Leah in case no one has told you lately but you are an amazing teacher! Thank you so much for making these videos they are a grade saver, time saver, life saver, and mental sanity saver!
I would seriously be so screwed without your videos Leah. I don't even know why I bother going to lecture anymore because I just come home and learn it all from you anyways xD
A minor correction: in time 3:56. The formal charge of the black oxygen is calculate by should minus has “as you taught us” oxygen should has a valence electrons of 6 minus 7 which it has = -1 and not the opposite since 7-6 doesn't equal to -1 Otherwise, YOUR videos are amazing over all. Thanks a lot :D
OMG LEAH!! "think of the negative charge as a burden" this sole sentence made me totally understand what was going on with the resonance effect. I understood it since you said it first. You are the best honestly. ❤❤❤❤ I'm gonna ace the exam because of you.
Thank you for the videos. I’m getting much much help from you! Btw I just have q question. 10:45 On the 4 th resonance molecule, Why the black electrons stop moving to the right side and the red electrons going back to the oxygen? Why it doesn’t have 5 resonance?
Great question. Doing so recreates what we see in Resonance Structure #1, where we have a negatively charged oxygen with alternating pi bonds throughout the ring. The pi bonds will simply be shifted one space over from where they started originally. Most professors will consider this the same molecule as #1. But drawing it does not necessarily make you wrong either!
i have a question! at 9:32, on the second resonance structure(the one on the right). why does the electron (on red color) over the carbon stop moving? why they can not jump to the next bond and make a double bond with the next carbon atom? , thank you for your time
One of the most important rules to remember in resonance is to never ever ever resonate onto an sp3 atom due to the atom already having a complete octet
In most cases, this is true. For maximum resonance, we are always looking for a conjugated system of pi electrons. Pi electrons are delocalized and able to move freely IF there are empty neighboring orbitals for them to move INTO. For more on this topic, watch my resonance series at leah4sci.com/resonance
It depends. Conjugate bases could be either strong or weak. A conjugate base is what is formed when an acid donates its proton in solution. It is the 'pair' to the previous acid.
For which example in the video? Ideally, we look at all 5 of the CARIO factors to make a complete assessment of acid/base strength. But if the big difference between the two structures is that one has more resonance, then we know that is what we should focus on.
What I'm not understanding is how the more stable conjugate base=a stronger acid. If the conjugate base is more stable, it's technically stronger, so shouldn't the acid be weaker?
In these examples we're deprotonating not protonating. In protonation you add H+/H3O+. In deprotonation you remove H+ or add OH-. In protonation a strong conjugate base gives a weak acid and in deprotonation a strong conjugate base gives a strong acid
Sorry this video wasn't what you were looking for, but i have many others. You can match what you are studying to my resources here: leah4sci.com/syllabus
Leah in case no one has told you lately but you are an amazing teacher! Thank you so much for making these videos they are a grade saver, time saver, life saver, and mental sanity saver!
Wow, you are so welcome! Always happy to help!
This whole series is seriously gonna save my grade! You're great at explaining these concepts, thank you!
You're so welcome, happy to help!
I would seriously be so screwed without your videos Leah. I don't even know why I bother going to lecture anymore because I just come home and learn it all from you anyways xD
Wow, so glad I was able to help so much!
A minor correction: in time 3:56. The formal charge of the black oxygen is calculate by should minus has “as you taught us” oxygen should has a valence electrons of 6 minus 7 which it has = -1 and not the opposite since 7-6 doesn't equal to -1
Otherwise, YOUR videos are amazing over all. Thanks a lot :D
you are right! I said/wrote them backwards!!
Your channel is so underrated. This material is fantastic for organic chemistry students! Thank you so much!
Wow, thank you! Glad you like it!
OMG LEAH!! "think of the negative charge as a burden" this sole sentence made me totally understand what was going on with the resonance effect. I understood it since you said it first. You are the best honestly. ❤❤❤❤ I'm gonna ace the exam because of you.
YAY! I'm so glad to hear that really helped it click for you. Fingers crossed for your upcoming exam!
Just started this in Organic chem and was confused, but now I'm total fine with this :D merci beaucoup :)
Happy to help!
Thank you so much for such a great explanation......love you....❤❤
You are so welcome!
Thank you Ma'am ! Your lectures are very helpful!
You're very welcome!
I m feeling so happy after dis... Thank u so much... Ur videos are really grade savers...keep it up
You're so welcome, happy to help!
Thank you for the videos. I’m getting much much help from you! Btw I just have q question.
10:45 On the 4 th resonance molecule, Why the black electrons stop moving to the right side and the red electrons going back to the oxygen? Why it doesn’t have 5 resonance?
Great question. Doing so recreates what we see in Resonance Structure #1, where we have a negatively charged oxygen with alternating pi bonds throughout the ring. The pi bonds will simply be shifted one space over from where they started originally. Most professors will consider this the same molecule as #1. But drawing it does not necessarily make you wrong either!
I. LOVE. YOU.
Me tooo😘😘
Thanks!
i have a question! at 9:32, on the second resonance structure(the one on the right). why does the electron (on red color) over the carbon stop moving? why they can not jump to the next bond and make a double bond with the next carbon atom? , thank you for your time
One of the most important rules to remember in resonance is to never ever ever resonate onto an sp3 atom due to the atom already having a complete octet
You explain this so clearly! ❤ 😊
Glad it was helpful!
Thank you! When comparing two molecules, would resonance be given more priority over inductive effect?
Resonance helps reduce the burden of charge where induction kinda/sorta helps, resonance wins
Great explanation. Couldn't wait for the next two videos to be uploaded.
glad you liked it!
Thank you! Seriously so helpful ❤
You're so welcome!
My professor didn't even explain it ias well as you! Thank you so much!
You're very welcome!
these videos are so helpful. Thank you!
You're very welcome, happy to help!
so is it safe to assume more pi bonds will probably result in more resonance structures?
\
In most cases, this is true. For maximum resonance, we are always looking for a conjugated system of pi electrons. Pi electrons are delocalized and able to move freely IF there are empty neighboring orbitals for them to move INTO. For more on this topic, watch my resonance series at leah4sci.com/resonance
Super mam.......thanks for this lovely ..Site...
You're so welcome!
does more stable in terms of conjugate base refer to weak base?
It depends. Conjugate bases could be either strong or weak. A conjugate base is what is formed when an acid donates its proton in solution. It is the 'pair' to the previous acid.
how do i know i have to look at the resonance structures? n not any of the other cario
For which example in the video? Ideally, we look at all 5 of the CARIO factors to make a complete assessment of acid/base strength. But if the big difference between the two structures is that one has more resonance, then we know that is what we should focus on.
I just wanna say thankyou jeeeeeZzzz ur a HEROOOOINEE
You're very welcome!
What I'm not understanding is how the more stable conjugate base=a stronger acid. If the conjugate base is more stable, it's technically stronger, so shouldn't the acid be weaker?
Naana Kena me neither. I saw in others video saying that strong base became weak conj. acid
In these examples we're deprotonating not protonating. In protonation you add H+/H3O+. In deprotonation you remove H+ or add OH-. In protonation a strong conjugate base gives a weak acid and in deprotonation a strong conjugate base gives a strong acid
Happy = Stable = Unreactive!
A molecule only reacts because it is unstable and looking to find a more stable situation.
I didn't get you book even after clicking on the link🤔
I'm so sorry to hear that! Please contact me through my website leah4sci.com/contact/ and my assistant or I will help you.
you are great at teaching! thank you
You're welcome, happy to help!
Thanks a lot, I really got it.
You are welcome
What if we have two donating groups in one benzene ring
Two is better than one, the ring will have even more negativity to stabilize potential positive charges
Very good! Love it!
Thanks!
Last example has 5 resonance contributors
thanks
after the 4th resonance how do u draw the 5th
Great Video, Thank You
You are very welcome
Have you ever made a bad video? cause I haven't found one yet. Thx for knowing how to teach because my poor professor never learned. :-)
Aww thanks so much for your kind words and you're so welcome!
super. thanks for video
You're very welcome!
thank you so so so much
You're welcome. :)
god bless you💗
Thank you so much
tysm!
You're very welcome!
thank you ♥♥
You're welcome!
awesome !
Thanks!
Good
Thanks
great
thanks
not helpful for what i needed but thanks
Sorry this video wasn't what you were looking for, but i have many others. You can match what you are studying to my resources here: leah4sci.com/syllabus
❤️❤️❤️
Glad you like it!
I love you
Me or my videos? ;)
✅✅
thanks!