@@cintyameiladewi3513 We decided to eliminate the Y variable, right? The coefficient of the Y variable in the first equation is 8 and in the second equation is 6. The least common multiple of 8 and 6 is 24 (3 x 8 = 24 and 4 x 6 = 24). Therefore, we can make the coefficients of Y opposites by multiplying the first equation by 3 and the second equation by -4, or by multiplying the first equation by -3 and the second equation by 4. In both cases, the coefficients of Y become opposites, and when adding the two equations, the Y variable is eliminated. Please let me know if you need further clarification.
Wow, this video was a game-changer for me! The way you explained made it crystal clear and easy to understand. Your step-by-step approach, starting from simple examples and gradually increasing the complexity, was incredibly helpful. I learned so much from each example, and by the end of the video, I felt like I had a solid understanding. It's obvious that you put a lot of effort into creating this tutorial, and it's greatly appreciated. I now feel much more confident in my ability to tackle these equations. Thank you and keep up the excellent work!
this is what I need it. there are some good in teaching but you are the one that step by step open path into my head, I'm understanding and learning so well and clear with you.
To eliminate the Y variable, we look at the coefficients of Y in both equations. In the first equation, the coefficient is 8, and in the second, it’s 6. To cancel out the Y’s when we add the equations, we need their coefficients to be opposites. The least common multiple of 8 and 6 is 24 (since 3 x 8 = 24 and 4 x 6 = 24). So, we multiply the first equation by 3, turning the 8 in front of Y into 24, and multiply the second equation by -4, turning the 6 in front of Y into -24. Now, when we add the two equations, the Y-terms cancel out because their coefficients are opposites: 24Y + (−24Y) = 0. By the way, you could also multiply the first equation by -3 and the second by 4. This would also make the coefficients of Y opposites, so the Y variable is eliminated when the two equations are added. Please let me know if you need further clarification. I’m happy to help!
Q: Why do I need to multiply the 2nd equation by -3? A: We want to eliminate the Y variable. In the first equation, the coefficient of Y is 3, and in the second equation, it’s 1. To cancel out the Y's when we add the two equations, their coefficients must be opposites. So, we multiply the second equation by -3, turning the 1 in front of the Y into a -3. Now, when we add the equations, the Y-terms cancel out because 3Y + (−3Y) = 0. Q:And how did you get -3? A: To decide the number to multiply by, we find the least common multiple (LCM) of the two coefficients. The LCM of 3 and 1 is 3. But to eliminate the Y-terms, we want their coefficients to be opposites. Since the first equation already has a 3, we need the second equation to have -3. So, we multiply the second equation by -3 to make the coefficients opposites. Let me know if you need further clarification.
7:00 why did you choose second equation instead first equation? 9:28 why did you choose second equation instead first equation again? I still cant understand
Why did you choose the second equation instead of the first equation? It is because the coefficients in the second equation are smaller numbers compared to those in the first equation. It is easier and faster to work with smaller numbers. However, you can also use the first equation and you will get the same answer. Why did you choose the second equation instead of the first equation again? It is because Y is already isolated in the second equation, so you can find it with fewer steps and save time. If you use the first equation, you will get the same answer but it will take more time as you need to do more steps.
We decided to eliminate the Y variable, right? The coefficient of the Y variable in the first equation is 8 and in the second equation is 6. The least common multiple of 8 and 6 is 24 (3 x 8 = 24 and 4 x 6 = 24). Therefore, we can make the coefficients of Y opposites by multiplying the first equation by 3 and the second equation by -4, or by multiplying the first equation by -3 and the second equation by 4. In both cases, the coefficients of Y become opposites, and when adding the two equations, the Y variable is eliminated. Please let me know if you need further clarification.
To eliminate the Y variable, we look at the coefficients of Y in both equations. In the first equation, the coefficient is 8, and in the second, it’s 6. To cancel out the Y’s when we add the equations, we need their coefficients to be opposites. The least common multiple of 8 and 6 is 24 (since 3 x 8 = 24 and 4 x 6 = 24). So, we multiply the first equation by 3, turning the 8 in front of Y into 24, and multiply the second equation by -4, turning the 6 in front of Y into -24. Now, when we add the two equations, the Y-terms cancel out because their coefficients are opposites: 24Y + (−24Y) = 0. By the way, you could also multiply the first equation by -3 and the second by 4. This would also make the coefficients of Y opposites, so the Y variable is eliminated when the two equations are added. Please let me know if you need further clarification. I’m happy to help!
Graphing method 👉 ruclips.net/video/SoVUECpWkKc/видео.html
Substitution method 👉 ruclips.net/video/8ZzFBp3FPEg/видео.html
I want to ask, why is C multiplied by negative 4?
@@cintyameiladewi3513
We decided to eliminate the Y variable, right? The coefficient of the Y variable in the first equation is 8 and in the second equation is 6. The least common multiple of 8 and 6 is 24 (3 x 8 = 24 and 4 x 6 = 24). Therefore, we can make the coefficients of Y opposites by multiplying the first equation by 3 and the second equation by -4, or by multiplying the first equation by -3 and the second equation by 4. In both cases, the coefficients of Y become opposites, and when adding the two equations, the Y variable is eliminated. Please let me know if you need further clarification.
Wow, this video was a game-changer for me! The way you explained made it crystal clear and easy to understand. Your step-by-step approach, starting from simple examples and gradually increasing the complexity, was incredibly helpful. I learned so much from each example, and by the end of the video, I felt like I had a solid understanding. It's obvious that you put a lot of effort into creating this tutorial, and it's greatly appreciated. I now feel much more confident in my ability to tackle these equations. Thank you and keep up the excellent work!
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this is what I need it. there are some good in teaching but you are the one that step by step open path into my head, I'm understanding and learning so well and clear with you.
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Thank you so much!!! Last month i was getting Cs and even Fs in math and i just got an A in my test
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Where di you get 3 and -4 on 5:52 ?
To eliminate the Y variable, we look at the coefficients of Y in both equations. In the first equation, the coefficient is 8, and in the second, it’s 6. To cancel out the Y’s when we add the equations, we need their coefficients to be opposites. The least common multiple of 8 and 6 is 24 (since 3 x 8 = 24 and 4 x 6 = 24). So, we multiply the first equation by 3, turning the 8 in front of Y into 24, and multiply the second equation by -4, turning the 6 in front of Y into -24. Now, when we add the two equations, the Y-terms cancel out because their coefficients are opposites: 24Y + (−24Y) = 0.
By the way, you could also multiply the first equation by -3 and the second by 4. This would also make the coefficients of Y opposites, so the Y variable is eliminated when the two equations are added.
Please let me know if you need further clarification. I’m happy to help!
My man
I have a question how you bring 3 and 4 number c
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On D Why do I need to multiply the 2nd equation by -3? And how did you get -3
Q: Why do I need to multiply the 2nd equation by -3?
A: We want to eliminate the Y variable. In the first equation, the coefficient of Y is 3, and in the second equation, it’s 1. To cancel out the Y's when we add the two equations, their coefficients must be opposites. So, we multiply the second equation by -3, turning the 1 in front of the Y into a -3. Now, when we add the equations, the Y-terms cancel out because 3Y + (−3Y) = 0.
Q:And how did you get -3?
A: To decide the number to multiply by, we find the least common multiple (LCM) of the two coefficients. The LCM of 3 and 1 is 3. But to eliminate the Y-terms, we want their coefficients to be opposites. Since the first equation already has a 3, we need the second equation to have -3. So, we multiply the second equation by -3 to make the coefficients opposites.
Let me know if you need further clarification.
@@gotutormaths Thank You so much this helped
W tutor ❤
Where did u get the - 1
Is it possible to solve problem D with the substitution method?
Yes it is possible. Please check out problem B in the substitution method video ruclips.net/video/8ZzFBp3FPEg/видео.html
what do you use to create tutorials kindly help me
7:00 why did you choose second equation instead first equation?
9:28 why did you choose second equation instead first equation again? I still cant understand
Why did you choose the second equation instead of the first equation?
It is because the coefficients in the second equation are smaller numbers compared to those in the first equation. It is easier and faster to work with smaller numbers. However, you can also use the first equation and you will get the same answer.
Why did you choose the second equation instead of the first equation again?
It is because Y is already isolated in the second equation, so you can find it with fewer steps and save time. If you use the first equation, you will get the same answer but it will take more time as you need to do more steps.
Nice
Great video. Im a little slow. Can you explain c a little more for me?
How come you multiple by 3 and -4?
I am sorry
We decided to eliminate the Y variable, right? The coefficient of the Y variable in the first equation is 8 and in the second equation is 6. The least common multiple of 8 and 6 is 24 (3 x 8 = 24 and 4 x 6 = 24). Therefore, we can make the coefficients of Y opposites by multiplying the first equation by 3 and the second equation by -4, or by multiplying the first equation by -3 and the second equation by 4. In both cases, the coefficients of Y become opposites, and when adding the two equations, the Y variable is eliminated. Please let me know if you need further clarification.
@@gotutormathswhy is 4 negative though?
@@sssssunyyI think it's because 6y is down, so 4 becomes -4
@@sssssunyy To make them opposite so that when you add them the Y-terms cancel out.
good
I got stuck at when we use the form Ax+By=C or
Y-Y1=m(x-x1) to write a standard form for equation .
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Please stdiues Graph of the Relation andpolynomial functions in todey
On question c, where did you find the 3 and 4 which you multiplied with the equation
To eliminate the Y variable, we look at the coefficients of Y in both equations. In the first equation, the coefficient is 8, and in the second, it’s 6. To cancel out the Y’s when we add the equations, we need their coefficients to be opposites. The least common multiple of 8 and 6 is 24 (since 3 x 8 = 24 and 4 x 6 = 24). So, we multiply the first equation by 3, turning the 8 in front of Y into 24, and multiply the second equation by -4, turning the 6 in front of Y into -24. Now, when we add the two equations, the Y-terms cancel out because their coefficients are opposites: 24Y + (−24Y) = 0.
By the way, you could also multiply the first equation by -3 and the second by 4. This would also make the coefficients of Y opposites, so the Y variable is eliminated when the two equations are added.
Please let me know if you need further clarification. I’m happy to help!
What if the y3y was only y
Only 3y sorry typo
Very nayis
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Y= x/3 -3
The answer in question d is no surely correct
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