Interpretation of SAED pattern | estimation of d-spacing & (khl) values - 29

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  • Опубликовано: 19 окт 2024
  • In this video, I have shown how to analyze Selected Area Electron Diffraction (SAED) pattern using ImageJ software. Like my other videos, this is the only available video on the internet, which shows some very important and simple tricks for interpretation of the SAED pattern.
    After watching this video, you will be able to calculate the following parameter from the SAED pattern:
    1) 1/D (per nm)
    2) 1/r (per nm)
    3) r (nm)
    4) d-spacing (Å)
    5) Miller indices (hkl)
    6) Indexing SAED pattern
    If you have any questions, ask them in the comment section below. For more videos, please subscribe to NanoWorld. Thank you.
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Комментарии • 118

  • @ANP-
    @ANP- Год назад +3

    Thank you very much Sir. Please do make more videos on Characterization to help people like us. You are a very good teacher.

  • @gezahegntadesse7228
    @gezahegntadesse7228 2 месяца назад +1

    A few people are confused about the conversion of.......1/D nm-1 into 1/r. You need to divide the 1/D values by 2. The formula for the conversion is 1/r = 1/D × (L / λ) / 2. Where: 1/D is the reciprocal space measurement in the SAED pattern. L is the camera length of the TEM. λ is the wavelength of the electron beam. The reason for dividing by 2 is that the diffraction spots in a SAED pattern correspond to the scattering vector, which is defined as: q = 2π / d. Where d is the real-space interplanar spacing. Thank you in advance

  • @Hkvlogs1154
    @Hkvlogs1154 2 года назад +1

    Really Very helpful videos.........
    Clearly explained all things that we have to do

  • @harishchandranishad6041
    @harishchandranishad6041 3 года назад +2

    Thank you for making this very informative video. I would like to thank you from the bottom of my heart. and one request is to please, kindly make one video on monocrystalline TEM SAED pattern analysis and spacing.

  • @saharjafari2484
    @saharjafari2484 Год назад +1

    thank you for the useful and complete information.

  • @mani2263
    @mani2263 3 месяца назад

    Excellent video, covered every aspect. I have one question kindly respond to clarify concept of the community. Right from the start, obtaining 1/2r, till matching d spacing you video is very coherent. However, to obtain 1/r (2nd column of the table) from 1/2r, instead of dividing it by 2 (which you did), should we not do the multiplication? i.e. 1/2r * 2 = 1/r

  • @anishajoseph2353
    @anishajoseph2353 Год назад

    Very Informative video. Sir please put this type of analysis for all characterization methods

  • @uzmasubhan877
    @uzmasubhan877 Месяц назад

    Very helpful session

  • @juanca17063
    @juanca17063 3 года назад

    Thanks a lot, very well explained.! Regards from Mexico

  • @aryanfathoniamri956
    @aryanfathoniamri956 3 года назад +1

    Thank you very much for the tutorial. Please make a video about the SAED pattern of LRTEM. There is no scale in the SAED pattern

  • @alexandrerodriguessimoes8020
    @alexandrerodriguessimoes8020 Год назад

    Thank you!! God bless you!

  • @fionajoylinemascarenhas5266
    @fionajoylinemascarenhas5266 Год назад

    Thank you very much for the video sir

  • @fayzahtalbi3348
    @fayzahtalbi3348 3 года назад +1

    Many thanks. Please make a video on the Single crystal SAED pattern .

  • @MrShkolololo
    @MrShkolololo 3 года назад +1

    Thank for your tutorial, it was very helpfull!

  • @HongNguyen-mb3io
    @HongNguyen-mb3io 2 года назад

    Thank very much for your usefull video

  • @Vinodpanwar94
    @Vinodpanwar94 3 года назад +3

    Please make a video on Single-crystal SAED pattern as well!

  • @КонстантинГорбунов-ы7ц

    Thank you for the informative video.
    Why didn't you use the formula L•lambda=R•d to find d - spacing?

    • @pinakmiku4999
      @pinakmiku4999 2 года назад

      Is this that you are mentioning the bragg equation?

  • @ahmedmalik9974
    @ahmedmalik9974 6 месяцев назад

    Nano world plz make such more videos

  • @vedant2136
    @vedant2136 3 года назад

    Nicely explained work . Thanks 🎉🎉

  • @souravpan3068
    @souravpan3068 3 года назад

    You are doing really nice work.

  • @jinzhou4327
    @jinzhou4327 2 года назад +3

    Could you please also make a video on how to index spot diffraction pattern? Really appreciate it.

    • @muhammaddanishiman1951
      @muhammaddanishiman1951 10 месяцев назад

      hello there, do you know how to index spot diffraction pattern?

  • @DrHaffeast
    @DrHaffeast 10 месяцев назад

    Can I know why the biggest radius on the small circle or inside circle. Instead of outer circle? Suppose (200) should be place at outer circle. I am new to this can you clarify.

  • @clauberdalmas
    @clauberdalmas 3 года назад +1

    Excellent! Thank you

  • @priyankadogra3258
    @priyankadogra3258 10 месяцев назад

    Thankyou sir your vdieo help me alot❤

  • @ritikacharak9650
    @ritikacharak9650 2 месяца назад

    Thank you.

  • @seenaselvam3326
    @seenaselvam3326 Год назад

    Kindly provide the JCPDS No for MXene..wonderful video

  • @dr.poojashandilya6885
    @dr.poojashandilya6885 2 года назад

    Thank you so much your video is wonderful.

  • @gaanak6595
    @gaanak6595 3 года назад

    Thank you for this video

  • @ahmadaziz5263
    @ahmadaziz5263 3 года назад +1

    Thank you. awesome!

  • @dhanyanp666
    @dhanyanp666 3 года назад

    Very useful videos, go ahead.

  • @majidraza346
    @majidraza346 4 месяца назад

    Thank you sir

  • @adelal-salihy9451
    @adelal-salihy9451 Год назад +1

    1/r = 2(1/2r) Therefore, when calculating (1/r), you should have multiplied (1/2r) x 2, but I noticed that you are dividing by 2. Can you explain that please?

  • @Mosesnewtechnology
    @Mosesnewtechnology 2 года назад +2

    Thank you for the tutorial, the math for converting 1/2r into 1/r may not be right. I think you are supposed to multiply not divide by 2. i.e 1/2r is a smaller value than 1/r. please check, thank you for the information

    • @dperea
      @dperea 2 года назад

      I think you are right, if 1/2r=n; then 1/r=2n.
      But then why it seems to be right when compared with the standard values in the card?

  • @kavitayadav8351
    @kavitayadav8351 3 года назад +1

    Hello sir, will you plzz make a vedio on the wemple -Didomenico for determining the non- linear refractive index

  • @harry-ho9ti
    @harry-ho9ti 3 года назад +1

    Sir pls upload more tutorials. Pls upload Vesta software tutorial.

  • @inamali2729
    @inamali2729 3 года назад +5

    Why you divide 1/2r values to find 1/r values ?

  • @zahirmuhammad9133
    @zahirmuhammad9133 3 года назад

    Great job sir

  • @tariqmslihsaadalhgre9775
    @tariqmslihsaadalhgre9775 Год назад

    Great explanation, Can I have JCPDS file for Bi2O3

  • @rcfychemistry3082
    @rcfychemistry3082 2 года назад

    How can we interpret the HRTEM images of nanoparticles and quantum dots..? Can u explain it in hindi..?

  • @research8540
    @research8540 8 месяцев назад

    Sir, 1/r = 2 times of 1/2r . Then How you did the half of 1/2r for 1/r ???

  • @aakashhossain7993
    @aakashhossain7993 Год назад

    I do not have any access to the JCPDS card for my use !! Is there any public domain from where I can access the JCPDS file ?

  • @dongmeimaylin4188
    @dongmeimaylin4188 3 года назад +3

    from C column to D column , it should be 1/2r *2 = 1/r

    • @nanoworld6122
      @nanoworld6122  3 года назад +14

      You are right,
      But his is not the mistake. The actual mistake is, I measured 2R but mistakenly labeled it as 1/2R in the first place and then use R instead of I/R.
      However, the method and calculation is accurate. But you need just to consider the 1/2R as 2R, 1/R as R.

    • @sharafpc786
      @sharafpc786 2 года назад +1

      @@nanoworld6122 yes.. i was wondering the same thing

  • @Vinodpanwar94
    @Vinodpanwar94 3 года назад +1

    Thank you!!

  • @simransapra823
    @simransapra823 3 года назад

    Awesome..Really helpful...

  • @asmasiddiqa8098
    @asmasiddiqa8098 8 месяцев назад

    thats great

  • @ahmedmalik9974
    @ahmedmalik9974 6 месяцев назад

    Plz make more videos.Very less videos on this channel are.

  • @rajshekhar616
    @rajshekhar616 8 месяцев назад

    Going from 1/2r to 1/r, you should have multiplied 2 not divided 2. I do not know how you got the right answer?

  • @kalpanagarg1301
    @kalpanagarg1301 Год назад

    How to get the jcpds card can you provide the link of your video in comment box?

  • @mariappankaruppiah177
    @mariappankaruppiah177 3 года назад +1

    How pair hkls, When more than one hkl for a calculated d spacing?

  • @harry-ho9ti
    @harry-ho9ti 3 года назад +1

    Please do a vdo on ac conductivity fitting and how to calculate the atomic positions of a sample for rietveld refinement. Pls. suggest the site.

  • @harry-ho9ti
    @harry-ho9ti 3 года назад +1

    Sir wht ll b d next video. Pls upload next one.

  • @ranjitkate8396
    @ranjitkate8396 2 года назад

    Please upload the videos on d spacing calculation from HRTEM image and XPS convolution and deconvolution

  • @mariappankaruppiah177
    @mariappankaruppiah177 3 года назад +1

    If the d spacing lower than 1A
    How to identify the hkl?

  • @skylerxing7548
    @skylerxing7548 2 года назад +2

    Very brilliant video. But I am wondering if I am wrong about the 1/2r and 1/r in relative values, if anyone can tell.

    • @trithien3t
      @trithien3t Год назад

      I am also think that, 1/2r=a => r= 1/2a, but in this case r is calculated reversely

    • @SP-qv9ui
      @SP-qv9ui Год назад

      1/2r is not a 1÷ (2r) its 2r in reciprocal plane

  • @suranjanapatowary9524
    @suranjanapatowary9524 2 года назад

    While indexing Miller indices in Microsoft paint, you have indexed the plane corresponding to the least r-value to the outermost circle. I am confused at this point.

  • @sanchiakharphanbuh251
    @sanchiakharphanbuh251 2 года назад

    Thank you for this video. Can I have JCPDS file for Mn2o3 and MnO

  • @LAURASILVANASALASCHAVEZ
    @LAURASILVANASALASCHAVEZ 8 месяцев назад

    no tienes el word editable ?

  • @anjalibaburajan2963
    @anjalibaburajan2963 Год назад

    Thank you soo muchh sir...can you please provide jCPDS card of Ceo2

  • @bharathimeti7753
    @bharathimeti7753 3 года назад

    Thank you for this tutorial. Kindly give me all values for PCMO , jcpds no. is 89-795. Also for BCMO Jcpds no. is 57- 767.

  • @sanmilankalita9058
    @sanmilankalita9058 Год назад

    Why did you divide 1/2r to find 1/r?????

  • @Ayu-rx3dz
    @Ayu-rx3dz 2 года назад

    Thank u so much for your guide sir. Sir, do you have JCPDS card no. 52-0875 for Ti3AlC2?

    • @nanoworld6122
      @nanoworld6122  2 года назад +1

      email respomded

    • @Ayu-rx3dz
      @Ayu-rx3dz 2 года назад

      @@nanoworld6122 Thank u so much sir, This really helped my research

  • @solankianitaba9399
    @solankianitaba9399 2 года назад

    please gave information that my XRD data match with which number JCPDS FILE NUMBER

  • @ashwinichavan7447
    @ashwinichavan7447 11 месяцев назад

    Hi can u pls provide jcpdf of 15-0087.

  • @richasharma5993
    @richasharma5993 3 года назад

    Thanku sir very informative video. Sir please send me the JCPDS File for ZnO

  • @pratikshatanwade3781
    @pratikshatanwade3781 3 года назад

    When saed scale is 10 1/nm then what will be the calculations and to decide that?

    • @mehdikhadem2576
      @mehdikhadem2576 2 года назад

      just in the Image-J, Analysis>set Scale change 2 to 10. the rest of the process remains the same

  • @gunntea9545
    @gunntea9545 2 года назад

    Why d=1/R ?? I only know that d.R=L.landa
    Could you tell my why L.landa=1 ?

  • @RohitSharma-yp5mg
    @RohitSharma-yp5mg Год назад

    Respected sir can you please provide me this standard values card ..???

  • @meemalli3328
    @meemalli3328 Год назад

    Hi, could you please share me the terbium JCPDS data?

  • @lakshmikantasain5667
    @lakshmikantasain5667 7 месяцев назад

    Could you please provide jcpds file of reduced graphene oxide and graphitic carbon nitride

  • @debashissarmah6390
    @debashissarmah6390 Год назад

    Required JCPDS Card.

  • @subinkc3539
    @subinkc3539 2 года назад

    JCPDS 44-0141 ?? can u pls share the jcpds file of alpha- MnO2

  • @TheAbhi23456
    @TheAbhi23456 3 года назад +1

    Thanks for the tutorial, it was helpful. Can you please help me in my SAED pattern through mail, I have some specific questions about it.

  • @anjalisuryavanshi6971
    @anjalisuryavanshi6971 Год назад

    Hello sir can you provide jcpds card

  • @sanjeevip6701
    @sanjeevip6701 3 года назад

    Analyse single crystal SAED pattern!!

  • @goyenkaneelam
    @goyenkaneelam 3 года назад

    How to index saed of crystalline materials

    • @nanoworld6122
      @nanoworld6122  3 года назад

      This video was for polycrystalline SAED pattern. However, I will upload soon a video on the interpretation of single crystalline SAED pattern.

    • @andreachan8944
      @andreachan8944 3 года назад

      @@nanoworld6122 Thanks a lot! I am looking forward to watching your new video.

    • @shobhnathgupta2618
      @shobhnathgupta2618 3 года назад

      Thank you sir. We are eagerly waiting for this.

  • @mohammedsalah1673
    @mohammedsalah1673 3 месяца назад

    Plz prof, could you send me a JCPD card of graphene oxide?

  • @chetanawasthi5610
    @chetanawasthi5610 2 года назад

    Please provide data for JCPDS file No. 290914

  • @nirmalkundu164
    @nirmalkundu164 3 года назад

    jcpds card no- 411445 for sno2

  • @BreakThroughBB
    @BreakThroughBB 3 года назад

    Sir.. please help me to analyse .. I calculated the d spacing but due to lack of jcpds card, I couldn't do it.. will you please provide your email address?

    • @nanoworld6122
      @nanoworld6122  3 года назад +1

      email address is available at the end of video.

    • @BreakThroughBB
      @BreakThroughBB 3 года назад

      @@nanoworld6122 got it sir❤️🔥

  • @sukanyaguharoy2739
    @sukanyaguharoy2739 Год назад

    What is your email ID?