Why do you use the parallel axis theorem about point B? If you observe point B's motion, it describes a cycloid and not rotation. Then, it seems that you switched from two rotational energies to translational and rotational kinetic energy to get the right answer.
For all those poor souls in the comments . Moment of inertia is always taken about the same point *with respect* to which you have the body's angular velocity (w) and Moment of inertia is along an axis parallel to angular velocity (W) vector (it's an axial vector if you don't know )
Why point B? Because it's the instantaneous center? What about if you have a rod that's translating and rotating (about it's end and not about it's center of mass), could you use the end of the rod for I ((ml^2)/3) as point B as in your example? Or does point B have to be the IC?
hi thanks for posting the vids. I dont unerstand the step from the ex from (1) -> (2) where I is substitued for (2/5)mr^2, where does the 2/5 come from??
Wow this is literally the best video - excellent explanation
I wonder y u don't have more subscribers..... u r the best !!!!!!!!!man u r a great teacher!!!
Thank you for the knowledge. 😀
Why do you use the parallel axis theorem about point B? If you observe point B's motion, it describes a cycloid and not rotation. Then, it seems that you switched from two rotational energies to translational and rotational kinetic energy to get the right answer.
For all those poor souls in the comments . Moment of inertia is always taken about the same point *with respect* to which you have the body's angular velocity (w) and Moment of inertia is along an axis parallel to angular velocity (W) vector (it's an axial vector if you don't know )
Are u freak?
Very awesome. You are incredibly clear and informative. My physics teacher has nothing on you.
Robin Hood lol! thanks Robin! glad you found it helpful! :)
Why point B? Because it's the instantaneous center? What about if you have a rod that's translating and rotating (about it's end and not about it's center of mass), could you use the end of the rod for I ((ml^2)/3) as point B as in your example? Or does point B have to be the IC?
Why would the wheel rotate about an axis through the point B ?
Very clear explanation. But shouldn't the last eq. 5 be square root of 7gh instead of division by 0.7?
Totally understand it ✌✌✌✌
Nice sir, thank you so much.....
hi thanks for posting the vids. I dont unerstand the step from the ex from (1) -> (2) where I is substitued for (2/5)mr^2, where does the 2/5 come from??
You're welcome! Thats simply the equation for the moment of inertia of a solid sphere!
thanks!
Amazing . Thanks
What do you mean rotating about point B? I can't picture it... anyone else?
Same
Nice... I like it
Thank you
Its very nice vedio
Ky-netic energy!
;-)
Thank you sir, always been confused about rolling object K. E, now got clear
Is there difference between total kinetic energy and total translation kinetic energy
Show the formula in stencil manner
Your writing is not so good 🕉🕉🕉