But the limit from the left-hand side does indeed exist, it is -4. The fact that (0, -4) is not an element of this function is not relevant. As the limits at zero from the left and right are unequal, discontinuous! Cheers!
@@VladimirHarold did you watch the whole video? I mentioned that for the sake of learning, I went ahead and demonstrated the other half as well. Cheers!
QUIZ QUESTION 👀👇
True or False? For the limit to exist at x=0, f(x) MUST have a defined value for x=0🤔
False. For example f(x)=x^x as no defined point for 0 but the lim as x->0 of x^x=1
Btw how did you comment 3 days ago and the video came out 1 hour ago??
@@AbdulalimAWAD because I’m the author and a ninja hahaha
@@AbdulalimAWAD nice answer, ninja
But the limit from the left-hand side does indeed exist, it is -4. The fact that (0, -4) is not an element of this function is not relevant. As the limits at zero from the left and right are unequal, discontinuous! Cheers!
@@VladimirHarold did you watch the whole video? I mentioned that for the sake of learning, I went ahead and demonstrated the other half as well. Cheers!
Piecewise continous
Very true!