2023 AP Calcululs AB & BC FRQ #4

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  • Опубликовано: 11 сен 2024
  • 2023 AP Calculus AB & AP Calculus BC Exam Free Response Question #4
    Function Analysis (Working with the first derivative)
    Topics: max/min/neither; intervals concave down from f’; limit; l’hopital’s rule (l’hospital’s rule); absolute minimum (candidates test)
    See more about L’Hospital’s Rule on the AP Exam here: • Using L'Hopital's Rule...

Комментарии • 30

  • @emmettjonesiii6092
    @emmettjonesiii6092 Год назад +5

    Just wanna say thank you as I used your videos a lot to study before the exam. Definitely wouldn’t have done well without you

    • @turksvids
      @turksvids  Год назад +1

      Awesome! Congrats on finishing the exam.

  • @shiv5702
    @shiv5702 Год назад +1

    Thanks so much for your help, I cant express how much your AP review quizes, rate in rate out video and your FRQ videos for each year helped. Thank you!!

    • @turksvids
      @turksvids  Год назад

      happy to hear some of my stuff was helpful! please share with your teacher/friends, in case future people can benefit too!

  • @abdallahsaleh1359
    @abdallahsaleh1359 4 месяца назад

    I do have a quick question tho. Regarding part a what I wrote is "Neither; because when x < 6, f'(x) >0 and when x > 6, f'(x) is also greater than 0". Would this be considered correct?

    • @ecomink
      @ecomink 4 месяца назад

      I don't think so, heres the scoring guide from the official website on this question
      •A response that declares f ′( x) does not change sign at x = 6, so neither, is sufficient to earn
      the point.
      • A response does not have to present intervals on which f ′( x) is positive or negative, but if any are
      given, they must be correct. Any presented intervals may include none, one, or both endpoints.
      • A response that declares f x ′( ) > 0 before and after x = 6 does not earn the point.

  • @andreaaacd9956
    @andreaaacd9956 Год назад +2

    all i did for part c was L’Hopital’s rule then found the limit, i hope that was enough 😭 4:02

    • @turksvids
      @turksvids  Год назад +4

      remains to be seen on the scoring guidelines. you'll get the vast majority of the points at minimum, maybe all of them (we can hope!)

  • @darkgalaxy9936
    @darkgalaxy9936 Год назад

    For 2b would saying f is concave down on (-2,0) and (4,6) because f’’(x)

    • @turksvids
      @turksvids  Год назад

      I’m not clear on what the ruling is on that. Generally you have to connect the explanation to the given. So f” is negative “because f’ is decreasing. “

  • @ashvinjaishankar3813
    @ashvinjaishankar3813 Год назад

    One of my students asked if it’s okay to justify that there is a point of inflection at x=6 so therefore it’s neither a relative max nor a relative min. Unusual approach but it sounds like as long as they properly explain the reasoning it should work.

    • @turksvids
      @turksvids  Год назад +1

      That’s a really interesting response. I think it definitely gets the point.

  • @Rose-pe1ob
    @Rose-pe1ob 4 месяца назад

    Turk I have a question please , there is a question that says find the volume of s which has the equation y=e of x -2 (-2down) but using rectangle cross section with height 5 times base , since region s is under the x axis well the answer be the integral from 0 to ln 2 of(0)-(e^x -2)^2 times 5 dx?
    Or without the 0 minus the whole equation? Please I need answer
    Is it correct?

  • @Rishkapish
    @Rishkapish Год назад +1

    Based on the frqs compared to last year... how do you think the curve is going to compare to last years?

    • @turksvids
      @turksvids  Год назад +1

      i really think it'll be about the same. it never moves all that much.

  • @yusufnaqui713
    @yusufnaqui713 11 месяцев назад

    Is the candidates test necessary to solve part d? Like could you just say that since f'(x) goes from negative to positive as it crosses x=2 then x=2 would have to be a minimum?

    • @turksvids
      @turksvids  11 месяцев назад +1

      You don't have to use the candidates test, but you do have to address that the question is about an absolute minimum, not a relative minimum. So you have to account for the end points somehow or make clear that they yield larger values. Good question!

  • @imbeckyv
    @imbeckyv Год назад +1

    At least I know I got at least 7/9 on this FRQ

  • @mercury4477
    @mercury4477 Год назад

    Is it okay to say "As f'(x) > 0 for 2 < x < 8, both f(6) and f(8) are greater than f(2), and thus can't be the absolute minimum"?

    • @turksvids
      @turksvids  Год назад

      yeah, not just okay, almost certainly better. candidates test was kind of annoying on that one!

    • @yatharthc6475
      @yatharthc6475 Год назад

      thats what i said too

  • @lucasliftslight
    @lucasliftslight Год назад

    Could you do the international FRQ?

    • @turksvids
      @turksvids  Год назад +1

      I would if they released them but unfortunately they only put out one set per year!

  • @andreaaacd9956
    @andreaaacd9956 Год назад

    wait does it matter if we wrote it as (-2,0) and (4,6) on part b 1:42

    • @turksvids
      @turksvids  Год назад

      like...did you mention they were intervals somehow? otherwise they kind of look like ordered pairs. not sure how they score that. (sometimes they're lenient, sometimes they're crazy strict on fine details.)

    • @darkgalaxy9936
      @darkgalaxy9936 Год назад

      You should earn the point since it’s interval notation. I did the same as well. The readers will know what you meant even if you didn’t do inequality notation.

  • @faeology
    @faeology 5 месяцев назад

    thank you for clutching us for the ap exams dude

    • @turksvids
      @turksvids  5 месяцев назад

      I'm trying to get everyone a 5 on this thing!

  • @calebcharlie4363
    @calebcharlie4363 Год назад

    For some reason I said -1

    • @turksvids
      @turksvids  Год назад

      it happens. testing situations are very different from casual study/review.