Periodic or Circular Convolution Watch more videos at www.tutorialspoint.com/videot... Lecture By: Ms. Gowthami Swarna, Tutorials Point India Private Limited
Thank you so much madam. I am Mathematics faculty . This method is easy and very clear . I will use your method to explain linear and circular convolution to my students.Great applause for your contribution.
In this case, you have X[n] having values for n as 0, 1, 2, 3... That is X[n]={1 2 1 1} are values for n= 0 1 2 3. This is for n>=0. What if you have n= -1, - 2, 3... also. That is for n
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Thank you so much madam.
I am Mathematics faculty . This method is easy and very clear .
I will use your method to explain linear and circular convolution to my students.Great applause for your contribution.
You are a good teacher.
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Good
@@Ash-ey7bj Thank you I thought you are scolding me as "Dog Student" 😂😂😂😂😂
Madam If we write like this. They will give full Marks?
This is absolutely amazing and a lot easier and efficient that the way we do it in my class, thank you very much, continue with the great work!
That trick is absolutely genius! Thank you so much for the clear explanation😍
excellent video. VERY CLEAR! Many Thanks
Even at the 1.5x speed
Her teaching was just awesome and easy to understand🔥
Weird flex but ok
quite Unparalleled teaching style. Huge love and gratitude from Bangladesh. Highly praiseworthy.
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Thank u so much i passed ny exam due to u. Very good clss. I can understand very thing thanks
Highly appreciated. Easy to understand.
This is very much useful for me .thanks a lot .keep uploading more videos
Thanks a lot Madam, you are a great teacher.
from Constantine, Algeria
Greetings from greece, amazing, easy to understand video
its really helpful for engg students so keep going and help the nations
Oh my god! Thank you maam.. this is soo easy method!
Haha react er option thakle tr reply a haha react kortam😂
If we write like this. They will give full Marks
Thank you so much mam ur videos r very helpful to me
Very helpful tutorial.Thank you.
I learn circular convolutoin very well miss😀
Thanks. It was a lot of help
Very useful video. Thank you mam
Very clear explanation and easy trick mam...slowly came to know that tricks are far better than watching nptel videos 😅
Fantastic way thanks a lot
You're so amazing!
Nice video ,thank You Ma'am
Thank you, you're amazing
Thank you!
Great tricks
Thanks you. It’s very useful. :D
Thank you madam from Nepal 🙏🙏
Fantastic nice explanation
thanks a lot !!!😍😍
I have understood, Thank you madam
Please share this channel as much as possible
Superb explanation mam....plz if possible post a vedio with 2 signals each one with different number of sequences
Thank you so much maam.
Thank you ma’am
Neatly done ✅
Thank you so much mam
Tqu mam
Saved my bacon! Cheers!
Thanks a lot miss 😀
Nice explanation
Thank you madam
Super! have a good day
Nice
Thanks
Hintli ablacım sizi de seviyoruz allah razı olsun
You just saved my mind from going crazy
good,,,
Nen unna position la nee kaallu mokkina thakkuve akkaa🙏🙏
THANK YOU MAM
In one problem is h(n )take it is parallel
In 2nd problem take as horizontal
How to write x(n) from graph confusining me a lot pls help me
💖💗
Should x(n) & h(n) both be periodic to use circular convolution?
Yes
In this case, you have X[n] having values for n as 0, 1, 2, 3... That is X[n]={1 2 1 1} are values for n= 0 1 2 3. This is for n>=0. What if you have n= -1, - 2, 3... also. That is for n
as the signal is periodic so you can write the signal in terms of n>=0 for this method you have to that
love you
God
How to manage carry on sum by column method while addition
Don't worry about carry if the addition yields 12 just write as 12
Hexophion and Exophion signals?
but what if different sample sizes?
i lovs yous very much
U can simply multiply
Yea but then we will have to take the last 4 digits ig
If carry is generated then??
Mam, what if there a carry????
Don't worry about carry if the addition yields 12 just write as 12
but what is the idea behind it?
If only x(n) is given not h(n) in qus. Then how to find circular convolution?
E.g. x(n)={1,2,3,4} arrow below 1
Insufficient data bro
If we write like this. They will give full Marks?
x(n) = {1,2,-1} h(n) = x(n) find y(n) and validation?? plz solve this
Bro ans should be { -3,-3,2}
@Serious Sam yeah bro u are right 😅
Thank you so much madam
Many thanks from Brazil. You saved my night now I can slap with my girlfriend
Woa????
Slap that basss
Are you sure
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How do u write h of n as an array?
Video are not clear mam
Thanks mallu:)
Thank you. One more thing, please marry.
lol....
Bruh
Thanks. It was a lot of help
Thanks. It was a lot of help