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at 23:45 what if the concentration is below 18.3% at a temperature of 150 would the calculations of W(alpha) and W(beta) be the same or would it be different?
α, β and L are used to represent the different phases of the system. α, and β represent solid solutions of Sn into Pb and Pb into Sn, respectively. With that in mind, I don't think it's right to say that the α+β phases are present in the liquid phase. Moreover, in the liquid phase, there are both Sn and Pb, but as liquids, and not as α, β solids. Therefore, within the L+α region we have a liquid phase (L) and an solid phase (α), and both of them are solutions of Sn and Pb.
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6 years later and let me tell you,,, You saved me through my exams. I was so confused with all the lines but this video right here changed my story. Thank you.
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At 25:37 shouldn't the concentration of Tin in the liquid phase be 61.9 wt% Sn? So, 18.3 wt% Sn would be the concentration in the alpha-phase right?
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at 23:45 what if the concentration is below 18.3% at a temperature of 150 would the calculations of W(alpha) and W(beta) be the same or would it be different?
7:24 Nice
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I have received your distance hug. Glad to help.
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If we are in L + α , it means [(liquid=α+β) + solid α ) ] ?
α, β and L are used to represent the different phases of the system. α, and β represent solid solutions of Sn into Pb and Pb into Sn, respectively.
With that in mind, I don't think it's right to say that the α+β phases are present in the liquid phase. Moreover, in the liquid phase, there are both Sn and Pb, but as liquids, and not as α, β solids. Therefore, within the L+α region we have a liquid phase (L) and an solid phase (α), and both of them are solutions of Sn and Pb.
Me watching this for no reason
i understood shit
Thank you!