Hello Duane, good talking to you again! I'm currently making a portfolio of sketches so that I can bring them to a few job interviews. I'm currently working on a transition fitting that is sloping on 4 sides. I even drew out a top view of it, and I've laid it out the exact same way you've done this way with formulas. I know I'm doing it correctly. It's 5 inches in fitting length slip and drive both ends, so I know the fitting length in the formula is the working length which is 4 inches. So when i do fitting working length squared plus slope square then that number square root its just not working out. The pittsburgh lengths end up being too long for the quarted inch bends on the left and right cheeks and yes i am adding another 1 inch to the number i get out of the formula for the finished length so i dont understand why its not working. I know the slopes for all 4 sides, but it's just not working out for some reason. The sizes are not fitting correctly when I put them together. Is there anyway you could help me with this if I send u an email? I'm getting so frustrated
My guess would be,,,,first we must be able to comprehend the terms used in our trade, for ex: top view, bottom view and side views,,,,That’s just my opinion.
@@ebbychavez765 Yes, this is used on all sides of a transitional fitting. The formula is basically the Pythagorean formula A square + B square = C Square. Let’s say A is the length of the fitting and B is the amount of change, in order to find the length of C you will need to add A square and B square then square root that number,,,,,this is the true length of the hypotenuse or in this case the true length of that one side of your fitting. If you want to see this formula in action you might want to check out my video sheet metal reducer/transition @ 6:25
thanks man!
Hello Duane, good talking to you again! I'm currently making a portfolio of sketches so that I can bring them to a few job interviews. I'm currently working on a transition fitting that is sloping on 4 sides. I even drew out a top view of it, and I've laid it out the exact same way you've done this way with formulas. I know I'm doing it correctly. It's 5 inches in fitting length slip and drive both ends, so I know the fitting length in the formula is the working length which is 4 inches. So when i do fitting working length squared plus slope square then that number square root its just not working out. The pittsburgh lengths end up being too long for the quarted inch bends on the left and right cheeks and yes i am adding another 1 inch to the number i get out of the formula for the finished length so i dont understand why its not working. I know the slopes for all 4 sides, but it's just not working out for some reason. The sizes are not fitting correctly when I put them together. Is there anyway you could help me with this if I send u an email? I'm getting so frustrated
@@sheetmetalwork awesome man thank u I will do!
What’s the good starting point if any?from field measurement to the shop table?
My guess would be,,,,first we must be able to comprehend the terms used in our trade, for ex: top view, bottom view and side views,,,,That’s just my opinion.
How do I type that formula on a iPhone calculator and does it work for any plenum from 1 sided to 4 sided?
@@ebbychavez765 Yes, this is used on all sides of a transitional fitting. The formula is basically the Pythagorean formula A square + B square = C Square. Let’s say A is the length of the fitting and B is the amount of change, in order to find the length of C you will need to add A square and B square then square root that number,,,,,this is the true length of the hypotenuse or in this case the true length of that one side of your fitting. If you want to see this formula in action you might want to check out my video sheet metal reducer/transition @ 6:25