Please thanks alot for your insight. But I'll like to rectify a mistake at the latter part. You were supposed to multiply the exponent that's -2 by the coefficient of -3🙏🥰
@@nhamiltondwight thank you so much! im quite stuck on a question as im get 2 different set of results using this method and also quotient rule. I cant figure the mistake ive made in either of them!
@@nhamiltondwight Actually the reverse so if y=x/3. It would be much appreciated. I am currently working on rate of change questions involving parametric you see, and this sort of thing is coming up frequently. The current one I am working with is 4πx2/25.
Nicole Hamilton Your video was very helpful, and so was my lecture. However applying what I’ve learned doesn’t give me the correct answers when I check my textbook answers. So I don’t understand why.
life saver I been trying to solve a math problem just like this for about an hour now lol, but not I have it solved thanks to you!!!!!!
in the second problem, shouldn’t the last part of the derivative be 6x^-3? thanks though
Yep, i was puzzled why not many hightlighted that to her.
Arigatooo
U. ARE. AMAZING. THANK YOU
In the second problem why have you changed it from 2x^3 + x to 2x^3 - x?
When you break the fractions, there is an error because the first negative should be positive Mam @Nicle Hamilton
Hi, now how will you differentiate a number over square root of x?
So noting the error, the final answer would be 18x+2+1-3/x³. Right?
And when u add the 2 and 1 u get:
18x+3-3/x³
Life saver thanks
Please thanks alot for your insight. But I'll like to rectify a mistake at the latter part. You were supposed to multiply the exponent that's -2 by the coefficient of -3🙏🥰
How would you then figure out what x would be
What if the letters was at the top like x^4/2, how will you differentiate that
@@nhamiltondwight What you said was too vague I couldn't understand it. Can you plz tell me the answer to that question if you know it?
would you get the same result had you used the quotient rule? Please please please reply
@@nhamiltondwight thank you so much! im quite stuck on a question as im get 2 different set of results using this method and also quotient rule. I cant figure the mistake ive made in either of them!
@@nhamiltondwight After a good nights sleep, i was finally able to solve it😂😂😂 thank you so so so much for this video and help!!!
What if there no x below the line and only above the line for example. Differenciate x/9
Thank you so much
how do you do this if x is solely on the numerator?
@@nhamiltondwight Actually the reverse so if y=x/3. It would be much appreciated. I am currently working on rate of change questions involving parametric you see, and this sort of thing is coming up frequently. The current one I am working with is 4πx2/25.
correction the 2 is actually an exponent
@@nhamiltondwight It does help a lot, thank you vey much.
Thank you so much for this. 👍
thank you it helped me a lot :)
Thanks for the Vid!
HELP ME PLEASE
Nicole Hamilton Your video was very helpful, and so was my lecture. However applying what I’ve learned doesn’t give me the correct answers when I check my textbook answers. So I don’t understand why.
thank you so much