circular convolution

[@miguelorellana777]

Very good presentation.

[@cricketindia8804]

sir, its a great video ,cleared my concept over circular convolution, but I want to bring 1 thing in yo notice that,
in solution part,
you took h(n)=(2,1,1,2) and
in question u were supposed to solve for h(n)=(2,1,2,1)....correct me if I am wrong.
great video indeed..hope u keep making such videos for DSP

[@akhtarin]

You are absolutely correct. here h(n) should be {2,1,1,2} .
Thank for this correction.

[@cricketindia8804]

thanks again sir,
today it was my DSP classtest... and yo videos did help a lot... there was no need to memorize u cleared my concepts in some minutes... thanks and keep up yo work sir,
and hope u can bring some videos for signals and systems...thanks again

[@punjabnewsexclusive2196]

Suprb sir ,""simple ,silent and sounding"" lecture

[@payares164]

One question : The result funcion only appears in the outpout domain one time in the N points or it appears periodically with period N to infinity ?

[@vijaysinghrajput8526]

super...plz make more videos...u are awwsome

[@ramavatarmeena5988]

Good Explanation

[@LiNa-sm3gf]

Thanx 👏👏👏👏👏👏 from mu heart u help me sou much even though i don't understand your langauge

[@anandburud6917]

thank u sir for ur valuable knowledge .. ur student(varsha ).

[@chokopola8664]

thank you so much sir. sir do give coaching for GATE exam?

[@meghanar4949]

We have to find idft at the end

[@ft-7683]

NOTE *h(n) = {2,1,1,2}*

[@mohamedasem6523]

h(n) = {2,1,2,1} in the Question and he draw it correctly
but when he start substituting became h(n) = {2,1,1,2} !!

[@bilalraees1211]

if N is not same for both x(n) & h(n), than??

[@KnowledgeAmplifier1]

Padd zeros at the end and make the 2 length same

[@expertforum5048]

brother your video is owsome.. keeep it up please. it is simple and straight forward.i like it very much. can i get your email or skype id?.

[@akhtarin]

[e-mail]