Solving ALL the integrals from the 2024 MIT integration bee finals

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  • Опубликовано: 30 сен 2024
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Комментарии • 107

  • @maths_505
    @maths_505  8 месяцев назад +31

    20:45 there should be a negative sign for the last integral so the last cot term is negative. Here are the timestamps:
    0:10 Problem 1
    6:09 Problem 2
    17:37 Problem 3
    21:47 Problem 4
    26:55 Problem 5
    Thanks and enjoy the video.

    • @joelchristophr3741
      @joelchristophr3741 8 месяцев назад +1

      Master can you make a video soon for the proof of anti-beta function which you wrote int 0to∞ x^s-1 / 1-x^k = pi/k cot s pi/k
      Your fan request please 🙌🙏

    • @tomasstride9590
      @tomasstride9590 8 месяцев назад +1

      I did not get the same answer as you for the fourth integral. I supposed I must be making a mistake. To check I by put the integral into Wolfram Alpha ( no easy matter). To my surprise it gave an answer 0f 2.39027. This is virtually the same as the answer I got which was 4pi sin(3pi/5)/5. I did the problem starting in the same way as you . But them I observed that the integrand has a removeable singularity at 1 and two simple poles in the upper half plane. I closed the contour appropriated and then just used easy methods to find the residues. May be you can comment.

    • @maths_505
      @maths_505  8 месяцев назад +2

      @@tomasstride9590 I forgot the negative sign for the 4th integral so that mistake is on me. I agree with the contour integration method that you've employed and if you're answer isn't the same then it must have been some minor error.

    • @joelchristophr3741
      @joelchristophr3741 8 месяцев назад +2

      ​@@maths_505I accept there is a missing negative sign.. but I want proof for that equation master.. that [ pi / k cot ( pi s / k) ] none of the RUclips videos have proof for it... hoping you'll make a video soon for that proof 🙏🙌

    • @maths_505
      @maths_505  8 месяцев назад +3

      @@joelchristophr3741 bro could you please stop with the master thing 😂 I mean it's a cool joke but I just like being called bro alot better 😂. I'll make a write up for it on my Instagram. See you in a few hours with a new video.

  • @lwany6713
    @lwany6713 8 месяцев назад +145

    "ima have to differentiate the fuck out of this thing" is a hell of a line.

  • @TanmaY_TalK
    @TanmaY_TalK 8 месяцев назад +119

    Happy integrating guys I need to learn physics for my exams

    • @Physicsbbc
      @Physicsbbc 8 месяцев назад +8

      good luck....physics>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>everything else(literally)

    • @pointblank8216
      @pointblank8216 5 месяцев назад +3

      How did it go? physics sucks ass

    • @artophile7777
      @artophile7777 Месяц назад

      ​@@Physicsbbc Damn you got slandered

    • @zyklos229
      @zyklos229 28 дней назад

      Imagine this IS your exam 😵‍💫

  • @elmaminsk5411
    @elmaminsk5411 7 месяцев назад +28

    I have better explanation of 5-th integral solution:
    Basically we just need to switch to binary number base, where 1/2 = 0.1, 1/4 = 0.01 and so on. It's very convenient for this problem because multiplying by powers of 2 just shifts all the digits in decimal part. As you mentioned in video, the function takes value = 1 for each x starts with 0.00..., for value = 1/2 x should start from 0.100...
    And it's easy to formulate the general rule: the value of integrand equals 1/2^n iff (n+1)-th and (n+2)-th digits of decimal part of x are zeroes, and no two consecutive zeroes appear in positions earlier. This is quite standard combinatorics problem, and we come that count of combinations of n binary digits with no two consecutive zeroes equals to Fib[n+1]. We should also take into account that n-th digit must be 1, and the rest of calculations are basically the same you did in the video, and the answer is sum of Fib[n] / 4^n for all natural n values.
    Also in final calculations of given series instead of Binet's formula you could simply use Fibonacci's generating function by substituting 1/4 there. I guess MIT contest finalists must use this formula which helped them to solve this problem in a fast manner)

  • @guilhermegoncalves110
    @guilhermegoncalves110 8 месяцев назад +14

    7:00 - What could be better than watching an integration being done where the person in charge of the solution has a sense of humor. Mathematics skills combined with showmanship.

  • @Trimza42
    @Trimza42 8 месяцев назад +10

    A ThreeBuleOneBrown video on your methodology for that horrendous last integral would be exquisite! I've stared at it for hours and spent 8 sides of A4 on it, whatever trick you need to know to do that in under 5 minutes must be pure madness.
    I think problems with floors of 2^n can be done with some binary representation wizardry on the variable 2^n x. Then integrals like that should turn into a sum of fractions, but computer science never interested me lmao. I'll stick with multivariable calculus and differential geometry that's a breeze compared to that integral.
    Serious respect to @maths-505 as always, awesome video!

  • @AB-nu5we
    @AB-nu5we 8 месяцев назад +13

    I'd vote for the tie-breaker integrals. Nicely done.

  • @lyonkang7402
    @lyonkang7402 7 месяцев назад +4

    I’ve only taken like half of calc 1 but I’m having a good time

  • @wilsonlu168
    @wilsonlu168 6 месяцев назад +2

    4:10 there should be a e^(x/2) before 4(......)^(-1/3) right?

    • @juanpabloguitarra
      @juanpabloguitarra 5 месяцев назад

      That's what I thought too! If not, then it doesn't make sense to think about it as the derivative of a product

  • @abdulmajidnematallah3357
    @abdulmajidnematallah3357 5 месяцев назад +1

    This isn’t even calculus anymore

  • @Xrtd62
    @Xrtd62 7 месяцев назад +5

    Where did the exponential go at 5:21 ?

    • @Nubb08
      @Nubb08 7 месяцев назад +1

      I think he just forgot to put the exponential because if you expand out the numerator of the yellow integral, e^x/2 should have been distributed to the 4 as well. So it’s 4e^x/2.

  • @aryaghahremani9304
    @aryaghahremani9304 7 месяцев назад +3

    25:44
    I really love this solution but for the equation u^3-3u-2=0, the root u=-1 also works, why choose 2 over that?
    also I guess a broader question, what do you do in these situations generally where the substitution is not a bijection
    thanks

    • @maths_505
      @maths_505  7 месяцев назад +2

      The integrand is non negative on the interval of integration.

  • @MrWael1970
    @MrWael1970 8 месяцев назад +4

    Useful problems and fascinating solutions. Thank you.

  • @owy-ej6bo
    @owy-ej6bo 7 месяцев назад +4

    the last integrate,suppose the total value is T,then integrating from 0 to 1/4 is 1/4,integrating from 1/4 to 1/2 is T/16,integrating from 1/2 to 1 is T/4,then you can solve T is 4/11

    • @murthys743
      @murthys743 7 месяцев назад +1

      i ddnt get you, could you explain more briefly

    • @vancedforU
      @vancedforU 5 часов назад

      Wow, this is actually so elegant

  • @TMH2007
    @TMH2007 8 месяцев назад +10

    THE MOST AWAITED VIDEO, I kept patience and didnt watch any other solutions coz i only needed your solutions!

  • @taterpun6211
    @taterpun6211 8 месяцев назад +1

    The fibonacci series at the end can also be derived using its recursion relation properties.
    If f(x) = Σ(k=0,∞)F(k)x^x
    (1-x-x^2)f(x) = Σ(k=0,∞)F(k)x^k(1-x-x^2)
    = Σ(k=0,∞)F(k)x^k - Σ(k=1,∞)F(k-1)x^k - Σ(k=2,∞)F(k-2)x^k
    = x +Σ(k=2,∞)(F(k) - F(k-1) - F(k-2))x^k
    = x
    f(x) = x/(1-x-x^2)

  • @nicolastorres147
    @nicolastorres147 8 месяцев назад +2

    21:48 I've actually wanted to use Cardano for an integral since a long time ago 🤣

  • @miniprime1
    @miniprime1 7 месяцев назад +1

    Most simple solution of problem 4 I found:
    Let f(x) be integrand. Then indefinite integral of f(x) is F(x) = 2(xf(x) + log|f(x)|)/3 + C. Therefore, I = F(1) - F(-1/3) = 14/9 + 2log(2)/3.

  • @nnnam3
    @nnnam3 6 месяцев назад +1

    I am curious what is the drawing software? That looks very clean!

  • @DONIVISIONHD
    @DONIVISIONHD 7 месяцев назад +1

    easiest calc 2 exam

  • @b4lrogd997
    @b4lrogd997 8 месяцев назад +4

    Im gonna enjoy it

  • @archismanrudra9336
    @archismanrudra9336 8 месяцев назад +3

    In the 4th problem with cardano, when you are finding limits, for x = +1, the equation is u^3 - 3u -2 = 0, for which one solution is u = 2, but another solution is u = -1. May be expand on this a bit? may be by going to the original equation for u in terms of x

    • @shivanshnigam4015
      @shivanshnigam4015 8 месяцев назад +3

      u cant be negative for the given limits

    • @maths_505
      @maths_505  8 месяцев назад +4

      The integrand can't be negative given the interval of integration. Oh someone's already answered 😂 cool.

    • @nicolastorres147
      @nicolastorres147 8 месяцев назад

      ​@@maths_505is it possible to have the method fail cause of multiple valid solutions? 🤔

    • @maths_505
      @maths_505  8 месяцев назад +2

      @@nicolastorres147 nah we can just split up the integral into 2 or more and apply the appropriate limits.

  • @pratyushyadav6357
    @pratyushyadav6357 7 месяцев назад +2

    ayo i subscribed brother. Love from India. Love your videos too man

    • @maths_505
      @maths_505  7 месяцев назад +4

      Love from right across the border homie

  • @快來快
    @快來快 8 месяцев назад +1

    I always love ur videos because of the dark background 😂 I use dark mode in every website and app😂😂

    • @maths_505
      @maths_505  8 месяцев назад +1

      Math on dark mode 😎

  • @satyam-isical
    @satyam-isical 8 месяцев назад +1

    Why didn't you participate in bee finals.
    I'm 110% guaranteed that you will win😅
    Btw these integrals are "fire emoji"

    • @maths_505
      @maths_505  8 месяцев назад +5

      I would've gotten atleast 2 and 4 correct within 4 minutes and that would've sealed the deal 🤣

  • @MahmoudMahmoud-wq4sl
    @MahmoudMahmoud-wq4sl 4 месяца назад

    Did you solve the first two problems with Feynman's technique?

  • @rzcaiza
    @rzcaiza 5 месяцев назад

    bit late but at 3:56 why wasn't the e^(x/2) expanded out to both, why just for (3cosx+4sinx)^(2/3)

  • @harshguruji5562
    @harshguruji5562 6 месяцев назад

    Hey | Alpha|

  • @joseph-jg2ie
    @joseph-jg2ie 6 месяцев назад

    How do I learn this wizardry? Any textbook recriminations??🙏

  • @randomcbsekid
    @randomcbsekid 3 месяца назад

    I just finished studying indefinite integration for the first time and d my friend ( also in similar situation) gave me the the first question to integrate since i saw a term of exponential in numerator i thought this integral would take the from of e^x (f(x)+f'(x)) but nothing i did made any sense...I have to say integration is pretty . Thanks for the solution !

  • @kumaraswamy3452
    @kumaraswamy3452 5 месяцев назад

    In the words of peter drury : Wonderful , Wonderful , Wonderful.......

  • @akiya9216
    @akiya9216 6 месяцев назад

    for the first integral, isnt the second half missing an e term? or is there supposed to be brackets around the whole thing

  • @Aditya_196
    @Aditya_196 5 месяцев назад

    3:39 you missed the brackets i got confused for like a minute but then realised that 😅

  • @shubhankardatta2437
    @shubhankardatta2437 7 месяцев назад +1

    At 25:42 , the value of u could have been -1 as well as it is satisfying u³-3u-2=0. You chose 2, which also satisfies the equation. Question is how do we know which one to chose?

    • @alexandreevrard9219
      @alexandreevrard9219 7 месяцев назад

      Same question here

    • @wilsonlu168
      @wilsonlu168 5 месяцев назад

      Because he lets u as the sum of two cube root which won't be negative in this situation

    • @shubhankardatta2437
      @shubhankardatta2437 5 месяцев назад

      @@wilsonlu168 why can't sum of two cube roots can't be negative?
      (-1)³+(-2)³= -9
      Though I forgot the content of the video as you can see I've made that comment a month ago.

    • @wilsonlu168
      @wilsonlu168 5 месяцев назад

      @@shubhankardatta2437 no mind
      the sum of two cube roots can be negative as you wrote
      but in this situation the integrand is non negative here
      If making the value of u negative here, ln(u) afterwards can't be performed

  • @shpark55
    @shpark55 8 месяцев назад +1

    I love it

  • @teqnify63
    @teqnify63 6 месяцев назад

    I do not have the requisite knowledge for this

  • @george-gbg
    @george-gbg 7 месяцев назад

    Where did you pick up a Swedish accent? 😀

  • @engineersspace2024
    @engineersspace2024 6 месяцев назад

    What writing board are you using for this one?

  • @KonaduKofi
    @KonaduKofi 6 месяцев назад

    What resources whould you recommend for integration

  • @nassirali1737
    @nassirali1737 4 месяца назад

    Love your content all my salutations from Morocco

  • @felipealonsoobandolopez9957
    @felipealonsoobandolopez9957 8 месяцев назад +1

    🤯🤯🤯excelente esto es lo mejor 😁

  • @jonsmith8579
    @jonsmith8579 8 месяцев назад +1

    Classic Maths 505 content

  • @esdobra
    @esdobra 7 месяцев назад

    yeah they aint doing allat in 5 min per problem

  • @Aditya_196
    @Aditya_196 5 месяцев назад

    😭 literally tells us its drastic 1:37

  • @seblara839
    @seblara839 8 месяцев назад

    Like for your first fibonacci boy of the channel!🎉

  • @murthys743
    @murthys743 7 месяцев назад

    bro , you had to mention that n is a whole number , i was solving it thinking it is to a non negative number
    anyways , great video

  • @Mathematician6124
    @Mathematician6124 5 месяцев назад +2

    Hey friend 😊. I solved all of them myself, except for the last yellow one. That required a hint

  • @kavimahajan8412
    @kavimahajan8412 8 месяцев назад +1

    How did you get so good at math

    • @maths_505
      @maths_505  8 месяцев назад +1

      I'm not exactly good just really persistent.

  • @jameyatesmauriat6116
    @jameyatesmauriat6116 7 месяцев назад

    Are these advanced integration techniques?

  • @Jalina69
    @Jalina69 5 месяцев назад

    That is impressive.

  • @kim2key
    @kim2key 8 месяцев назад

    At 25:29 you say that when x goes to 1 u goes to 2. But why not to -1 for example. The cubic equation has more than 1 solution. How do you know which one to choose?

    • @maths_505
      @maths_505  8 месяцев назад

      The integrand isn't negative on the interval of integration.

  • @nicolastorres147
    @nicolastorres147 8 месяцев назад

    What if we integrated beyond 1 where we would get a real number as a sum of conplex conjugate cube roots? 🤔

    • @maths_505
      @maths_505  8 месяцев назад

      The cube roots of complex conjugates need not be conjugates of each other so I don't that would be viable.

  • @Coronavirus-rt7fi
    @Coronavirus-rt7fi 7 месяцев назад +2

    Here is the timestamp :
    0:10 Problem 1
    6:09 Problem 2
    17:37 Problem 3
    21:47 Problem 4
    26:55 Problem 5
    Nice video.👍

  • @yoav613
    @yoav613 8 месяцев назад +1

    Wow,well done!

  • @Raspberry_aim
    @Raspberry_aim 8 месяцев назад

    41:45 maths 505 vid? Yes please!!

  • @TechToppers
    @TechToppers 8 месяцев назад

    Where can I find proofs to formulae at 19:40?

    • @maths_505
      @maths_505  8 месяцев назад +1

      On my Instagram soon

  • @sadi_supercell2132
    @sadi_supercell2132 8 месяцев назад

    Best integrator 💪💪

  • @我孫子あ
    @我孫子あ 8 месяцев назад

    I waited for this!!!

  • @thewolverine7516
    @thewolverine7516 8 месяцев назад

    My bro is on fire!!!

  • @Dedicate25
    @Dedicate25 8 месяцев назад

    bless you

  • @Daniel-yc2ur
    @Daniel-yc2ur 8 месяцев назад

    Love this

  • @NaN_000
    @NaN_000 8 месяцев назад +2

    Thank you

  • @nickosrp
    @nickosrp 8 месяцев назад

    --at the first problem: using the function with its derivative to find A and B;is it somekind of integration trick?

    • @maths_505
      @maths_505  8 месяцев назад +2

      More of an educated guess

  • @thomasolson7447
    @thomasolson7447 8 месяцев назад +1

    I'm a moron, I know it. But sometimes I wonder, with all this focus on weird integrals that don't really seem to tell a story, do these kids know numbers? How many of these kids looked at a set of normalized whole numbers from negative max to positive max and associate the sphere with R^3? How many of them know that you can color those spheres with quaternions using single input or 3 input values? How many of them know there are strong associations between algebra and trigonometry? I know this stuff and it's not because of higher education. I just explored a bit on my own. I have grade 12. And I will never go beyond that.

  • @Anonymous-Indian..2003
    @Anonymous-Indian..2003 8 месяцев назад +4

    In 2nd question,
    You made it very complex
    Just use
    Numerator: x + ln(2-e⁻ˣ)
    Denominator: eˣ - 1
    Then substitute t = e⁻ˣ
    Then integrate t=0 to 1
    Numerator: -ln(t) + ln(2 - t)
    Denominator: 1 - t
    Now replace t→1 - t
    Numerator: -ln(1 - t) + ln(1 + t)
    Denominator: t
    Now it is ς(2) + η(2)
    Simple
    Btw lots of respect from Indian CSE undergrad 😅

    • @maths_505
      @maths_505  8 месяцев назад +3

      I just couldn't resist a Feynman's trick approach 😂 your solution is excellent.

    • @Anonymous-Indian..2003
      @Anonymous-Indian..2003 8 месяцев назад +1

      ​​​@@maths_505
      Then you should use this complexity for third question, just by the use of complex analysis and contour integration.😂😂
      On residues at 72° and 144°
      e^(2iπ/5) and e^(4iπ/5)
      Then answer will be just
      (4π/5)sin(2π/5)

    • @krishnakushwah7285
      @krishnakushwah7285 6 месяцев назад

      Thankyou i was searching for it 😭