Thanks for the amazing video, One thing I want to ask about the graph, how to draw the graph at different pressure and temperature to see the dynamic behavior of the mixture (ammonia-water).
1. before temp t, There are no vapours ? Even at room temperature water got some vapour pressure..... Can anyone clarify? 2. 3:21 Xa and Ya both decreses on increasing temperature.... as compared to their previous state. How it is possible that mole fraction of A is decreasing in vapour as well as liquid state.... ?
1.It is assumed that there are almost no vapous of water below t temperature assuming ideal behaviour 2.As temperature is increasing and A is more volatile than B so mole fraction of A is decreasing in liquid phase... And when the vapours of B begins to form the mole fraction of B begins to rise steadily......
This is the best video in the whole internet
Amazing explanation sir.
Awesome way to demonstrate.... thank you sir
I have been days trying to understand this by videos and web pages, but I couldnt understand It untill I saw this video
Great dude
Explained 1000 times better than my class teacher
The best video,no doubt at all
thanks man i had trobule understanding with the books you make it clear for me
Thank you very much for making It, you are a good person
Well done sir keep going on
Nicely explained thanks!
thanks a lot ... you are unique and best
Thanks, well explained👏
Amazing explaining completely understand it but kindly make more videos like on pressure temperature diagrams of hydrogen systems..
Thanks
Thanks for the amazing video, One thing I want to ask about the graph, how to draw the graph at different pressure and temperature to see the dynamic behavior of the mixture (ammonia-water).
Great Explanation!!
Do more videos on solutions phase diagram.
Thank you sir
It is an awesome video
Thank you very much!!!
Thanks!
Thanks alot
Thank you!
Superb.. Please add subtittle..
Good
Plzzz upload combined of vapour pressure and mole fraction
1. before temp t, There are no vapours ? Even at room temperature water got some vapour pressure.....
Can anyone clarify?
2. 3:21 Xa and Ya both decreses on increasing temperature.... as compared to their previous state. How it is possible that mole fraction of A is decreasing in vapour as well as liquid state.... ?
1.It is assumed that there are almost no vapous of water below t temperature assuming ideal behaviour
2.As temperature is increasing and A is more volatile than B so mole fraction of A is decreasing in liquid phase...
And when the vapours of B begins to form the mole fraction of B begins to rise steadily......