Note :- The braking force Fb originating from the brake system and developed on the tire-road interface is the primary retarding force. Braking force Fb is given by , Fb= (Tb-ΣI*α )/r ,where Tb is the applied brake torque, I is the rotating inertia connected with the wheel being decelerated, α is the corresponding angular deceleration, and r is the rolling radius of the tire.(Fb= Fbf+Fbr) The maximum braking force that the tire-ground contact can support is determined by the normal load and the coefficient of road adhesion. With four-wheel brakes, the maximum braking forces on the front and rear axles are given by, Fbf(max)= (mu)*Wf Fbr(max)= (mu)*Wr . If Fbf = Fbf(max) then tire will slide and on further increment of Fb will lead the tire to lockup.Similar for the rear braking.
Why solving the equation you considered the moment at A and B is zero... But when a car is moving its tyres has moment, then how can you consider it zero
I Guess , when the braking force is maximum, the vehicle has stopped completely i.e, the wheels are not rotating anymore , hence they won't exert any force on the ground.
Note :- The braking force Fb originating from the brake system and developed on
the tire-road interface is the primary retarding force. Braking force Fb is given by ,
Fb= (Tb-ΣI*α )/r ,where Tb is the applied brake torque, I is the rotating inertia connected with
the wheel being decelerated, α is the corresponding angular deceleration, and r is the rolling radius of the tire.(Fb= Fbf+Fbr)
The maximum braking force that the tire-ground contact can support is
determined by the normal load and the coefficient of road adhesion. With four-wheel brakes, the maximum braking forces on the front and rear axles
are given by,
Fbf(max)= (mu)*Wf
Fbr(max)= (mu)*Wr .
If Fbf = Fbf(max) then tire will slide and on further increment of Fb will lead the tire to lockup.Similar for the rear braking.
Why solving the equation you considered the moment at A and B is zero... But when a car is moving its tyres has moment, then how can you consider it zero
@@harivardhan8678 moment about a is zero
Great Boss
why is tractive force not included in calculating brake force?
I Guess , when the braking force is maximum, the vehicle has stopped completely i.e, the wheels are not rotating anymore , hence they won't exert any force on the ground.
We just find the value of Maximum braking force , that leads to locking.So, no tractive force is included in the derivation.
Assuming one is not pressing on accelerator pedal while braking
change the mouse pointer it is so distracting
what is 'μ' while calculating maximum braking force?
Bro how do we find the rotational inertia and angular deceleration.
Bro how did you find Fb and Fbr , Fbf