How to Draw Shear Force and Bending Moment Diagrams for a Beam with a UDL

This video shows how to draw the shear force diagram (SFD) and bending moment diagram (BMD) for a simply supported beam with a uniformly distributed load (UDL).
A shear force diagram shows the variation of shear force along the length of the beam.
A bending moment diagram shows the variation of the bending moment along the length of the beam.
We then work through an example problem to improve understanding and enable the viewer to solve similar problems in the future.
For other videos covering beams with uniformly distributed loads, more than one point loads, shear force and bending moment diagrams and other engineering related content, please check the channel.
Link for video showing how to calculate the support reaction forces for a simply supported beam with a uniformly distributed load (UDL) - • How To Calculate Suppo...
Thanks for watching!
00:00 Introduction
00:20 What are shear force and bending moments
01:29 Example question
02:33 Shear force diagram
04:14 Bending moment diagram

[@pDamlad]

This really helps

[@user-pe2cv4tk2w]

Great graphics!

[@TheEngineeringExecutive]

Thanks, glad you like them!

[@majeedsofy2050]

At Point B ( end of 6' to the right), the shear force you calculated is 0 but the diagram shows (150 N)? because shear forces at 0 and 6' distance should be equal and 150 N each, please explain why ?

[@TheEngineeringExecutive]

Apologies for the poor explanation on my behalf, sorry for the confusion. When x = 0 the shear force goes from 0N to 150N. When x = 6 the shear force goes from -150N to 0N. The UDL continues to act on the beam up until x=6, so the magnitude of the shear force increases up until 6m as the span of the UDL increases. Hope this helps

[@zainiqbal-ek7mz]

Hello dear,
Great job. I would like to appreciate your work. But it would be better if you would edit or add another video to explain the corrected Shear force diagram. I am also attaching your reference comment below so for more understanding.
"Apologies for the poor explanation on my behalf, sorry for the confusion. When x = 0 the shear force goes from 0N to 150N. When x = 6 the shear force goes from -150N to 0N. The UDL continues to act on the beam up until x=6, so the magnitude of the shear force increases up until 6m as the span of the UDL increases. Hope this helps"

[@hapless_152]

Switch off the cringey music.

[@TheEngineeringExecutive]

Thank you for the feedback, please see most recent upload