isn't it supposed to be, for the range, a positive 2? If you do the same idea to the denominator once you are looking for range, it would be x = 2. If not, why would x -2 still be x = -2 for the range? :"""{
Thank You So much! Our teachers at school just solve the questions and expect us to understand and when we ask questions, they make fun of us. So this was really helpful, thank you
After 10 years I through myself into a algebra 2 class and I feel like quitting. Too late to drop the class. This is the only channel keeping me alive in this class 👏🏻👏🏻👏🏻when I’m lost I come here 💯
Fastest way of finding the range: Since the degree of both numerator and denominator is the same, just divide the leading coefficient of the numerator which is 2 by the leading coefficient of the denominator which is 1 that will result to 2. Therefore range=(-○○,2)u(2,○○).
@Harris Park really? please enlighten me about this, cause I've tried lots of rational functions and they seem to be working well... Not sure about rational functions with holes tho
I really wish I had you as a teacher many years ago Brian, I'm at university and the tutor/lectures may as well be speaking a different language, you make math make sense.
Thank you! This is the best example I've seen and I have spent days trying to figure this out. It's like, everyone else seems to be able to skip the 'math' of it in broken down steps. Also, no one else has shown how to flip the variable and solve for the inverse function to find the range. The crazy part is, this is like chapter 1 in a lot of algebra books! And I can do the rest of the book just fine but domain and range of algebraic functions has always been my achilles heel. Hopefully, not anymore. And I know it's important because I want to get into some calculus soon and that whole subject seems like it's basically full of functions. Thank you again. You're my favorite math tutor on youtube because of your process and just the way you communicate idea. A lot of math teachers aren't always the best with words.
I am so thankful to have found this video, many of my previous teachers would take much longer to explain this process and I really appreciate your help. You are very good at explaining things in a sensical way!
Thank you so much I wasn't able to determin the range on a fraction equation. But now im better thank you... I hope youre still doing these videos im going to subscribe now on the channel ❤
Thank you so much, you're the first video that makes sense ,other tutorials avoid doing fractions and do easy equations instead which I find pointless but you explained this very well
Isn't the first step by finding the domain you set it not equal to zero. You set it to just zero but the denominator cannot equal zero so you have to set it not equal to zero. Like an equal sign but with a line through it. So shouldn't the domain be [-4,all real #).
سبحان الله وبحمده سبحان الله العظيم 🌼🌷🌼🌷🌼🌷🌼🌷🌼🌷🌼🌷🌼 اللهم اني اسألك الهدى، والتقى، والعفاف، والغنى، والمغفرة من كل ذنب. 🦋🌹🦋🌹🦋🌹🦋🌹🦋🌹🦋🌹🦋 اللهم اني اسألك النجاح والتوفيق ⚘
Why did you do all this Sir ! It was simple at first ! THAT'S MY SOLU y=(2x-1)/(x+4) xy+4y=2x-1 xy-2x=-4y-1 x(y-2)=-4y-1 x=-4y-1/y-2 SO Range is all R exepting 2 Tell me plz if it's true
I never understood why we used the x in the inverse function to predict the range But my math teacher will always be like ....domain : possible x values .....range : possible y values So can't we just make x the subject in original eqn and 🤔 about possible y's.....and leave swapping of x and y to inverse alone?
hmm, well that is more advanced than what I teach so when you swap variables look for algebraic techniques such as completing the square or dividing that can help you isolate the y. There might be an easier way but I am not sure of the right methods without spending time looking it up as I do not recall
Please does this method of calculating the range work for all rational functions? How do I find the range of (3x-8)/x squared-9x+20? Thanks for the video
Hi! can i attach the youtube link of your video to the self-learning modules of our department in order for the students to learn more from the contents of this video aside from the modules that will be distributed to them? Thanks a lot.
Hello Sir, What about this question? I have been trying for a few hours and i can't seem to get anywhere close. I managed to find the domain which is (2
![Seungmin "그렇게, 천천히, 우리(As we are)" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/kAzmhLHePqU/mqdefault.jpg)
isn't it supposed to be, for the range, a positive 2? If you do the same idea to the denominator once you are looking for range, it would be x = 2. If not, why would x -2 still be x = -2 for the range? :"""{
Chris Martin that's what I said its positive 2 he had to made a mistake it wouldn't make sense for it to be -2
that is correct, I made a mistake, comment is pinned so others can see
I was about to ask the same thing lol but good thing they pinned this :))
you can correct in the video? some ppl do it with like a note or something like this
Yeah wtf
You made more sense in the first two minutes than my PreCal teacher has all year
Well happy to do that for you
I wish you are my professor in diffirential calculus
Agreed 100%, my hs teacher garbles about other stuff while explaining math
agreed
Facts bro same
Thank You So much! Our teachers at school just solve the questions and expect us to understand and when we ask questions, they make fun of us. So this was really helpful, thank you
sorry to hear about that Vanessa, but happy to be there for you
Yea homie our teacher always did dat to me too
After 10 years I through myself into a algebra 2 class and I feel like quitting. Too late to drop the class. This is the only channel keeping me alive in this class 👏🏻👏🏻👏🏻when I’m lost I come here 💯
Range is (-○○, +2,) U (+2,○○)
Thank you,for a second I thought something was wrong with me
I know it's a late reply but ye I was gonna comment that
Yeah this is right
Fastest way of finding the range:
Since the degree of both numerator and denominator is the same, just divide the leading coefficient of the numerator which is 2 by the leading coefficient of the denominator which is 1 that will result to 2. Therefore range=(-○○,2)u(2,○○).
What if the x-4 is x+4, will it be (○○,4)(4○○)‽
Yep!!! One thing people seem to be forgetting is, you can just use your horizontal asymptote to find the range 😹
@Harris Park really? please enlighten me about this, cause I've tried lots of rational functions and they seem to be working well... Not sure about rational functions with holes tho
his vids always make us feel like we are sit-in students 😆
Thanks sir, this helped, got stumped in finding the range, but now I know
I really wish I had you as a teacher many years ago Brian, I'm at university and the tutor/lectures may as well be speaking a different language, you make math make sense.
I have forgotten this and now have to work with it again and this video put the biggest smile on my face all week!
Thank you so much, this has been such a big help, especially during quarantine :)
Thank you! This is the best example I've seen and I have spent days trying to figure this out. It's like, everyone else seems to be able to skip the 'math' of it in broken down steps. Also, no one else has shown how to flip the variable and solve for the inverse function to find the range.
The crazy part is, this is like chapter 1 in a lot of algebra books! And I can do the rest of the book just fine but domain and range of algebraic functions has always been my achilles heel. Hopefully, not anymore. And I know it's important because I want to get into some calculus soon and that whole subject seems like it's basically full of functions. Thank you again. You're my favorite math tutor on youtube because of your process and just the way you communicate idea. A lot of math teachers aren't always the best with words.
So happy to help
Always a great help. Thank you for making these videos
happy to help!
thank you so much!! i literally never understood domain and range, in under 7 minutes it all clicked
Why he sound gay for a split second
I was in deep trouble and frusted with my life then I just saw your video and it helped and brought me hope . Thank you so much
Please do not stop posting videos, you explain it far better than my textbooks
Professor McLogan, thank you for an excellent video/lecture on Finding Domain and Range of a Rational Function.
You are very welcome!!
this man needs to hit 1 million subscribers
You are helping me through my college course! Thank you.
I love you😭you literally teach me what my algebra 2 teacher should be
2:11 His voice change tho... Anyways thanks for the video! Why can’t my math teacher teach like this??
I should send you my tuition check...... I've learned more from you than my pre-cal professor....
I don't know what I would do without you
Actually you are the best teacher in mathematics.
just happy to help
I'm from Saudi Arabia this time is first time I watch your videos big thanks for the things you offer, thanks doctor
you are very welcome, I am no doctor, just a friendly guy happy to help you out!
Your way of teaching is brilliant, Kudos to you
you're the greatest human being alive tysm man
You're such a great teacher. Thank you for sharing your knowledge with us
I am so thankful to have found this video, many of my previous teachers would take much longer to explain this process and I really appreciate your help. You are very good at explaining things in a sensical way!
He who teaches math properly, I hope you're going to have great year, and if you don't, I hope you have the strength to withstand any problem.
Thanks sir this video was really helpful.As I have never got the chance to understand math this kind of a way.
Thank you so much
I wasn't able to determin the range on a fraction equation. But now im better thank you...
I hope youre still doing these videos im going to subscribe now on the channel ❤
Thank you so much, you're the first video that makes sense ,other tutorials avoid doing fractions and do easy equations instead which I find pointless but you explained this very well
Thank you so much man. Ive been struggling with the range for quite a while till your video popped up. Real life-saver
you are THE BOSS! I was struggling with this for like three days, saw your video and now i understand!
I have an algebra 1 EOC tomorrow and I super nervous, hopefully I do good
Did you do good? I hope you did
I declared you as my new math professor😀
Thank you so much! I haven’t done math in a while and am about to take a Calculus class next semester, so this refresher is very helpful!
thanks a lot Mr. Brian Mclogan
This was great :)) Thanks for sharing!
Happy to help
Thank you for teaching me through all of high school and Duel Enrollment Precal
thank you so much it helped me in my calculus exam
These videos are so helpful. Thank you!
I'm in BC calculus and I had to remind myself how to do this😂😂 thanks!!
I'm in college calculus and I had to remind myself how to do this ahaha
TKANKS! I'm a freshman, now i know how to find the Range
This is very helpful
Thank You Mr. Brian
The range, according to what you taught, is meant to be R = (-∞ , 2) ∪ (2 , ∞)
Thank you Professor 😊
You are very welcome!!
that was very helpful. thank you
I learned several times how to find the inverse but never once learned that that was how you find the range... thank you lmao
You explained it really well!!
HE IS A LIFESAVER
good job teacher respect👏
Thank you!!
Thank you, sir! 💛
Very nice explanation sir. 😊
Thanks so much😊😊😊😊
Thank you so much! this helped me heaps! :)
Yey thank you sir! Finally i got the correct answer for my homework.
Exclude the HA to find the range. To find HA , find the limit of the function when x goes to infinity.
Thanks a lot ! I suffered a lot because of this lesson
You're so helpful 😉
man the moment you got the camera i totally got lost. i need to see people do it and learn.
do you have a question I can answer?
@@brianmclogan plz send me material of Improved (G'/G) expansion method. Me doing research on this method
After I saw dis video I got good score n mah teacher banned me cuz I got de score he never expected from me tnx homie I only wanted knowledge
im taking algebra 1and got a test in 30 min this is very helpful
me as a teacher, eating all my markers in front of the class
Isn't the first step by finding the domain you set it not equal to zero. You set it to just zero but the denominator cannot equal zero so you have to set it not equal to zero. Like an equal sign but with a line through it. So shouldn't the domain be [-4,all real #).
I am finding the values that make the denominator equal to zero so I can omit them from the domain, same idea different process
this makes so much sense
thanks really helpful
you are very welcome!
Thanks I was thinking the same.
Quick question does that mean that the domain of my inverse function is my original functions range?
yep
سبحان الله وبحمده سبحان الله العظيم
🌼🌷🌼🌷🌼🌷🌼🌷🌼🌷🌼🌷🌼
اللهم اني اسألك الهدى، والتقى، والعفاف، والغنى، والمغفرة من كل ذنب.
🦋🌹🦋🌹🦋🌹🦋🌹🦋🌹🦋🌹🦋
اللهم اني اسألك النجاح والتوفيق ⚘
اللهم امين
thanks sir u r very smart teacher (:
just a lot of practice
but what about if the given denominator is trinomial? how will you solve for the range?
This helped so much thank you!!
you are very welcome! happy to be able to assist you
how did you get the -2y in line 4 in range
Cool stuff...Learned a lot from yah
Nice thanks 👌
Why did you do all this Sir ! It was simple at first !
THAT'S MY SOLU
y=(2x-1)/(x+4)
xy+4y=2x-1
xy-2x=-4y-1
x(y-2)=-4y-1
x=-4y-1/y-2
SO Range is all R exepting 2
Tell me plz if it's true
yes you have the same range as me, but I wrote it wrong
thats exactly what he did. Its the same thing.
except he interchanged, which u need to do at the end or at the start.
I never understood why we used the x in the inverse function to predict the range
But my math teacher will always be like
....domain : possible x values
.....range : possible y values
So can't we just make x the subject in original eqn and 🤔 about possible y's.....and leave swapping of x and y to inverse alone?
How do you find the range if the numerator and denminator are both quadratic equation?
domain is simple just find when the denominator is equal to zero, as far as range a calculator would be preferred to graph
But our teacher wouldn't let us use a calculator :( I tried using your method but it got more complicated than I thought btw Thanks for the reply :)
hmm, well that is more advanced than what I teach so when you swap variables look for algebraic techniques such as completing the square or dividing that can help you isolate the y. There might be an easier way but I am not sure of the right methods without spending time looking it up as I do not recall
is the short cut for finding the range is the same as finding the horizontal asymptote?
Nice One sir!!
I have a question. What if the numeratr has a squared value (x^2) and also has an x on the denominator?
Go to khan academy, they have this example you're welcome :)
this man is a god
Is a rational equation and a rational function the same? can i use that formula to find the range of a rational function?
yes
Brian McLogan thanks sir
😀
we love you brian
Sir I think it should be positive 2 instead of negative 2. Can you clarify on that.
Please does this method of calculating the range work for all rational functions? How do I find the range of (3x-8)/x squared-9x+20? Thanks for the video
I have a question though, what if your numerator is quadratic, how will you eliminate the spare y variable?
Hi! can i attach the youtube link of your video to the self-learning modules of our department in order for the students to learn more from the contents of this video aside from the modules that will be distributed to them? Thanks a lot.
Thank you very much
does this method works with any function?? because it is really easy
rational function yes, but there are variations, such as more complex examples
too bad:/ I tried it on a root function and didn't work. Well professor, can you tell me how to calculate the range?
im gonna quit the uni and watch your videos boss :D :D :D :D :D
Thank you 😊 .......
you are very welcome!
sir may i just give my comment you did the process for inverse which is solving for the new y but to find the range solve for x..
Thank You!!
you are very welcome!
Thank you❤
Hello Sir,
What about this question? I have been trying for a few hours and i can't seem to get anywhere close. I managed to find the domain which is (2
sir what if the problem is F(x)=3x two squared+2 over 4x-2? how can i solve it?
Shouldn't my answer for range be relating to y and not x? If not what differentiates domain and range?