Maximum Likelihood Estimation for the Geometric Distribution

[@danielkojoakaachobli2628]

Thanks Prof. The confusion in my mind in respect of maximum likelihood estimation has now been cleared.

[@Comrade-wv1lu]

এই টপিকটা নিয়ে যতটুকু কনফিউশন ছিলো সব দূর করার জন্য অসংখ্য ধব্যবাদ। ভালোবাসা নেবেন।

[@traj250]

Great vid to follow the diff steps. Professor skipped a lot of steps and was confusing (jammed into the end of lecture of course). Thanks for the clear video!

[@Thergh]

It's always like that. I hate when they do this, it leads to so much not needed fructration

[@Thergh]

What a great explanation, thank you for making my exams easier!

[@pauleseme8406]

Well explained, you have rescued me indeed, thanks

[@catiat7262]

Hello, first of all, thank you very much for your videos. I just watched some concerning maximum likelihood estimator and it was very helpful. However, I just came across with an error in this formula. The estimator of p should be 1/x-bar. I think the problem starts with the definition of the pmc.

[@JohnEvorda]

Thank you Prof God bless ...

[@carylannebeltran]

Thank you so much! This was so helpful.

[@Agustinoism]

Thank you so much. Can you do uniform distribution next.

[@yousif_alyousifi]

Thank you for a great video. May I know which tools you are using for delivering this lesson?

[@traj250]

looks like one note? or similar to

[@Blahcub]

This is incorrect because xi in the definition should be xi-1. This means our true answer should be 1/xbar.

[@johnnysins4870]

That’s only if x = 1..2..3….. not if x starts at 0 no

[@Blahcub]

@@johnnysins4870 why tf johnny sins in a maximum likelihood estimation video lmao

[@johnnysins4870]

@@Blahcub Research for new role coming up

[@sathapornwattana2239]

Thank you( Exp100)

[@giuliomartini6892]

This ain't it bruh

[@natehagen9710]

This might be part of it...

[@traj250]

might be because how he defined the pmc at the beginning... that's what I think at least

[@kriszhli]

This is correct. Most people define n as positive integer but here n can be 0.