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Автовоспроизведение
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By observation one solution is 2Factorise the equation to obtain (a-2)(a^2+2a+5) = 0Solving a^2+2a+5 by the quadratic formula we get -1+i or -1-iSo the solutions are 2, -1+i or -1-i
a³+a=10 -->a(a²+1)=2×5 =2(2²+1)Similar structure of both side means that x=2
A formula from the third degree has to have 3 roots But since we found one root then we can simply it to find the other two
it cant be 1*1*1+10 ?
(a ➖ 2a+1) .
By observation one solution is 2
Factorise the equation to obtain (a-2)(a^2+2a+5) = 0
Solving a^2+2a+5 by the quadratic formula we get -1+i or -1-i
So the solutions are 2, -1+i or -1-i
a³+a=10 -->a(a²+1)=2×5
=2(2²+1)
Similar structure of both side means that x=2
A formula from the third degree has to have 3 roots
But since we found one root then we can simply it to find the other two
it cant be 1*1*1+10 ?
(a ➖ 2a+1) .