Pls take 700 or 750 circular Mills as standard. Taking 1000 circular mills would result in very bulky core which results in more core losses. 2 amp/mm2 is useful in very large transformers. For best compromise, use between 2.5-3.5 amp/ sq mm. Flux density is taken as 1T for normal use. For continuous use 24 Hrs, you may take 0.8T. Test the efficiency of the transformer, then mark it's current at maximum efficiency. Beyond that current, losses increase and correspondingly more heat is generated.
Namskar mai ek high school teacher hu, electronics hobbies hu, abhi transformer banane ki koshish kr raha hu, mere bhi pahane ke across ye CIRCULAR MILLS aaya lekin ye 1000 circular mills aur 750 circular mills kya hote hai . Dhananjay Dudhe, chandrapur , maharashtra. 966591 8558
@@madhuridudhe7163 aap circular mills ke chakkar me mat pado. Jo practically industry me use hota hai, wahi use karo. 3.5 ampere per sq mm ka current carrying capacity rakho. Turns per volt = 7.5/(area of core in square inch) Ya 48/(area in sq CM). Bahut badiya transformer banega. Aap decide kar lo ki kitne VA ka transformer banana chahte ho. Baaki saara method same rahega.
can i ask plss... where did number 42 came from to get the window area? and are the sizing of core is an assumption? or how did you say that possible core is 3 and 4 .. plsss i want an answer i really appreciate it thank you
42 is the calculated number of the same frequency and same iron flux density and copper current density.. We have window area = 1.69 sq. " × 35% margin = .5195 Now 1.69 - .5195 = 1.17 sq." Primary 24 SWG diameter in inches = .022 Secondary 13 SWG diameter in inches = .092 PRIMARY TURN : 1024 × .022× .022 = .4956 SECONDARY TURN: 57 × .092 × .092 = .4824 Now .4956 + .4824 = .9780 sq. " (Which is our requirement) And what we have is 1.17 sq. " I hope it will help you.
23 SWG = .292 mm^ 24 SWG = .245 mm^ 25 SWG = .2027 mm^ These are the actual wire size .2424 mm^ Exact matches are not available Hope it will help you...Thank you
![[430] How To Calculate Ferrite Core Maximum Power Handling to Design High Frequency Transformer](http://i.ytimg.com/vi/Fk2OeYY_poo/mqdefault.jpg)
![[430] How To Calculate Ferrite Core Maximum Power Handling to Design High Frequency Transformer](/img/tr.png)
Number one information
sir aap welding transformer ke core ko kaise assemble karte hai ispar ek vdo bana dijiye
Pls take 700 or 750 circular Mills as standard. Taking 1000 circular mills would result in very bulky core which results in more core losses. 2 amp/mm2 is useful in very large transformers.
For best compromise, use between 2.5-3.5 amp/ sq mm. Flux density is taken as 1T for normal use. For continuous use 24 Hrs, you may take 0.8T.
Test the efficiency of the transformer, then mark it's current at maximum efficiency. Beyond that current, losses increase and correspondingly more heat is generated.
Namskar mai ek high school teacher hu, electronics hobbies hu, abhi transformer banane ki koshish kr raha hu, mere bhi pahane ke across ye CIRCULAR MILLS aaya lekin ye 1000 circular mills aur 750 circular mills kya hote hai . Dhananjay Dudhe, chandrapur , maharashtra. 966591 8558
@@madhuridudhe7163 aap circular mills ke chakkar me mat pado. Jo practically industry me use hota hai, wahi use karo.
3.5 ampere per sq mm ka current carrying capacity rakho.
Turns per volt = 7.5/(area of core in square inch)
Ya 48/(area in sq CM).
Bahut badiya transformer banega.
Aap decide kar lo ki kitne VA ka transformer banana chahte ho.
Baaki saara method same rahega.
Nice
Sir
4 inch bobin me 12no coil se stepdown stabiliser data chahiye
super sir real and perfect calculation
sir, how to caliculate bobin winding area.let me know the formula please.
65000 e Kay se aya please share details
Sir how to calculate the winding area in transformer
Sir it is a long calculation
I will try to explain this in a video as soon as possible
and how to design three phase transformer using the same calculation plz need video in detail
and also need to know how to find winding area?
C6 core me transformer winding data nikalne ka formula bataye
Sir buck boost transformer ka data kasy calculate karty hai
42 Kahan se aaya ye please bataiye.
Good video 👏
Sir ac24v @2.1amps calculation is not matching please help me .
I am using the core T-31/ 38mm size
Sir aap kitne square mm ki wire dhund rhe hai wo chart se match kar lijiye
42 Kahan se Aaya 42 calculation karein plz🙏🙏🙏
Winding area ko lekar problem hai please solve this.
106.66/42 . ye 42 kaha se aaya sir ji
Copper dencity how can find
Awaj bhut slow h video me
بارك الله فيك ممكن رقمك واتس
Sir ji 42 Kahan se Aaya Uski formula se solve Karke dikhayein🙏🙏🙏
Sir jee iska pdf download link do na.
3pase transfermer ka tarn
300 empier ka welding Transformer ka data dijiye
mithlesh sharma .
can i ask plss... where did number 42 came from to get the window area? and are the sizing of core is an assumption? or how did you say that possible core is 3 and 4 .. plsss i want an answer i really appreciate it thank you
42 is the calculated number of the same frequency and same iron flux density and copper current density..
We have window area =
1.69 sq. " × 35% margin = .5195
Now 1.69 - .5195 = 1.17 sq."
Primary 24 SWG diameter in inches = .022
Secondary 13 SWG diameter in inches = .092
PRIMARY TURN :
1024 × .022× .022 = .4956
SECONDARY TURN:
57 × .092 × .092 = .4824
Now .4956 + .4824 = .9780 sq. "
(Which is our requirement)
And what we have is 1.17 sq. "
I hope it will help you.
Sir 24 Kahan se Aaya Uski nikalkar dikhao formula do
24 kahan likha hai
How to calculate Flux density? Please help me sir
video ki Awaaz mein bass bahut jyada hai kuch bhi samajh mein nahin a raha hai
.2424 mm² =24 swg the wire chat is not matching
23 SWG = .292 mm^
24 SWG = .245 mm^
25 SWG = .2027 mm^
These are the actual wire size
.2424 mm^
Exact matches are not available
Hope it will help you...Thank you
Aap pura explain nhi kiya..thik se