Abstract Algebra 15.4: Irreducible Polynomials

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  • Опубликовано: 7 фев 2025
  • When working in polynomial rings over an integral domain, polynomials can be either reducible or irreducible. We begin to discuss some of the consequences of this.

Комментарии • 7

  • @Forced2
    @Forced2 5 лет назад +2

    Amazing video.

    • @patrickjones1510
      @patrickjones1510  5 лет назад +2

      Thank you. I created these videos for an online class that I was teaching, and I'm always happy that other people find them useful.

  • @priyamhazarika2744
    @priyamhazarika2744 Год назад

    Thank you 😊, it was helpful and time saving

  • @sangeethag1408
    @sangeethag1408 4 года назад

    Prove that Any polynomial in F[x] can be written in a unique manner as a product of irreducible polynomials in F[x] , can you give a proof for this question?

    • @patrickjones4813
      @patrickjones4813 4 года назад

      The basic idea, which you'll have to add details to, is that suppose f(x) is a polynomial is F[x]. It is either reducible, or irreducible. If it is irreducible, you're done. If it is reducible, then it factors into polynomials of lower degree than the original. Those polynomials are individually either reducible or irreducible. Repeat the original argument. Because the degrees have to be lower each step, this can't be an infinite process.

    • @sangeethag1408
      @sangeethag1408 4 года назад

      @@patrickjones4813 Thank you sir

  • @bobonaqa
    @bobonaqa 2 года назад

    am more confused than before haha... but don't worry, it's probably just me