"Yes Lord, YES LORD" 5:53 Love your content brotha! I'm a middle school math teacher and I've been tutoring one of my coworkers in Calculus since they're going back to school to finish their degree. It's been a genuine joy to do math as well as reference your videos! I see your passion and your joy of teaching.
thank you for putting it into language. some people learn visual, some learn pattern, and some of us need to hear the explanation in factual informational ways. this did it for me! thanks!
I have always despised math until now--you make it so easy to understand and actually enjoyable. Thank you for passion and contribution toward millions of people. Keep being amazing!
i looked at it and i thought ok the answer is yes for the first question and no for the rest. I am happy i stayed here to see that lim exist and it is continous. it was really a good example.
So marvelous, I'm enjoying your teaching style. I searched for you in abstract algebra 1and 2 to clear myself in some concepts but to no avail kindly link me up sir
Your passion is what makes you a great teacher! ❤
"Yes Lord, YES LORD" 5:53
Love your content brotha! I'm a middle school math teacher and I've been tutoring one of my coworkers in Calculus since they're going back to school to finish their degree. It's been a genuine joy to do math as well as reference your videos! I see your passion and your joy of teaching.
Thank you!
thank you for putting it into language. some people learn visual, some learn pattern, and some of us need to hear the explanation in factual informational ways. this did it for me! thanks!
I have always despised math until now--you make it so easy to understand and actually enjoyable. Thank you for passion and contribution toward millions of people. Keep being amazing!
Great to hear!
Man, the passion is admirable.
Always very clear explanations. You come up with strategies I would never have thought of in your videos.
At that point, it's continuous but not differentiable.
Correct! Too kinky to differentiate.
Excellent explanation 👌!
Keep it up.
I love the energy you bring in your videos ❤
Amazing teacher. Clear, simple and very well explained. Thank you!
You never disappoint prime!
Sir, I'm from India,,
Your teaching style is just fabulous ❤
Thank you sir, you makes me remember math, a new student follows your excellent explaining.
Thank you, sir. I like that even if it looks weird, it exists.
i looked at it and i thought ok the answer is yes for the first question and no for the rest. I am happy i stayed here to see that lim exist and it is continous. it was really a good example.
You're an amazing Teacher.I love your passion ❤
super fun video! made me excited to continue learning calculus. keep up the good work.
Precise Good Simple Explanation.👍
you're the man and no two ways above that..!
they should hire you as my lecturer.................SUBSCRIBED
Thank you sir! Love your energy while teaching!
Wonderful sir.
Love the passion
Detailed explanation.
Yes lord!
I loved your explanation!!
Thanks!
You are welcome!
Thanks for this video Mr...I did not understand during my calculus 1 classes. But now you paved the way now I understand 👍 👌👌
Very well explained!
BRO i like how u teach math! makes me wanna learn math without the school requiring me to learn it
Continuity is sufficient condition for integration and necessary condition for differentiation
Three times yes
Haha! I will have to do a video on " Necessary and Sufficient." Thanks for all the tips.
youre a great teacher , appreciate the videos so much🙏
Very clear explanation..
So marvelous, I'm enjoying your teaching style. I searched for you in abstract algebra 1and 2 to clear myself in some concepts but to no avail kindly link me up sir
You're so underrated thank you
Thank you dear teacher
Beautiful 💐
Hi man all your video are inspirational I am encouraged to go far with maths
I really really likes yous pattern of learning, your learning is step-by-step and you becomes the hard topic to easy.❤😊👍🪷 continue you passion......🎉
But not differentiable at x=2 since derivative at x=2 of x^2+1=2x=2(2)=4 and derivative of 7-x=-1 at x=2 and 4,-1 are not equal.
Thanks first time watching Your video
Well explained 🎉🎉❤
You are such a life saver
Damn I am so angry that l am only discovering your videos now after failing three tests.
Better late than never
Wonderful so nice
Outstanding
🦸
Thanks very much sir u really enlightened me on this ❤
Great way of teaching
Glad you think so!
Is it correct to put 2, not 1 in the calculation of LHL. The statement doesn't say that we can take value equal to 2 for LH
Amazing...
Hey man! We love maths & we love you!❤
You have very good handwriting
You have wisdom
NIce expalnation!! Keep it up
Fantastic one❤
thanks a lot will smith😊
Thanks man, that helped ❤
Nice handwriting!
lad you are crazy.......... thanks man got it
Well understood
Nice teaching😘😘
amazing teacher
Thank you! 😃
As a Physicist I'd say, a function is continuous if I can draw the graph without lifting my pen😂
What a misleading physicist
You teach really nice but ill suggest you give copius example to strengthen what we already know 😊
....my cadid advise😅
Nice lecutes always...
شكراَ
Now 4th Question :> Is this function differentiable at x=2?
thank you so much
Please help me find inverse of x+radical of x
Do I have to do the same for 7-x to prove that the entire function is continuous?
Had to subscribe.
Great Video!
Evaluate x^3-8/x^2-4
Lim x is 2.please how do i solve this
Factor top and bottom
Made it easy 👏👏👏👏
Thanks
Thanks Sir 🙏
Fun fact:
If you
a) follow the convention that 0^0 = 1
and
b) hate either piecewise functions or yourself
you can create this monstrosity:
Θ(x) = 0^(|x| - x)
α(x) = 0^(|x| - x)
σ(x) = Θ(x)-α(x)
ι(x, n, s) = |s|(Θ(s)Θ(x-n)+α(s)α(x-n)) + cos(sπ/2)cos(σ(x-n)π/2)
f(x) = (x^2+1)ι(x, 2, 1) + (7-x)(ι(x, 2, -1)-ι(x, 2, 0))
LaTeX for desmos copy-pasting:
\Theta\left(x
ight)=0^{\left|x
ight|-x}\
\alpha\left(x
ight)=0^{\left|x
ight|+x}
\sigma\left(x
ight)=\Theta\left(x
ight)-\alpha\left(x
ight)
\iota\left(x,\ n,\ s
ight)=\left|s
ight|\left(\Theta\left(s
ight)\Theta\left(x-n
ight)+\alpha\left(s
ight)\alpha\left(x-n
ight)
ight)+\left(\cos\left(s\frac{\pi}{2}
ight)
ight)\left(\cos\left(\sigma\left(x-n
ight)\frac{\pi}{2}
ight)
ight)
f\left(x
ight)=\left(x^{2}+1
ight)\iota\left(x,\ 2,\ 1
ight)+\left(7-x
ight)\left(\iota\left(x,\ 2,\ -1
ight)-\iota\left(x,\ 2,\ 0
ight)
ight)
It's actually not that complicated.
Θ(x) = 1 if x >= 0 else 0
α(x) = 1 if x
I'm going to tell my parents that I've learnt something 😅😅
You must find R H limt amd LH limt first.their value must be equal.
Yes Lord ❤️🔥 thank you sir 🫂
If limt exist then function f(x) exit.
Thank you❤
😮 "prime newtons" indeed
Yes lord 🙌🙌🙌
Dope ☢
Yes lord! 😂🙌🏾
like this guy
can you please eplain that of 7-x for me please
If X>0
i finally understand this shit😃😃
made so easy and doable! please be my lecturer🙃🥲