Energy of a charge distribution III - energy density in terms of electric field

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  • Опубликовано: 12 ноя 2024

Комментарии • 3

  • @venkateshamav8602
    @venkateshamav8602 5 лет назад +1

    At 7:05 why is the second term not going to zero E^2 has 1/ r^4 and dV has r^3 so it comes to 1/r at infinity this also should go to zero right ??

    • @kuldipkunghadkar6802
      @kuldipkunghadkar6802 5 лет назад

      Exactly... I doesn't get the clear cut explaination yet. If u did plz inform me

    • @jaiprakashshukla9911
      @jaiprakashshukla9911 4 года назад

      @@kuldipkunghadkar6802 Well no one is explaining it. For the surface integral, the value of r is constant. So for r equals infinity the value of both V and E is zero. But for the volume, it varies from 0 to r. So there are some values of r for which the value of E is definitely not zero even though r is very large.