Abstract Algebra | Irreducible polynomials

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  • Опубликовано: 10 ноя 2024

Комментарии • 9

  • @maxdominate2481
    @maxdominate2481 3 года назад +1

    So glad to find your channel. I just bought an abstract algebra book and was looking through a proof in the section "Irreducible Polynomials Are Maximal Ideals" and thought I'd type that "section title" into RUclips to see what would come up...and here you are. I'm looking forward to watching more of your stuff.

  • @absolutezero6190
    @absolutezero6190 3 года назад

    5:00 is the cleanest edit

  • @maxdickens9280
    @maxdickens9280 Год назад

    You can try to prove it yourself and skip ahead to 8:47 to watch the applications.

  • @rac6040
    @rac6040 4 года назад +3

    Brother you are doing great work..Love from India 🇮🇳🇮🇳🇮🇳

    • @divya296
      @divya296 3 года назад +1

      Me too ,from India. Sir, greetings from India

  • @keyblade134679
    @keyblade134679 Год назад

    Does this proof extend to the multi variable case ?

    • @kevxjn
      @kevxjn 5 месяцев назад

      Technically K[x,y] is isomorphic to (K[x])[y], in the sense that the ring of polyals in two variables x and y, is isomorphic to the one only having one variable but the coefficients into K[x].
      The problem with that is that while K is a field, we know that K[x] is not.
      So that's a nice question.
      But yes, you can prove that every ideal I = (p) where p is an irreducible element inside a Ring is maximal, then the result which involves the quotient R/M, that you can see on the left side of the blackboard, is true without making any assumptions on the qualities R must have.
      So yes, that should estend onto the multi variable case

  • @vindhyachalsingh8217
    @vindhyachalsingh8217 4 года назад

    Tku