I have a doubt .Suppose I connect the power supply directly to the ammeter .Does the ammeter give any value?Does this value is more than the ammeter reading when we out a resistor in the circuit.
Ammeter has very small (ideally zero) resistance. Thus, current will become very large if just the ammeter is connected (a short circuit). Most powerpacks protect against this by having a circuit breaker, which automatically turns powerpack off if current gets too big. Remember: current is voltage/resistance, so if resistance gets very small, current gets VERY big.
MsJovi102 Voltage is low, so no real hazards. Just take care as input to powerpack is from mains. Resistor can get hot for big currents so take care when handling. Sources of error: calibration of meters (zero error), reading scales on meters, minor fluctuations in readings during each trial; if you are going to find R of resistor using the graph gradient, then the resistance of connecting wires is another source of error to consider.
components may become heated due to the current flowing through the circuit, causing the effective resistance to increase which affects the p.d and current reading.
If you connect your power supply the other way around, the circuit will still work. A current will still flow (just the other way). The only difference would be that ammeter and voltmeter would show negative values if we reversed the terminals of the power supply.
Arjel Onde Hi. It was a 10 ohm resistor. You can see the whole experiment carried out here: ruclips.net/video/hxYn74Yhkpk/видео.html. The resistance is the voltage lost across resistor divided by the current through the resistor.
Felix Olsson thanks for the reply...I really appreciate it... I have no practical knowledge about electricity and all those lab experiments... Every now and then i am watching tutorials in youtube... But theory wise, i can explain and discuss all of it.... nice video by the way...
Hi, if you have a constant voltage supply, and want to use a rheostat to vary the voltage across the resistor/bulb, then connect your resistor/bulb as in this diagram - bit.ly/2M6ZzU9 - and put your ammeter in series with bulb/resistor, and voltmeter in parallel with the bulb/resistor. You can then use the rheostat to vary the bulb voltage from 0 to max.
![I.N "HALLUCINATION" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/n5B5q1Hwt_U/mqdefault.jpg)
my worst embarrassment as a physics student is my lack of knowledge about circuits... but this video helps a LOT. thanks man
same
same, I can handle theory stuff but when it comes to circuits i get so annoyed and frustrated
Same
you weren't the only one
Thank you . It was very useful . It cleared all my misconceptions . Keep up the good work
This really helped in my practical exam Thanks❤
Nice explanation...this video helped me so much ....👍
Well explained cleared all my misconceptions
it's sooooo helpful thnq really it hlped me a lot..!!
Thanks.....It helped me a lot
Hey......I am replying on my own comment😆😆😆
Lol
Very helpful kind sir. Have a nice day
I had my practical exams tomorrow thank u for clear explanation
Same as me.
Thank you very much. This video has cleared all the contradictions.
I have a doubt .Suppose I connect the power supply directly to the ammeter .Does the ammeter give any value?Does this value is more than the ammeter reading when we out a resistor in the circuit.
Ammeter has very small (ideally zero) resistance. Thus, current will become very large if just the ammeter is connected (a short circuit). Most powerpacks protect against this by having a circuit breaker, which automatically turns powerpack off if current gets too big. Remember: current is voltage/resistance, so if resistance gets very small, current gets VERY big.
It's just amazing and thanks because of you I passed in my exams
Can you list some precautions and possible sources of error for an experiment such as this? Thank you.
MsJovi102 Voltage is low, so no real hazards. Just take care as input to powerpack is from mains. Resistor can get hot for big currents so take care when handling. Sources of error: calibration of meters (zero error), reading scales on meters, minor fluctuations in readings during each trial; if you are going to find R of resistor using the graph gradient, then the resistance of connecting wires is another source of error to consider.
components may become heated due to the current flowing through the circuit, causing the effective resistance to increase which affects the p.d and current reading.
It's really confusing in another tutorial the negative terminal of the transducer is connected to positive of ammeter
If you connect your power supply the other way around, the circuit will still work. A current will still flow (just the other way).
The only difference would be that ammeter and voltmeter would show negative values if we reversed the terminals of the power supply.
Excellent job sir 👍😊
Thank you! Cheers!
great sir u explain very well
7 yrs later he became a legend
Thank you so much for your video is helpful for my exem perpose
Thank you so much
It is really a very helpful video!!
Thanks bro for the information 🙂
Sir please tell me how to plot a graph for Ohm's law flower.
Thanks its very helped for me
nice video
its really working🤗😊
May I ask how do we know which wire to use to connect the terminals? And how to know which terminal connect to which?
Its colour coordinated
Thanks for perfect explanation!!
Well explained...thank you
helpful, well explained
Very interesting video
Thanks l got it all
Thanks helped a lot...👍😇
Can you add a load like the knob type resistor box to this circuit
Rheostat kahan par hai
U made it easy sr thanks
If I will connect ammeter after resistor (near positive terminal) what will happen. Is current varies?
May God bless your soul.
how many ohm did u use for resistor ?
Cant remember, but you should be able to work it our from the voltage and current😁
Thanks for your support!
Great help.Thank you so much
What is the name of the nosil you added to connect wire to key
Do you mean the crocodile clip? Some call them alligator clips :)
thnx..it's very useful
How much ampere it was ?
Pls tell why ammeter is connected negative to negative and positive to positive?
They are just made that way - it's convention. If you hook it up the other way you will get a negative reading.
Thanks this really helped
I love this keep it up
thanks sir
Can we make the circuit without using resistor or rheostat?
Among d 2 small machines which one is ammeter and voltmeter
Robert George The one with A on it is ammeter, V is voltmeter. It is kinda small, but you should be able to see it.
This is wonderful
Very clear , thanks
helpful thank you, sir
Haw to mark Ampiyr metor resisror....
can you make a video on the kinds of resistors?
Carbon Composition Resistor.
Thermistor.
Wire Wound Resistor.
Metal Film Resistor.
Carbon Film Resistor.
Variable Resistor.
Varistor
Light Dependent Resistor.
thanks helped a lot
is voltmeter reads from zero or is just a source of error (+ error)
How many ohms is your resistor?
Arjel Onde Hi. It was a 10 ohm resistor. You can see the whole experiment carried out here: ruclips.net/video/hxYn74Yhkpk/видео.html. The resistance is the voltage lost across resistor divided by the current through the resistor.
Felix Olsson thanks for the reply...I really appreciate it... I have no practical knowledge about electricity and all those lab experiments... Every now and then i am watching tutorials in youtube... But theory wise, i can explain and discuss all of it.... nice video by the way...
,thanks it is well understood
Can u make good process to write in exam
Thanks !!!Dude!!!
Name of Connective wire
easy method thank you for
keep it up
super
Informative!
Sir how to connect rheostat in this circuit
Hi, if you have a constant voltage supply, and want to use a rheostat to vary the voltage across the resistor/bulb, then connect your resistor/bulb as in this diagram - bit.ly/2M6ZzU9 - and put your ammeter in series with bulb/resistor, and voltmeter in parallel with the bulb/resistor. You can then use the rheostat to vary the bulb voltage from 0 to max.
Thank you so much!!
Good but where is the rheostat
Simple and good one.
Who is watching in 2024😂
Meeeee😂😂
me 😂
Me
Me
Me💀
Need For exam can you explain it with whole process
Out of all the useless crap i learned in school circuits is by far the top of my list
Well explained.
Even Helpful after 7 years 😱😱😱
Thank you sir👍👍👍
Thank you❤❤❤
thank you!!!!!!!
After 30 min.... I have to give my practical 😂😂
How we we record the obseve data in this expeeiment
good idea
thank you so much sir
very useful
2021 and still helpful
Thanks sir
Ohm my gosh you should try this application! scout circuit solver on the playstore!
Upload thevenins theorem
Where's rhrostat
the power source itself can alter the voltage across the circuit
🎉thank you
thank u.very useful
no clear on reding
thanks and love u
Hello, I'M Igor ,fron Brasil city São Paulo
tysm very helpful
ohm law setting information is fine
No rheostat
shah j No. I am testing the effect of supply voltage on current so I am not changing resistance - so I am not using a rheostat.
Felix Olsson ok but can you make rheostat video circuit with rheostat plz😫😫😫
wow are you a teacher_?
Thank you
e🅱ic
isnt voltage inversely proportional to current!!
How are you from England
Where is rheostat at
No rheostat in this one - resistance is kept constant, voltage is changed and effect on current is measured.
Tq
Tq..
Love it