@@swastikbiswas8293 amar mone hoy mathematician er pore second best profession 'bor ke stalk kora'!! kobbui stalk mitti hoyechhish kneo amar dosh? talk ki dekhbu oi lokta tor moton khanikta!
@@swastikbiswas8293 eshob bole amay porte boshano na bessi bessi(*insert one of your 33 koti names*)! aar amio eshob shune porte boshe jai amar ki korun obostha!
Osar X - That's your point of view, for me he nailed it. I am very happy he's a part of our politics, he's brillant and very original it can only be a big plus for our political landscape.
3^3+4^3+5^3=216=225-9=15^2-3^2. Z^3+(Z+1)^3+..+(Z+a)^3=1/4*(Z+a)^2*(Z+a+1)^2 - 1/4*Z^2*(Z-1)^2. Z^3+(Z+1)^3+..+(Z+a)^3=integer^2 - another iinteger^2. Sum of consecutive integers with exponent cube=integer^2-another integer^2. Z^3=integer^2-another integer^2-sum of consecutive integers with exponent cube. If give sum approaching to infinity it seems difficult finding integer Z that satisfies equation Z^n=X^n+Y^n.
3^3=15^2-3^2 -( 4^3+5^3) integer^3=integer^2-integer^2 - sum consecutive integers cube. Give sum consecutive integers cube.approaching to infinity. It seems difficult exists Z,X and Y integers which satisfies Z^n=X^n+Y^n.
" I have discovered a truly marvelous demonstration of this proposition that this margin is too narrow to contain." z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}. when (a) move from 1 to 2,3,4....endless The equation (z^n=x^n +y^n) with z,x,y are the integers which is the cause of an unreasonable.
3^3+4^3=(4*5/2)^2-(3*2/2)^2=100-9=91. 3^3+4^3+5^3=15^2-3^2=225-9=216 3^3=10^2-3^2-4^3 3^3=15^2-3^2-4^3-5^3. 3^3=a^2-3^2-4^3-5^3-6^3-....endless. How exists Z,X and Y integers same time satisfy long winded forms of Fermat when (a) move from 1 to 3,6,10.15....endless.
z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}. when (a) move from 1 to 2,3,4....endless The euqation (z^n=x^n +y^n) mean many other equations with a =1,a=2....endless. If exists a reasonable equation all other equayions are unreasonable
What makes you say that? My friend's mom quit a well paying job to become a parole officer. It's very meaningful work. I imagine it feels great to witness a "screw-up" turn their life around.
Yeah I know. I am a french scientist. I watched plenty of his talks in french. Listening to him speaking in english just makes me smile.
he is so funny and interesting.... great talk
And I also think that he's accent and pronounciation is sooooooo attractive too.
Amazing talk...He clearly expresses everything from his body language
Thank you, Cedric Villani, for speaking in an English I can at last, as an average Parisian, understand ! :-)
Very rare class of good speaker who is mathematician
Which part of the talk did you like so so much, hm? I have a feeling it is Andre Weil's quote, right?
@@riddhimanna8437 bessi korishna stalker bou amar!!
Talk e te na mon diye , prothom comment e mon🤦
@@swastikbiswas8293 amar mone hoy mathematician er pore second best profession 'bor ke stalk kora'!! kobbui stalk mitti hoyechhish kneo amar dosh? talk ki dekhbu oi lokta tor moton khanikta!
@@riddhimanna8437 paguus re!! Tui maths pore Fields ba Abel medal pa. Ami nije toke RUclips e stalk kobbus
@@swastikbiswas8293 eshob bole amay porte boshano na bessi bessi(*insert one of your 33 koti names*)! aar amio eshob shune porte boshe jai amar ki korun obostha!
He is so attractive isn't it? I m a big fan of Cedric Villani from Korea. I think he's just great
Bae Jooyoung Sorry but he fucked up in politics
Osar X - That's your point of view, for me he nailed it. I am very happy he's a part of our politics, he's brillant and very original it can only be a big plus for our political landscape.
Yes! I was searching for the right word...you are right the word is 'attractive'! Also sometimes I laughed so much I had to pause the video lol
I LOVE the final phrase...
I love the "preparatory classes" system
Émerveillement inlassable. Je me delecte. Gratitude. Mo d
domb
3^3+4^3+5^3=216=225-9=15^2-3^2.
Z^3+(Z+1)^3+..+(Z+a)^3=1/4*(Z+a)^2*(Z+a+1)^2 - 1/4*Z^2*(Z-1)^2.
Z^3+(Z+1)^3+..+(Z+a)^3=integer^2 - another iinteger^2.
Sum of consecutive integers with exponent cube=integer^2-another integer^2.
Z^3=integer^2-another integer^2-sum of consecutive integers with exponent cube.
If give sum approaching to infinity it seems difficult finding integer Z that satisfies equation Z^n=X^n+Y^n.
lol youtube should include Latex, i can't read all these comments lol
3^3=15^2-3^2 -( 4^3+5^3)
integer^3=integer^2-integer^2 - sum consecutive integers cube.
Give sum consecutive integers cube.approaching to infinity. It seems difficult exists Z,X and Y integers which satisfies Z^n=X^n+Y^n.
I just love Cedric haha.
" I have discovered a truly marvelous demonstration of this proposition that this margin is too narrow to contain."
z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}.
when (a) move from 1 to 2,3,4....endless
The equation (z^n=x^n +y^n) with z,x,y are the integers
which is the cause of an unreasonable.
3^3+4^3=(4*5/2)^2-(3*2/2)^2=100-9=91.
3^3+4^3+5^3=15^2-3^2=225-9=216
3^3=10^2-3^2-4^3
3^3=15^2-3^2-4^3-5^3.
3^3=a^2-3^2-4^3-5^3-6^3-....endless.
How exists Z,X and Y integers same time satisfy long winded forms of Fermat when (a) move from 1 to 3,6,10.15....endless.
It's cute that you think that understanding ODEs puts you on his level.
It's only when he speaks English. When he's talking in French his voice is a lot more even and (obviously) his pronunciation is better.
excellent. sums up in words thoughts of mine
YOUPI !!! i understand all the words ! merci !
Cédric you speak english very much great
Idk if the video has no audio at all or it is just my phone. Hopefully is gonna get fixed.
Me too! And I thought my phone ... :/
z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}.
when (a) move from 1 to 2,3,4....endless
The euqation (z^n=x^n +y^n) mean many other equations with a =1,a=2....endless.
If exists a reasonable equation all other equayions are unreasonable
There's a problem with the sound in this video, could the uploader please check this problem and fix it? Thanks in advance.
The sound is broken for me..?
I like this guy !!
For sure
Ladies and Gentlemen: The real Sheldon!
Exactly ^^ He's amazing in so many ways.
stop going to the shade!
14. Parole officer?? I can't imagine that being one of the best jobs
What makes you say that? My friend's mom quit a well paying job to become a parole officer. It's very meaningful work. I imagine it feels great to witness a "screw-up" turn their life around.
Princeton has the most Fields Medalists.
+EdD5 not as former students, that's what he was talking aout
For a Frenchman, I agree ;-)
His English isnt bad at all:)
Entertaining talk, although oriented for the nonspecialists.
j'adore sa voix qui part en couille ahah, trop de swag
what a fucking accent putain
@classicmusic05 What about the bow tie? :P
cool guy
Awesome... :|
He sounds like borat when he speaks english^^. Just kidding, this guy is amazing!
Ted's like a weird cult now
Funny accent :D
There's no voice to this video
I find the idea of an idol overrated
He speaks like arabics ROFL
He shouldn't inhale helium ballooms before speeches. I gives a bad impression.
excellent. sums up in words thoughts of mine