Conductometric titration of weak acid and strong base (weak acid vs strong base)/Conductometry

This video describes how to draw the conductometric titration curve for a weak acid with a strong base (acetic acid/CH3COOH vs sodium hydroxide/NaOH). It explains about the Conductometry, Principle of Conductometric titration. It explains on how to draw the conductometric titration curve for the mixture of acids with a strong base. Introduction of Conductometry, Conductance, advantages and disadvantages of conductometric titration, applications of conductometric titration.
Before titration - only CH3COOH present
CH3COOH does not dissociate easily - low conductance
Initial addition of NaOH - CH3COOH and small amount of CH3COONa
CH3COOH does not dissociate easily due to common ion effect of CH3 COO- - slight decrease in conductance
During titration till equivalence point /neutralisation point -
CH3COONa ionises better than CH3COOH - conductance increases slowly
At equivalence point/neutralisation point - CH3COO- and Na+ are present
Conductance increases
After equivalence point - excess NaOH is added
accumulation of OH - with high ionic conductivity - conductance increases drastically
High concentration of salts in the solution does not give accurate results
Presence of other electrolytes other than the species to be analysed will not give accurate results
Limited use for redox titration.

[@Itz_ronny07]

Superb Superb Superb...
No words are found for Appreciation of method of explaination and information...
👌👌👌👌👌👌👌

[@RevathiPurushothaman]

Thank you very much for your compliments.

[@Incredible_Dam]

Mam, I think it should be the Conductivity or Specific Conductance graph. 🤔

[@parulsoni964]

Thanks a lot,🌸🤩

[@RevathiPurushothaman]

You are most welcome.

[@Xzlovier]

Mam slight correction at 2:40 , if already CH3COONa has formed and applying common ion then also ultimately conductance should increase since CH3COONa has been formed and dissociates in its ions more easily , even compensating the decrease in dissociation of CH3COOH and thus increasing the conductance overall .

[@RevathiPurushothaman]

In the beginning when it just starts to form only, this common ion effect will lead to a small dip.

[@sainibhattacharjee645]

Thank you very much Madam

[@RevathiPurushothaman]

Most welcome.

[@gayaprasadbauddh6521]

Thanks you soo much mam for explaining too good 🙏

[@RevathiPurushothaman]

You are most welcome

[@pakomotshwarakgole9796]

Why should readings near the endpoint be ignored mam?

[@RevathiPurushothaman]

We are not ignoring. We need not be as careful as in the case of volumetric titration. We are going to obtain the end point from the intersection of the 2 lines only.

[@pakomotshwarakgole9796]

@@RevathiPurushothaman oh alright thank you

[@RevathiPurushothaman]

Most welcome.

[@shubhamsinghmahar212]

It's just amazing ❤️😍

[@RevathiPurushothaman]

Thank you so much.

[@rohit451.]

Nice explanation thank uh ma'am.
My lab ma'am explain but i didn't get all. But here all clear.

[@RevathiPurushothaman]

Thank you. It's my pleasure.

[@manrajpreet2904]

Thanks alot, it's helpful

[@RevathiPurushothaman]

Most welcome.Happy that it helped you.

[@dipitakarmakar1975]

If we dilutied naoh will there be any change

[@cricketlover5153]

Thank you so much mam...ur saviour for me😌😌❤

[@RevathiPurushothaman]

It's my pleasure.

[@vishanthn4211]

Very informative

[@RevathiPurushothaman]

Thank you.

[@dipakranjanparida855]

Mam u can show that the end point in the titration curve

[@RevathiPurushothaman]

The intersection of the two lines is the send point. It is shown in the titration curve.

[@faithcherop9089]

Thanks alot..👍❤️.

[@RevathiPurushothaman]

You are most welcome.

[@kartikpunde7793]

Best explanation mam 🙂

[@RevathiPurushothaman]

Thank you very much.

[@AtwiineOsbert-eo3gl]

This is the best

[@RevathiPurushothaman]

Thank you so much.

[@DS.Debabrata_Saha]

*Very very helpful for me*

[@RevathiPurushothaman]

Its my pleasure.

[@dipitakarmakar1975]

What if there is volume correction??

[@RevathiPurushothaman]

What do you mean?

[@shivukumaralamani4408]

Thank you 😊

[@RevathiPurushothaman]

Most welcome.

[@rakesh-zb2kq]

👍👍tq madam

[@RevathiPurushothaman]

It's my pleasure.