Speed of a Satellite in Circular Orbit, Orbital Velocity, Period, Centripetal Force, Physics Problem

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  • Опубликовано: 3 фев 2025

Комментарии • 215

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    @jelly_boydj705 4 месяца назад

    made 7 years ago and still helps me out today👌

    • @willoughbykrenzteinburg
      @willoughbykrenzteinburg 6 дней назад

      Yeah, orbits haven't changed much in seven years, so it probably still works!

    • @jelly_boydj705
      @jelly_boydj705 6 дней назад

      @ that’s not what I ment 😂

  • @karkadeight
    @karkadeight 7 лет назад +33

    Wow that's a really fast satellite.

    • @hannalot_
      @hannalot_ 6 лет назад +8

      This is about the speed of an actual satellite

    • @studentvet3163
      @studentvet3163 4 года назад +5

      @Jebediah Jr,how?l mean what is the importance of calculating the speed of a satellite if it isn't real?

    • @studentvet3163
      @studentvet3163 4 года назад

      @@hannalot_ how?

    • @dominobuilder100
      @dominobuilder100 4 года назад +5

      Sarah Abderrahman ISS moves in almost 8km/s, so that’s even faster. And what do you mean with not real? Being able to calculate these simple things are essential to understand the fundamentals of how an object would act when put into orbit. It’s important as hell

    • @studentvet3163
      @studentvet3163 4 года назад +3

      @@dominobuilder100 oh I just thought that a satellite with that high speed hasn't been made yet I mean it is still on paper

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    @horse-kun444 3 года назад +109

    Taking physics as a freshman was the biggest mistake of my life

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    @rowannasser716 5 лет назад +3

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    @bereketmesfin6966 3 года назад

    Thanks bro I see all ur videos like chemistry math

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    @samuelinioluwa3769 3 года назад

    Thanks for the video, i've been having issues understanding this topic

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    @luckyrauniyar7359 11 месяцев назад +1

    Thnx , you are helpful for me

  • @devkaneria8669
    @devkaneria8669 5 лет назад +2

    really good explanation!!!

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    @ريتاجمحمد-د9د 5 лет назад +1

    Best channel

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    @ablene_teklie 3 года назад +1

    As it is new year in my country, my new year resolution for this year is to start studying physics. I have never studied even for the final exams.

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      @MJFinn 3 года назад

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    @josiahdahlstrom 6 лет назад +3

    Very to the point and exactly what i was looking for! Thanks so much!

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    @chiefshizac Год назад

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    @Eaterofstars09 2 года назад

    Thanks man❤️

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    Extremely helpful 👍🏻

  • @sashank6142
    @sashank6142 4 года назад

    I am in 9th grade and u made this soo easy

  • @jesusmrosario-claudio4104
    @jesusmrosario-claudio4104 4 года назад

    Thank you once again

  • @wildlandsairsoft5499
    @wildlandsairsoft5499 2 года назад

    The first part of this video helped me understand an extra credit question in my Geog605 class, remote sensing of the environment. We were asked how many times a certain satellite would orbit the earth in a day and we were only give the satellite altitude, earth's mass and radius, and the gravitational constant. The essential piece of missing info was the equation for the distance of a circular path.
    One question though, how did you translate your velocity value into m/s?

  • @ronabajraktari4556
    @ronabajraktari4556 4 года назад

    Thank you very much for this video

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    @adarshkrishansharma5796 Год назад

    Tysm bro

  • @rachelwood9373
    @rachelwood9373 6 лет назад +3

    Thank you so much for your help, this was extremely helpful to me.

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    @AHMEDALFourjani1998 7 лет назад +5

    thank u 👍

  • @rjrodrig
    @rjrodrig 2 года назад

    Fantastic

  • @maggiefan4429
    @maggiefan4429 4 года назад

    thanks, great explanation!

  • @ريتاجمحمد-د9د
    @ريتاجمحمد-د9د 5 лет назад +1

    It really helped

  • @arshaanalamkhan
    @arshaanalamkhan 4 года назад

    So there is finally physics in chemistry

  • @henywetherford901
    @henywetherford901 5 лет назад +2

    so helpful, thanks!!!

  • @chitundujames5479
    @chitundujames5479 2 года назад

    To me nice lesson sir

  • @articcircleado
    @articcircleado 4 года назад

    Bless your soul

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    @pradyotranjan5462 3 года назад +4

    Redirected here from a link in my book

  • @Noahmalacad
    @Noahmalacad 3 года назад

    thanks bro

  • @1more1more34
    @1more1more34 5 лет назад

    Thanks man

  • @ChrisGidee
    @ChrisGidee 7 месяцев назад

    This wonderful

  • @bedirhanyerlitas8529
    @bedirhanyerlitas8529 2 года назад

    thank you so much hocam

  • @ekoi1995
    @ekoi1995 3 года назад

    5:07 is the speed of the satellite angular velocity?

  • @jeanneerinestrella4739
    @jeanneerinestrella4739 Год назад

    when do we use m/s and km/s when solving for velocity?

  • @ali-rp9qy
    @ali-rp9qy 3 года назад

    tq sir

  • @alexdcn
    @alexdcn 3 года назад

    is this related in calculating quantities related to planetary or satellite motion?

  • @jasondean88888
    @jasondean88888 3 года назад

    42,200,000 x 2pi / 86,400 = 3068
    Seems a good deal easier for the last answer and we'll within reason given rounding. If we had more sigfigs for R it would be just as accurate.

  • @ilovesunny8887
    @ilovesunny8887 7 лет назад +5

    Wich drawing program are u using?

  • @iasmamd
    @iasmamd 5 лет назад

    Thank u so much you are amazing ❤❤❤

  • @hannakennedy3720
    @hannakennedy3720 6 лет назад

    amazing video, thank you!

  • @nomanqureshi653
    @nomanqureshi653 3 года назад

    Sir, how you can cancel both R, In centripetal Force R is the radius of circle(i think it should be the distance between Surface of Earth and Satellite) and in Gravitational Force R is the separation between two masses (from center of Earth to the Satellite). Could you Please Explain

  • @thidaswinathsara6164
    @thidaswinathsara6164 4 года назад +1

    What will happen if new mass added to the satellite while moving? affect of the linear momentum? and how it maintain the speed constant?

    • @jo-oy4vj
      @jo-oy4vj 4 года назад

      if you add new mass the same way rockets dock to ISS, then it won't affect anything because the new mass already achieve equal speed to the satellite

    • @thidaswinathsara6164
      @thidaswinathsara6164 4 года назад

      @@jo-oy4vj ok, thanks

  • @brightchirindo5393
    @brightchirindo5393 6 лет назад +12

    thanks for the lecture it was inspiring. God bless you in jesus name

  • @sundaramkalyan2411
    @sundaramkalyan2411 5 лет назад

    while on a circular orbit if the velocity of the object is increased then it will go further away but a new balance can be achieved only if distance decrease. (Higher velocity means higher centrifugal force and it can be balanced only by a higher gravitational force which will happen only if distance decrease) in reality an elliptical orbit is created. how do you explain this by the above simple physics?

  • @shreenidhhi8633
    @shreenidhhi8633 5 лет назад +1

    What calculator are you using bro???

  • @ريتاجمحمد-د9د
    @ريتاجمحمد-د9د 5 лет назад

    Thankkks

  • @pradeepboyane3800
    @pradeepboyane3800 6 лет назад

    Bro! You rock!

  • @sivakotireddykavya5345
    @sivakotireddykavya5345 4 года назад

    Sir,for explaining which app u have used?

  • @tycobb7679
    @tycobb7679 5 лет назад +1

    Where did you get the 6254.3 m/s from. What did you do to get it.

    • @TheJoey3590
      @TheJoey3590 5 лет назад

      He used the equation: v=square root (GM/r). This will give you the speed of the satellite which is in circular orbit. If it was in an elliptical orbit, you'd have to use a different equation.

    • @cristhianv.5649
      @cristhianv.5649 3 года назад

      It is probably too late now, but what he did was double parenthesis like this: ((6.67 X 10 ^ -11)(5.97 X 10^24) divided by 1.018 X 10^7))

  • @pizehshirley5792
    @pizehshirley5792 6 лет назад

    thank you....

  • @ashrielburnett1203
    @ashrielburnett1203 6 лет назад +2

    I'm not getting the calculation for r even though I put in all the values u have in for the cube root thingy

    • @nsifrahman9031
      @nsifrahman9031 5 лет назад +1

      Why are you so girly?
      It's thing and not thingy 😂

    • @ianfjay6883
      @ianfjay6883 5 лет назад +2

      @@nsifrahman9031 lol how is thingy girly?

    • @homeofsports3295
      @homeofsports3295 3 года назад

      I think he made a mistake in the calculations, I wasn't able to find the same answer as him for the radius between the center of the earth to the satellite.

  • @CoalChrome
    @CoalChrome 4 года назад +1

    could you maybe explain what the variables mean

  • @samarjitdeshmukh4845
    @samarjitdeshmukh4845 4 года назад

    Isn't v the tangential velocity? So shouldn't T = 2pir/v/r since v/r = w which is the rotational velocity?

  • @tayyabashahzadi9314
    @tayyabashahzadi9314 6 лет назад

    can u plz explain the variation of centripetal accl. and velocity of planets at different distances from sun?

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  • @Dyanxiu
    @Dyanxiu Год назад

    Im an average student and nim thankful for this but kinda lost in number 2(b) 😭

  • @Yos7a76
    @Yos7a76 3 года назад

    Can you do ESCAPE VELOCITY OF A SATELLITE

  • @garbage6577
    @garbage6577 Год назад

    Believe it or not, I'm having to perform many calculations for a singular mission that I'm planning in Kerbal Space Program

  • @jcutey
    @jcutey 6 лет назад

    At 12:13 shouldn't the value of R^2 be cancelled by R and the remaining value should be R?

    • @alexshaw714
      @alexshaw714 6 лет назад +1

      When you have a/b = c/d, you multiply 'a/b' by d (to get rid of the 'd' on the bottom of the right hand side, and multiply the remaining c by b to get rid of the denominator on the left hand side, leaving 'ad = bc'.
      If it was a/b * c/d, then you're right, the R would cancel the R^2.

    • @haloless2092
      @haloless2092 5 лет назад

      Are u dumb?

  • @stevesaam1924
    @stevesaam1924 5 лет назад +3

    Isn't it v=√(2GM/R) ? First example speed of satellite

    • @DeletionRoad
      @DeletionRoad 5 лет назад +3

      pretty sure thats the escape velocity my guy

  • @IbrahimKhandker
    @IbrahimKhandker 6 лет назад +1

    Super like

  • @ramasai7125
    @ramasai7125 6 лет назад

    please clarify me it's angular speed is equal to that of earth about its own axis

  • @BenBezuidenhout
    @BenBezuidenhout 3 года назад

    so satelies move at 11059.2km/h? constantly around earth?

  • @stalin9122
    @stalin9122 6 дней назад

    Got jee tomorrow wish me luck boys

  • @macaoa
    @macaoa Год назад

    I keep getting 6.2543E10 for the speed on my calculator. I was wondering what am I doing wrong? I did convert the km into m by multiply it by 1000 and got the same radius in the video. I plugged the exact number in also.

  • @larrymason5120
    @larrymason5120 6 лет назад +5

    This dude 100% got rid of his speech impediment! How tf do you do that?

  • @bearosellegamboa8668
    @bearosellegamboa8668 4 года назад

    Is the 6.38x10^6 constant?

    • @homeofsports3295
      @homeofsports3295 3 года назад +2

      As far as I'm aware the radius of the earth doesn't change, so 6.38x10^6 meters or 6371 kilometers should be a constant.
      edit : "The scientists estimated the average change in Earth's radius to be 0.004 inches (0.1 millimeters) per year, or about the thickness of a human hair, a rate considered statistically insignificant." *Source : NASA* (www.nasa.gov/topics/earth/features/earth20110816.html#:~:text=The%20scientists%20estimated%20the%20average,a%20rate%20considered%20statistically%20insignificant.)
      edit 2 : at this rate of 0.1 milimeters per year, it would take 10 milions year just for the radius to go up by 1 kilometer, so I would say 6.38x10^6 meters or 6371 kilometers is good enough

  • @XxPlayMakerxX131
    @XxPlayMakerxX131 6 лет назад

    What is the work of the Earth on the satellite and why is it equal to zero?

    • @potatoeater2629
      @potatoeater2629 6 лет назад

      XxPlayMakerxX131 i dont fucking know but these are so fucking hard fr

    • @Fleischgewehr
      @Fleischgewehr 6 лет назад

      Forces only do work if they have some vector component along the path of motion. This path of motion is the circular orbit, the force is the centripetal force directed towards the center of the Earth. These are perpendicular, so gravity does no work. It's a similar story for charged particles moving in a mass spectrometer, if you've seen that.

    • @rye-bread5236
      @rye-bread5236 6 лет назад

      if the earth is inside the system it cannot do work. hence 0. If it is outside the system like external forces. it does work.
      my prof has us set it up like so
      work= change in energy
      work= PE + KE ...
      on the left is external forces that create work (b0th pos. and neg. work has to be parallel though. Work that is perpendicular is 0. Torque is when there are perpendicular force and distance )
      on the right is internal energies, Gravitational potential and kinetic. If 0 work that means the internal forces are equal and opposite (for this scenario)
      Hope this helps.

  • @ahmedehab8766
    @ahmedehab8766 5 лет назад

    Gold