Wow , You have no idea how this saved me. I had to balance this equation and I had no idea how to do it , but I did not even think of doing by a mathematical way . I was trying to do it by the oxidation numbers but it confused me even more. Thank you very much for teaching this method. Now I will use this method every time I have a similar equation
Mounir Zouhari I am so glad this helped! I came across this problem on an exam, and the guess and check method took too long for me. So I watched other people on RUclips do the algebraic method on other chemical problems, and decided to try it on this one! Good luck to you!
Hi there! Yes you can use 2 or 3, what will happen if you declare another value is that the rest of the numbers will change accordingly. It’s sort of like changing the ratios to a cooking recipe. I also made a video on how to declare an arbitrary value if that helps!
Hi Beatrice, sorry for such a late response! I made a video on how to declare an arbitrary value for you. Hopefully this helps. If not please let me know and I’ll try to see if I can be of more help. Here is the link. ruclips.net/video/Gn3QSi2rm14/видео.html
Hi there! Yes you absolutely can! It should work. If you start with the following: (NH4)2[Cr2O7] and go through decomposition to give Cr203 + 4 H2O + N2 So 1:1:4:1 is the balanced reaction.
Plss solve it properly you have done some mistake I have made it in the same manner and my answer matches with the solution so kindly check the mistake you made 😊
Wow , You have no idea how this saved me. I had to balance this equation and I had no idea how to do it , but I did not even think of doing by a mathematical way . I was trying to do it by the oxidation numbers but it confused me even more. Thank you very much for teaching this method. Now I will use this method every time I have a similar equation
Mounir Zouhari I am so glad this helped! I came across this problem on an exam, and the guess and check method took too long for me. So I watched other people on RUclips do the algebraic method on other chemical problems, and decided to try it on this one! Good luck to you!
You deserve so many more subs.
Wow thank you so much❤🎉
I have no words sir, i can only say thank you sooo much ♥️
Ur method is like totally different but really useful😀😀
Thank you for the feedback! I am glad it is useful for you!
Tnx u saved my life
13:17 how u did -2 i didnt understand that part ?
Thank You Sir
Its Really Helpful.
😃😃😃😃
From India❤❤
❤️ from India
Thank You Man
AMAZING
Hello! This video is super helpful! Could the arbitrary value be anything? For example, could it be 2 or 3? Would you still be able to solve it?
Hi there! Yes you can use 2 or 3, what will happen if you declare another value is that the rest of the numbers will change accordingly. It’s sort of like changing the ratios to a cooking recipe. I also made a video on how to declare an arbitrary value if that helps!
Hello, how do you declare arbitrary variables? Thank you!
Hi Beatrice, sorry for such a late response! I made a video on how to declare an arbitrary value for you. Hopefully this helps. If not please let me know and I’ll try to see if I can be of more help. Here is the link. ruclips.net/video/Gn3QSi2rm14/видео.html
I think we usually take coefficient of bigger compound 1 to balance the chemical equations.
Thank you so muchhhh🙏🙏
Hi sir, could I use this method in solving the thermal decomposition of ammonium dichromate which gives chromium(III) oxide,water and nitrogen?
Hi there! Yes you absolutely can! It should work. If you start with the following:
(NH4)2[Cr2O7] and go through decomposition to give Cr203 + 4 H2O + N2
So 1:1:4:1 is the balanced reaction.
❤😊 best enough
Genious
Wrong my answer is coming 3cu+8hno3 - 3cu(no3)2+2no2+4h20
Sir plzz try to explain in hindi😊😅
Plss solve it properly you have done some mistake I have made it in the same manner and my answer matches with the solution so kindly check the mistake you made 😊
Tnx u saved my life