Anyhow the concept is quite clear and you can solve such types of problems. Good to see that you are calculating each and everything to clear you and I am waiting for your answer....thank you
Ok so centroid of triangle from vertex is equal to 2/3 x H = 36 mm while centroidal axial for whole figure is 30 and difference is d =6 mm which is right. I hope it is clear now so make that correction. This is the correct way.
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In I-2 d (according to the parallel axis theorem) is 6 not 3 !
Why? Plz explain
Anyhow the concept is quite clear and you can solve such types of problems. Good to see that you are calculating each and everything to clear you and I am waiting for your answer....thank you
@@engradnanrasheedmechanical Sir 'd' for triangle is (36-30) .... y bar for triangle is 36 .. Please correct me if I am wrong
Ok so centroid of triangle from vertex is equal to 2/3 x H = 36 mm while centroidal axial for whole figure is 30 and difference is d =6 mm which is right. I hope it is clear now so make that correction. This is the correct way.
You are right ....Good Job....
Sir If the value of M is different then what we do?
I didnt get you but different value will be placed...
@@engradnanrasheedmechanical I am your student of section M
@@engradnanrasheedmechanical Thanks sir !
Yes I know dear....
Why we take 30 for ý botom
We have calculated the location of neutral axis of the body keeping the bottom as reference and that comes out to be 30 from.bottom.