Solved Exam Problem: Hydrostatic Force on a Semi-circular Plane Gate

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  • Опубликовано: 13 сен 2024
  • MEC516/BME516 Fluid Mechanics: Solution to the hydrostatic force on a plane gate. This is a typical exam-type question.
    All of the videos in this course, sample exams (with solutions), and a copy (pdf) of this presentation can be downloaded at:
    www.drdavidnayl...
    Course Textbook: F.M. White and H. Xue, Fluid Mechanics, 9th Edition, McGraw-Hill, New York, 2021.
    #fluidmechanics #fluiddynamics

Комментарии • 15

  • @FluidMatters
    @FluidMatters  Год назад +1

    All the videos for this introductory Fluid Mechanics course are now available at: www.drdavidnaylor.net/

  • @altmylife
    @altmylife Год назад +2

    Thank you for sharing your knowledge, this video has helped me start to get a better grasp on these kinds of problem. I'm not sure how but I ended up with a yCP value of 2.63. I used the equation from the FE exam reference handbook: yCP = yC + IxC/yC*A. My yC value was 2.6 which I got from adding the centroid distance to the slant distance from edge of gate to edge of water. I had the same IxC and A values. Any idea where I went wrong? My handbook doesn't include the formulas you were using but I was able to solve for the normal force to the gate using my version of that formula.

    • @FluidMatters
      @FluidMatters  Год назад

      Sorry, it's super hard to debug solutions with just a comment to go by, often with different nomenclature (i.e., yC).

  • @Gaelleda
    @Gaelleda Год назад

    when do we use the area of the projection to calculate the horizontal force? in some exercises hey use the area of the projection and in others like yours they use the area of the initial shape. i don't know when we must you each of them

    • @FluidMatters
      @FluidMatters  Год назад +1

      Note that the force F is normal to the gate. If you the projection (into the vertical plane) you would get the horizontal force. So, you can use the technique often used for curved gates here too, if you want.

  • @emirbfitness
    @emirbfitness Год назад +1

    you’re the best

  • @jackiebooth4452
    @jackiebooth4452 2 года назад

    What is the equation for yr?

    • @FluidMatters
      @FluidMatters  2 года назад

      yr? I suggest giving a time marker, as I a don't know what you are referring to.

  • @Gaelleda
    @Gaelleda Год назад

    I think that Yc = Yg + Ixx'/A×Yg
    And Ixx' = 3,14×r²/ 4
    So I don't understand what you did

    • @FluidMatters
      @FluidMatters  Год назад

      Ixx is the 2nd moment of area about the horizontal axis through the centroid of the semi-circle. It is correct in this solution for sure. Note that Ixx must be proportional to R^4. Your formula for Ixx (with R^4) looks like it is for a full circle, rather than a half-circle. That's the best I can do for you.

    • @Gaelleda
      @Gaelleda Год назад

      @@FluidMatters yes that's true. Thanks a lot but for the formula of Yc. Is it correct?

    • @FluidMatters
      @FluidMatters  Год назад

      @@Gaelleda Difficult to say, as you are using a different nomenclature that me.

    • @user-gw3bv3fn8o
      @user-gw3bv3fn8o Год назад

      @@FluidMatters I come up with this Ixx = πr⁴/8 = 0.3927r⁴

    • @FluidMatters
      @FluidMatters  Год назад

      @@user-gw3bv3fn8o This is not the second moment through the centroid of the area. Your formula is about the wrong axis location (the base of the semi-circle.