Part c asks for over/under estimate at M(2)...shouldn't we be using value from part b and not M(0)...won't change the final answer, but thought we should use M(2), not M(0)
For part c, you wrote the second derivative expression as d^2M/dt^2 = 1/4(-dM/dt). But wouldn’t the second derivative just be the value -1/4 since you’re deriving in terms of M and not t? So it would be d^2M/dt^2 = 1/4(-dM/dM) which is just d^2M/dt^2 = 1/4(-1) ?
It's an arbitrary constant so it doesn't matter until you actually solve for C. the final result is all that's really going to matter, which I think is correct.
Everyone online complaining about milk but I’m over here with 9/9 on this frq 😂
fr me too 🤣
Who?
Cares
oh i did not get this right...
I did part a and dipped.
For part D I kept the constant in the exponent so my value for c was a little different and so was my particular solution, would this be okay?
Part c asks for over/under estimate at M(2)...shouldn't we be using value from part b and not M(0)...won't change the final answer, but thought we should use M(2), not M(0)
Wait the goat frq helper is FROM MY CITY⁉️that’s so cool
For part c, you wrote the second derivative expression as d^2M/dt^2 = 1/4(-dM/dt). But wouldn’t the second derivative just be the value -1/4 since you’re deriving in terms of M and not t? So it would be d^2M/dt^2 = 1/4(-dM/dM) which is just d^2M/dt^2 = 1/4(-1) ?
Nevermind we are still finding the second derivative in respect to t but in terms of M. I got it now
@@ladymisfortune1015 made the same mistake as you lol
For d I believe you moved over 40 incorrectly as you end up with all positive numbers when C should have been subtracted from 40
It's an arbitrary constant so it doesn't matter until you actually solve for C. the final result is all that's really going to matter, which I think is correct.
I didnt finish d but I separated it right, integrated, think I found c 😭😭 but I should get few points for it maybe 2 idk
I did this as a logistics problem I hope I didn’t get the whole thing wrong
What if you made the solution curve go through the point and it looks like that but a little higher
It doesn't have to be exact. As long as it mostly follows the slope field
Does it have to go through the point ?
yes
ur funny math man