Isn’t the 4th step explanation that your giving is for overlap and add method.... Please check. Why are we adding M-1 samples to the previous block in overlap and save method.
The length of the output signal of convoluted signals x (of length A) and y (of length B) is A+B-1. In this case A=12 and B=3 therefore the length of the output signal is 12+3-1=14
Thank you so much for the video. Everything is so well explained and illustrated. I wish my professors could explain things as good as you do!
Good video! Very clear and easy to understand! Thank you!
11:26 The matrix multiplication is backwards. you can't multiply 4x1 matrix with a 4x4
Yeah he solved it in wrong way, it should've been 4x4 multiplied with 4x1
Why did you take 1,2 in x6[n] instead of 1,1?!
very helpful thank you very much saved my day
Very helpful video. Thank YOU for uploading .
Good one sir 👍
Excellent
Thank you so much
There were some mistakes but thank you for visualization
What is the criteria of choosing the value for 'N'? Why have you taken it 4 or 8??? Why not non-multiples of 4?
what to do when we are said to take L=3 and h(n) is given as [1,2,3]
You did a wrong in the step of x[6]....
ossom
very helpful tnx!
do you have also vid on overlap add?
Thank you for watching. I will upload a video on overlap add method soon.
akhtar nadaf kab kroge sir??
Isn’t the 4th step explanation that your giving is for overlap and add method.... Please check. Why are we adding M-1 samples to the previous block in overlap and save method.
sir
x(n) has 12 values
But y(n) has 14 values how this possible sir???
The length of the output signal of convoluted signals x (of length A) and y (of length B) is A+B-1.
In this case A=12 and B=3 therefore the length of the output signal is 12+3-1=14
You should take faster
talk