

[@norahchabu6923]

This is nice. You just made me understand this 🙂🙂

[@singing_saurabh8990]

Thanku so much sir...this video really helped a lot👌👍🙏

[@ritikyadav3165]

I think u r right

[@nasarchoori3093]

May i know which class you are??

[@cassied9327]

Very clear and fun lesson

[@jiyamudgal7715]

Thanks , sir it is a very useful video

[@ritikyadav3165]

Sure

[@ab56895]

Just a small doubt,
What will be the product when CH3I (methyl iodide) is added to CH3-NH2 (primary amine) ?
Will the product be CH2=N(CH3)3 ?
Note: Here, equals sign (=) is a double bond
and, minus sign (-) is a single bond.

[@53khandakalepratikpravin91]

CH3I+ CH3NH2---∆-->CH3NHCH3+HX
( 2°amine)

[@nourhanmb6586]

Helped a lot, so thankful 🥺❤️

[@swetasingh3662]

Could you please tell me how to avoide OH ion to nucleophilic substitution with methyl iodide...??

[@mirjanavrdoljak899]

Can you help me with this reaction:
HOCH2CH2CH3 + CH3I (excess)
Thanks

[@이도형-y4n]

I wonder how CH3I makes -NH2 into -(CH3)3+... somebody knows?

[@abhipshasharma9726]

Thank you so much, this was awesome

[@edupugantivenkat7093]

incredible!

[@هيناتاميديا]

this is very nice❤

[@simranvidyarthi2916]

Helped alot , thanks 👍

[@gunasekaran5469]

Good explanation sir...

[@玩了七年的漢默]

thank you

[@dushyantvyas1659]

thank you soo much :)

[@devanshgupta687]

Thanks

[@vasanthjk2628]

hi sir , i didn't understand that stereochemistry part , its bit difficult

[@lakshmisomasi6216]

Stereochemistry deals about cis and tra in this case but jee syllabus only 8 membered alkene ring can show cis and trans variations because of its large size so it is less hindered .in the case of cis it is same as the usual one and in case of trans the ring is passes over it , now when I say ring that means one of the carbon-carbon bond so that it can from trans , trans in 8 membered ring brings stability due to less dipole moment and in other rings which have less than 8 carbons in it ,the trans type brings instability due to angle strain as rest all carbons are sp3 hybridized so angle between them should be 109.5°

[@ritikyadav3165]

Metoo

[@StudymotivationAk]

Good

[@saranshdhage]

Nice..

[@sheesh1706]

Aymeen