Interesting puzzle, where they main move for me was to resolve block 3 through a rather easy "either-or" strategy. The moment one places the 3 at r4c9 in block 6, the ovious impact is to create a 58 pair in r6c7 and r6c9. This pair holds the key to solve block 3. We can see there that the 6 is either in r2c8 or r3c9. With cell r6c7 being a 58, this means that those 6s will either be joined by a 5 OR an 8. knowimg now that we have either a 56 OR 68 pair in r2c8 and r3c9, we can place the 9 in r2c7 and the 4 in r1c7. Having done this, we now know for surethe the 5 must be in r2c8, the 6 in r3c9 and finally the 8 in r3c7. The rest becomes rather simple.
Interesting puzzle, where they main move for me was to resolve block 3 through a rather easy "either-or" strategy. The moment one places the 3 at r4c9 in block 6, the ovious impact is to create a 58 pair in r6c7 and r6c9. This pair holds the key to solve block 3. We can see there that the 6 is either in r2c8 or r3c9. With cell r6c7 being a 58, this means that those 6s will either be joined by a 5 OR an 8. knowimg now that we have either a 56 OR 68 pair in r2c8 and r3c9, we can place the 9 in r2c7 and the 4 in r1c7. Having done this, we now know for surethe the 5 must be in r2c8, the 6 in r3c9 and finally the 8 in r3c7. The rest becomes rather simple.
Placing the 8 at R7C4 would have been a bare minimum before going to pencil marks at 4:17. Also the 7 at R1C2 and the 1 at R2C9.